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Solve a system of linear equations By reducing a matrix Pamela Leutwyler
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Describe the solutions to:
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The coefficient matrix:
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Replace row 1 with row 1 – row 2
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1 110
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Replace row 2 with row 2 – row 1
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Replace row 2 with row 2 – row 1 0 011
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Replace row 3 with row 3 – 3 row 1
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-3
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Replace row 3 with row 3 – 3 row 1 -3 0 011
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Replace row 3 with row 3 – row 2
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Replace row 3 with row 3 – row 2 00
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Replace row 1 with row 1 – row 2
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Replace row 1 with row 1 – row 2 0
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The matrix is in REDUCED ECHELON FORM
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1 1 Every FNZE is a 1 First NonZero Entry in a row of a matrix
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The matrix is in REDUCED ECHELON FORM 1 1 Every FNZE is a 1 Every FNZE is to the right of the FNZE above it.
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The matrix is in REDUCED ECHELON FORM 1 1 Every FNZE is a 1 Every FNZE is to the right of the FNZE above it. 0 0 0 0 In a column containing a FNZE, every other element is a 0
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Interpret :
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w= -x +z
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Interpret : w= -x +z y= -z
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Interpret : w= -x +z y= -z
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Interpret : w= -x +z y= -z x= x z= z x and z are the independent variables
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Interpret : w= -x +z y= -z x= x z= z
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Interpret : Every solution is a linear combination of these vectors
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