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$100 $200 $300 $400 $500 $200 $300 $400 $500 Problem Solving Multi-Step Equations Simple and Compound Interest Multi-Step Inequalities Transforming.

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Presentation on theme: "$100 $200 $300 $400 $500 $200 $300 $400 $500 Problem Solving Multi-Step Equations Simple and Compound Interest Multi-Step Inequalities Transforming."— Presentation transcript:

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3 $100 $200 $300 $400 $500 $200 $300 $400 $500 Problem Solving Multi-Step Equations Simple and Compound Interest Multi-Step Inequalities Transforming Formulas

4 Problem Solving for $100 Find 4 consecutive even integers whose sum is 228

5 Let x be the smallest of the numbers. Then, the other numbers will be x+2, x+4 and x+6 x + (x+2) + (x+4) + (x+6) = 228 4x + 12 = 228 4x = 216 x = 54. So the other numbers are 56, 58 and 60 Answer Back

6 Problem Solving for $200 An item is on sale for 30% off the original price. The final sale price is $42.65. What was the original price?

7 Answer Back Let x = the original price of the item. Then: x - 0.3x = $42.65 0.7x = $42.65 x = $60.93

8 Problem Solving for $300 Andy puts a certain amount of money into a bank account. When he withdrew the money from the account he had $558.45. If this is 9.5% more than he started with, how much money did he deposit into the account?

9 Answer Back Let x = the amount of money he started with. Then: x + 0.095x = $558.45 1.095x = $558.45 x = $510

10 Problem Solving for $400 If the perimeter of a rectangle is 64cm and the length is 10cm less than twice the width. What is the length and width of the rectangle?

11 P = 2(L+w) let x = the width. Then: 2x – 10 = L so, 64 = 2(2x – 10 + x) 32 = (2x + x – 10) 32 = 3x – 10 42 = 3x 14 = x so, the width = 14 and the length = 2(14) -10 = 28-10 = 18cm Answer Back

12 Problem Solving for $500 The cost of renting a car is $50 per day plus 15 cents per mile driven. If Amy rented the car for three days and paid a total of $217.50, how many miles did she drive?

13 Answer Back Let x = the # of miles driven. Then, $217.50 = 50(3) + 0.15x 217.50 = 150 +.15x 67.50 =.15x x = 450 miles

14 Multi-Step Equations for $100 Solve for x: 3x = x/3

15 Answer 3x = x/3 9x = x 8x = 0 x = 0 Back

16 Multi-Step Equations for $200 Solve for C: 7 + 2(3 + C) = 2(3 + 7) + C

17 Answer 7 + 2(3 + C) = 2(3 + 7) + C 7 + 6 + 2C = 6 + 14 + C 13 + 2C = 20 + C 2C = 7 + C C = 7 Back

18 Multi-Step Equations for $300 Solve for d: 7.25d + 2d – 5d – 2 = 4d + 3

19 Answer 7.25d + 2d – 5d – 2 = 4d + 3 4.25d – 2 = 4d + 3 0.25d – 2 = 3 0.25d = 5 d = 20 Back

20 Multi-Step Equations for $400 Solve for n. (1/3)(n + 9) – 5 = 7

21 Answer Back (1/3)(n + 9) – 5 = 7 (1/3)(n + 9) = 12 n+9 = 36 n = 27

22 Multi-Step Equations for $500 Solve for p. 4p – 4 = 2(p+3) – 6(9-p)

23 Answer Back 4p – 4 = 2(p+3) – 6(9-p) 4p – 4 = 2p + 6 – 54 + 6p 4p – 4 = 2p + 6p + 6 – 54 4p – 4 = 8p – 48 -4 = 4p – 48 44 = 4p p = 11

