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L8 Optimal Design concepts pt D
Homework Review Inequality constraints General LaGrange Function Necessary Conditions for general Lagrange Multiplier Method Example Summary
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MV Optimization- E. CONSTRAINED
For x* to be a local minimum:
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LaGrange Function If we let x* be the minimum f(x*) in the feasible region: All x* satisfy the equality constraints (i.e. hj =0) Note: when x is not feasible, hj is not equal to 0 and by minimizing hj we are pushing x towards feasibility!
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Necessary Condition Necessary condition for a stationary point
Given f(x), one equality constraint, and n=2
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Example
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Example cont’d
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Lagrange Multiplier Method
1. Both f(x) and all hj(x) are differentiable 2. x* must be a regular point: 2.1 x* is feasible 2.2 Gradient vectors of hj(x) are linearly independent 3. LaGrange multipliers can be +, - or 0.
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MV Optimization Inequality Constrained
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To Use LaGrange Approach Convert Inequalities to Equalties?
Given an inequality Add a variable sj to take up the slack No longer an inequality Can now use Lagrange Multiplier Approach
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MV Optimization Active or Inactive Inequalities?
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KKT Necessary Conditions for Min
1. Lagrange Function (in standard form) 2. Gradient Conditions
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KKT Conditions Cont’d 3. Feasibility Check for Inequalities
4. Switching Conditions, e.g. 5. Non-negative LaGrange Multipliers for inequalities 6. Regularity check gradients of active inequality constraints are linearly independent
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KKT Necessary Conditions for Min
Regularity check - gradients of active inequality constraints are linearly independent
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Ex 4.32 pg 150
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LaGrange Function
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4 equations and 4 unknowns
Non-linear system of equations
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Use Switching Conditions to Simplify
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Case 1 Non-linear system of equations Both inequalities are VIOLATED
Therefore, x is INFEASIBLE
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Case 2 System of 3 linear equations in 3 unknowns Rewrite
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Gaussian Elimination
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Gaussian Elimination cont’d
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Ex 4.32 cont’d Check last eqn (for s1 feasiblity)
Nope! The point is not feasible.
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Case 4 We can use Gaussian elimination again Where are cases 1-4?
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Check if regular point Rank= order of largest non-singular matrix in A
since det (A) is non-singular, the A matrix is full rank We can also see that the vectors are not parallel in figure.
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All Equations must be satisfied
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Summary General LaGrange Function L(x,v,u,s)
Necessary Conditions for Min Use switching conditions Check results
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