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Published byMarybeth Gibson Modified over 9 years ago
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EXPANDING AND CONDENSING LOGARITHMS
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PROPERTIES OF LOGARITHMS Product Property: Quotient Property: Power Property: PROPERTIES OF LOGARITHMS
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Product Property: PROPERTIES OF LOGARITHMS
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= log a M + log a N EX. EXPRESS AS A SUM OF LOGARITHMS. 1) log a MN = log b A + log b T 2) log b AT = log M + log A + log T + log H 3) log MATH
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= log 5 (193) EX. EXPRESS AS A SINGLE LOGARITHM 4) log 5 19 + log 5 3 5) log C + log A + log B + log I + log N = log CABIN
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ON YOUR OWN Expanding the Logarithm (Write as a sum of logarithms):
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ON YOUR OWN Expanding the Logarithm (Write as a sum of logarithms):
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EX. EXPRESS AS A SUM OF LOGARITHMS, THEN SIMPLIFY. 6) log 2 (416) = log 2 4 + log 2 16 = 6 = 2 + 4
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EX. 7 USE LOG 5 3 = 0.683 AND LOG 5 7 = 1.209 TO APPROXIMATE… log 5 (21) = log 5 3 + log 5 7 = 0.683 + 1.209 = 1.892 = log 5 (3 7)
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PROPERTIES OF LOGARITHMS Quotient Property PROPERTIES OF LOGARITHMS
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EX. EXPAND (EXPRESS AS A DIFFERENCE) 8) 9)
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ON YOUR OWN Expanding the Logarithm (Write as a difference of logs):
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ON YOUR OWN Expanding the Logarithm (Write as a difference of logs):
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EX. 10 USE LOG 5 3 = 0.683 AND LOG 5 7 = 1.209 TO APPROXIMATE… = log 5 3 – log 5 7 = 0.683 – 1.209 = -0.526
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PROPERTIES OF LOGARITHMS Power Property: PROPERTIES OF LOGARITHMS
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= -5 log b 9 EX. EXPRESS AS A PRODUCT. 11) 12)
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ON YOUR OWN Expanding the Logarithms:
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ON YOUR OWN Expanding the Logarithms:
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EX. 13 USE LOG 5 3 = 0.683 AND LOG 5 7 = 1.209 TO APPROXIMATE… = log 5 7 2 = 2(1.209) = 2.418 log 5 49 = 2 log 5 7
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EX. 14 EXPAND = log5+ logy+ logx 3 = log5 + logy + 3 logx log5x 3 y
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EX. 15 EXPAND Simplify the division. Simplify the multiplication of 4 Change the radical sign to an exponent Express the exponent as a product
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ON YOUR OWN Expanding the Logarithms:
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ON YOUR OWN Expanding the Logarithms:
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EX. CONDENSE. 16) 17)
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Express all products as exponents Simplify the subtraction. Change the fractional exponent to a radical sign. Simplify the addition. EX 18 CONDENSE
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PROPERTIES OF LOGARITHMS log a 1 = 0 log a a = 1 log a a x = x If log a x= log a ythen x = y because a 0 = 1 because a 1 = a Change-of-Base Product Property Quotient Property Power Property
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