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Discrete Mathematics Lecture 7. 2 Analysis of Algorithms Analyzing an algorithm Time complexity Space complexity Time complexity Running time needed by.

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Presentation on theme: "Discrete Mathematics Lecture 7. 2 Analysis of Algorithms Analyzing an algorithm Time complexity Space complexity Time complexity Running time needed by."— Presentation transcript:

1 Discrete Mathematics Lecture 7

2 2 Analysis of Algorithms Analyzing an algorithm Time complexity Space complexity Time complexity Running time needed by an algorithm as a function of the size of the input Denoted as T(N)

3 For analysing running time What do we mean by running time analysis? Determine how running time increases as the size of the problem increases Cost for each statement 1 unit time for arithmetic and logical operation,assignment and return Number of time each statement done By this two step we can find T(n) Asymptotic notation O-”big-oh” notation Upper bound for algorithm 3

4 Step1 int I = 0; Step2 while (I < n) Step3 { cout << “I is: " <<I; I++; } T(n)=3n+2 O(n) 4 stepcostNo. Of time 111 21N+1 32N

5 5 Step1 int i = 1; Step2 double sum = 0; Step3 while(i < n) Step4 { double value; cin >> value; sum = sum + value; i++; } Step5 double average = sum / i ; Step6 cout << "Average: " << average; T(n)=5n+1 => O(n) stepcostNo. Of time 111 211 31N 44N-1 521 611

6 6 Step1 for (int i = 0; i < n; i++) Step2 { cout << "i is " << i; } T(n)=4n+3 => O(n) _____________________________________ stepcostNo. Of time 13N+1 21N

7 Find big-oh for Nested loop for (int i = 0; i < n; i++) { for (int j = 0; j < n; j++) { //some statments } 7


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