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Published byJunior Tucker Modified over 9 years ago
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REDOX REACTIONS Oi L Oxidation is L osing electrons (becomes more positive) Ri G Reduction is G aining electrons (becomes less positive) Cu(s) + 2AgNO 3 (aq) Cu(NO 3 ) 2 (aq) + 2Ag(s) Put in charges and look at changes 02+ more positive ( L ost e - s) Cu is oxidized from 0 to 2+ 1+ 0 Less positive ( G ained e - s) Ag 1+ is reduced from 1+ to 0 Cu is the reducing agent and AgNO 3 is the oxidizing agent
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MgC 2 O 4 H 2 SO 4 H 2 SO 3 Cr 2 O 7 2- Assign oxidation numbers for each element below Co(NO 3 ) 2
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MgC 2 O 4 H 2 SO 4 H 2 SO 3 Cr 2 O 7 2- Assign oxidation numbers for each element below Co(NO 3 ) 2 x = +3 (the assigned charge for carbon in this compound) x = +6 (the assigned charge for sulfur in this compound) x = +4 (the assigned charge for sulfur in this compound) x = +6 (the assigned charge for chromium in this compound) x = +5 (the assigned charge for nitrogen in this compound)
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2 MnO (s) + 5 PbO 2 (s) + 10 HNO 3 (aq) → 2 HMnO 4 (aq) + 5 Pb(NO 3 ) 2 (aq) + 4 H 2 O (l) ______ is oxidized from a ______ charge to a ________ charge. _______ is reduced from a ______ charge to a ________ charge. _______ ____ is the reducing agent. ____________ is the oxidizing agent.
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2 MnO (s) + 5 PbO 2 (s) + 10 HNO 3 (aq) → 2 HMnO 4 (aq) + 5 Pb(NO 3 ) 2 (aq) + 4 H 2 O (l) ______ is oxidized from a ______ charge to a ________ charge. (OiL) _______ is reduced from a ______ charge to a ________ charge. (RiG) ____________ is the reducing agent. ____________ is the oxidizing agent. +2+7 More positive (Lost electrons) OiL Mn 2+ +2+7 +4+2 Less positive (Gains electrons) RiG Pb 4+ +4 +2 MnO PbO 2
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Fe (s) + FeCl 3 (aq) → FeCl 2 (aq) ______ is oxidized from a ______ charge to a ________ charge. _______ is reduced from a ______ charge to a ________ charge ____________ is the reducing agent. ____________ is the oxidizing agent.
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Fe (s) + FeCl 3 (aq) → FeCl 2 (aq) ______ is oxidized from a ______ charge to a ________ charge. (OiL) _______ is reduced from a ______ charge to a ________ charge. (RiG) _______ ____ is the reducing agent. ____________ is the oxidizing agent. 0+3+2 Fe 0+2 Fe 3+ +3+2 Fe FeCl 3
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Cu (s) + 4 HNO 3 (aq) → 2 NO 2 (g) + 2 H 2 O (l) + Cu(NO 3 ) 2 (aq) ______ is oxidized from a ______ charge to a ________ charge. (OiL) _______ is reduced from a ______ charge to a ________ charge. (RiG) ____________ is the reducing agent. ____________ is the oxidizing agent. 0 +2 Cu0+2 +5 +4 N +5 +5+4 Cu HNO 3
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