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2.2 Geometrical Application of Calculus
Types of Stationary Points 1. Minimum - + - + - + - + - + - - + + x LHS Minimum RHS f’(x) < 0 = 0 > 0
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2.2 Geometrical Application of Calculus
Types of Stationary Points 2. Maximum - + - + - + - - + - + x LHS Maximum RHS f’(x) > 0 = 0 < 0
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2.2 Geometrical Application of Calculus
Types of Stationary Points - + 3.Point of Horizontal Inflection - + - + - - + - + - + - - + - + - x LHS Inflection RHS f’(x) > 0 < 0
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2.2 Geometrical Application of Calculus
Types of Stationary Points Find any stationary points on the curve f(x) = x2 - 2x & determine what type it is. f’(x) = 2x - 2 f(1) = (1)2 – 2(1) = -1 2x - 2 = 0 (Stationary) (1, -1) 2x = 2 f’(0) = 2(0) - 2 = -2 x = 1 f’(2) = 2(2) - 2 = +2 LHS x = 0 Stationary x = 1 RHS x = 2 - + (1, -1) is a Minimum
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(0, 2) is a horizontal point of inflection
2.2 Geometrical Application of Calculus Types of Stationary Points 2. Find the turning point on the curve y = 2x3 + 2 and determine what type it is. f(x) = 2x3 + 2 f(0) = 2(0)3 + 2 = 2 f’(x) = 6x2 (0, 2) f’(-1) = 6(-1)2 = +6 6x2 = 0 (Stationary) x = 0 f’(1) = 6(1)2 = +6 LHS x = -1 Stationary x = 0 RHS x = 1 + (0, 2) is a horizontal point of inflection
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