24 Multi-Step Inequalities for $100 Solve for x: x/(3) + 3 > 5

25 Answer x/(3) + 3 > 5 x/(3) + 3 - 3 > 5 - 3 x/(3) > 2 x/(3) * 3 > 2 * 3 X > 6 Back

26 Multi-Step Inequalities for $200 Solve for x: -5x + 20 ≤ 10

27 Answer -5x + 20 ≤ 10 -20 -20 -5x ≤ -10 (-5x)/(-5)≤ (-10)/(-5) X ≥ 2 Back

28 Multi-Step Inequalities for $300 Replace the with a number that makes the inequalities equivalent -3x > x < -9

29 Answer -3x > (-3x)/(-3) > / (-3) x < /(-3) and x < -9 So, /(-3) = -9 /(-3) * -3 = -9 * -3 = 27 Back

30 Multi-Step Inequalities for $400 Solve for x: -(x-6) + 5 - 2x < 8

31 Answer -(x-6) + 5 - 2x < 8 -(x-6) + 5 - 5 - 2x < 8 – 5 -(x-6) - 2x < 3 -x + 6 – 2x < 3 -3x + 6 < 3 -3x + 6 – 6 < 3 – 6 -3x < -3 (-3x)/(-3) < (-3)/(-3) X > 1 Back

32 Multi-Step Inequalities for $500 Solve for x. 10x – 5 - 3x > 3 – (5 - x)

33 Answer 10x – 5 - 3x > 3 – (5 - x) 7x – 5 > 3 – 5 + x 7x – 5 > -2 + x 7x > 3 + x 6x > 3 x > 0.5 Back Check 1: (Substitute it in –> Should be equal) 10(0.5) – 5 – 3(0.5) = 3 – (5 – (0.5)) 5 - 5 – 1.5 = 3 - 4.5 -1.5 = -1.5 Check 2: (Pick value that is true) Let x = 1 10(1) – 5 – 3(1) > 3 – (5 – (1)) 10 - 5 – 3 > 3 - 4 2 > -1 => True Check 3: (Pick value that is false) Let x = 0 10(0) – 5 – 3(0) = 3 – (5 – (0)) -5 > 3 - 5 -5 > -2 => FALSE

34 Transforming Formulas for $100 Solve for x: y = -2x + 5

35 Answer y = -2x + 5 y - 5 = -2x y-5 = x -2 Back

36 Transforming Formulas for $200 Solve for m: n = 4p + 5m

37 Answer n = 4p + 5m n – 4p = 5m n – 4p = m 5 Back

38 Transforming Formulas for $300 Solve for p: 2t = s/4 – 8p

39 Answer 2t = s/4 – 8p 2t – s/4 = -8p -t + s = p 4 32 Back

40 Transforming Formulas for $400 Solve for y: 7y – 3x = 2m 4 2

41 Answer 7y – 3x = 2m 4 2 7y – 6x = 8m 7y = 8m + 6x y = 8m + 6x 7 Back

42 Transforming Formulas for $500 Solve for c: C – 3m + 5 = 2n 2

43 Answer C – 3m + 5 = 2n 2 C – 3m = 2n - 5 2 C – 3m = 2(2n – 5) C – 3m = 4n – 10 C = 4n + 3m – 10 Back

44 Simple and Compound Interest for $100 Write the formula for simple interest.

45 Answer I = prt I: Interest p: Principal r: Rate t: Time Back

46 Simple and Compound Interest for $200 Write the formula for compound interest:

47 Answer B = p(1+r) n B: Balance p: Principal r: Rate n: Number of times interest is compounded Back

48 Simple and Compound Interest for $300 If Jane put $800 into a bank account which pays 3.25% simple interest annually for 4 years, how much money did she have at the end?

49 Answer I = prt I = 800 * 0.0325 * 4 I = 104 Total = p +I = 800 + 104 = $904 Back

50 Simple and Compound Interest for $400 Find the balance if $675 is deposited in an account which pays 3.75% interest compounded annually for 4 years.

51 Answer B = p(1+r)n Compounded Annually: p = $675 r = 3.75% n = 4 years B = 675(1 +.0375) 4 B = $782.09 Back

52 Simple and Compound Interest for $500 Find the balance if $29,200 is deposited in an account which pays 2.4% interest compounded quarterly for 3 years.

53 Answer Back B = p(1+r) n Compounded Quarterly: p = $29,200 r = 2.4% =.024/4 (quarterly) =.006 n = 3 years * 4 = 12 times B = 29,200(1 +.006) 12 B = $31,373.19


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