1. Airam Salinas & Fatima Gonzalez December 18, 2013 7-8 A

2. A cruise ship has 680 rooms. Those with a view rent for $160 per night and those without a view rent for $105 per night. On a night when the ship was completely occupied, revenues were $92,500. How many of each type of room are on the ship? PROBLEM SITUATION

3. The variables in these equation are A which represents the number of rooms with a view, which costs $160 per night, and F which represents the number of rooms without a view, which costs $105 per night. DEFINE VARIABLES

4. Our system of equations are ∆ 92,500 = 160A + 105F ∆ A + F = 680 SYSTEM OF EQUATIONS

5. First you need to rewrite one of the equations: A + F = 680 Solve for F: F = 680 - A Now substitute into the other equation. 92500 = 160A + 105(680-A) 92500 = 160A + 71400 - 105A 92500 = 55A + 71400 -71400 -71400 21100 = 55A 21100/55 = A To solve this equation you will have to use substitution. SOLUTION METHOD A=383.64 F=296.36

6. (A, F) (383.64, 296.36) SOLUTION TO THE SYSTEM OF EQUATIONS

7. ∆92,500 = 160(383.64) + 105(296.36) True ∆ 383.64 + 296.36 = 680 True CHECK OF SOLUTION

8. The number of rooms has to be a whole number in order to make sense in this problem situation. 383.64 is the number of rooms with a view. 296.36 is the number of rooms without a view. SOLUTION IN THE PROBLEM SITUATION