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CHAPTER 3 SOUND TRANSMISSION
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Sound in a Medium w Vibrating object displaces molecules in medium w molecules move back and forth w “bump” into others transmitting vibration thru medium
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In the Medium: w We have both OSCILLATION of particles w and w TRANSMISSION of energy (or propagation)
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Particle Motion w In Air, in line with transmission-- LONGITUDINAL w On Water, perpendicular to transmission-- TRANSVERSE
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Displacement of Molecules in the Medium w creates areas of more molecules w --increased density--CONDENSATION w and areas of fewer molecules w --decreased density--RAREFACTION
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Because We have Transmission: w We can talk about how fast sound travels in the medium = SPEED OF SOUND or c w Depends on medium, temperature, density, state w In Air = 344 meters/sec or 1100 feet/sec
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Sound Travels Out From the Source In All Directions (at the same speed) So, Until Sound Encounters some object, the “wavefront” is spherical
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We Can Also Talk About: w Distance Traveled during each cycle w = WAVELENGTH λ = c/f Wavelength = speed of sound / frequency
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Wavelength Questions: What is the wavelength in meters of a 1720 Hz sound traveling in air? What is the wavelength in meters of an 86 Hz sound traveling in air?
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Question 1: Freq = 1720 cyc/sec, c = 344 m/sec wavelength = c/f =344m/sec /1720 cyc/sec =0.2 m/cyc
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Question 2: Freq = 86 cyc/sec, c = 344 m/sec wavelength = c/f = 344m/sec /86 cyc/sec = 4 m/cyc
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When Talking about Amplitude: Remember Power is Rate at which Work is done (Work /Time = Power) But the power in sound doesn’t all travel the same direction Only some of it reaches you.
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Therefore, we are more interested in: How much Sound Power there is in a given area (e.g., the opening of ear canal, microphone) New term: INTENSITY = Power/Area
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Remember : Sound Power is spread over the Wavefront So the farther you are from the sound source: the larger the area over which power is spread the smaller the intensity
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Intuitively, we all know this The closer you are, the louder the sound The farther away you are, the softer the sound
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The Physics of the Situation: The relation between distance and intensity is an example of THE INVERSE SQUARE LAW Intensity = 1/distance 2
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WHY? Surface area of sphere = 4 Pi r 2 In this case r = distance The area is proportional to distance squared
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Change in Intensity = old d 2 / new d 2
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EXAMPLE: w Moving from 100 m to 200 m away from source w Delta I = 100 2 /200 2 w = 1 x 10 4 /4 x 10 4 = 1/4 =0.25
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Decibel Notation w Intensity is measured in Watts/cm 2 w Range of : w Just Audible 10 -16 W/cm 2 w to to w Just Painful 10 -4 W/cm 2
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Can You Imagine? w AUDIOLOGIST: “Mr. Smith, you hearing in the right ear is down to about 3 times ten to the negative twelfth Watts per square centimeter, while your left ear is a little bit better at ten to the negative fourteenth…” w MR. SMITH: “ZZZZZZZZZZZZZ”
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SO, We need a simpler set of numbers w Something less unwieldy w The Solution is the BEL (after A.G. Bell)
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The Genesis of the Bel w the logarithm of the ratio of a measurement to a reference value
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What is a log? w Log (x) = power you would raise 10 to to get x w e.g., log (10) = 1 w because 10 1 = 10 w or, log (0.01) = -2 w because 0.01 = 10 -2 w You can use a calculator to obtain logs
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Inside the Logarithm is w A ratio of two numbers (or fraction) w An absolute measurement over w A reference value
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The Reference Value for Intensity Level w is 1 x 10 -16 Watts/cm 2 w Bels IL = log ( Im/ 1 x 10 -16 W/cm 2 ) w Where Im = measured intensity
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The Range of Human Hearing w Detection w 10 -16 W/cm 2 OR 0 Bels w Pain w 10 -4 W/cm 2 OR 12 Bels
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The Bel Is Too Gross a Measure For Us w So, We work in TENTHS OF BELS w The DECIBEL (dB) w dB IL = 10 log ( Im/ 1 x 10 -16 W/cm 2 )
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EXAMPLE: w What is IL of sound with absolute intensity of 2 x 10 -16 W/cm 2 ? w = 10 log (2 x 10 -16 W/cm 2 / 1 x 10 -16 W/cm 2 ) w = 10 log (2) w = 10 (0.3010) w = 3 dBIL
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Example--Relative Change w How will the intensity level change if you move to twice as far from a source? w We know that intensity change = old dist 2 /new dist 2 w = 1/4 or 0.25 w dB IL = 10 log (0.25) = 10 (-0.5991) = 6 dB
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Bels or Decibels w Can be calculated from any measure w But dB IL means something specific w Another scale is dB SPL w Sound Pressure Level
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IMPEDANCE w The opposition to vibration, or w What, other than motion, happens to your applied force? w That is what do you have to overcome?
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Impedance has 3 components: w Resistance: Energy lost to heat through friction (R) w Mass Reactance: Energy taken to overcome inertia (Xm) w Stiffness Reactance: Energy taken to overcome restoring force (Xs)
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Impedance and Frequency: w Resistance is generally the same across frequency w Reactance Components change with frequency
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Reactance and Frequency: w Mass reactance is greater at high frequencies w --it’s harder to get massive objects to vibrate quickly w Stiffness reactance is greater at low frequencies w --it’s harder to get stiff objects to vibrate slowly
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Mass and Stiffness Reactance Resonant Freq.
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At Resonant Frequency w Mass and Stiffness Reactance Cancel w Only opposition to vibration is Resistance w In Forced Vibration, you get the most vibratory amplitude for amount of force applied
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Sound Wave Phenomena Reflection-bouncing off an object Absorption-sound trapped (absorbed) by an object Diffraction-spreading of sound into area beyond an object Refraction-bending of sound waves in a medium
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Sound Encountering an Object: Transmission-setting object into vibration Reflection-sound bounces back Absorption-sound becomes trapped in gaps of surface of object
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Reflected and Incident Sound Meet Producing INTERFERENCE Where the two waves meet in phase, the intensity doubles --Constructive Interference Where they meet out of phase, cancellation --Destructive Interference
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Getting around an Object: w depends on size of object and wavelength of sound λ > object’s diameter, sound passes by λ < object’s diameter, sound blocked w Area of reduced or no sound energy is “sound shadow”
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Diffraction Sound passing an object will spread to fill in area beyond it, behaving as if the edge of the object were the sound source.
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Refraction the bending of the sound’s path produced by changes in medium e.g., temperature changes will bend path of sound propagation
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Sound Fields FREE FIELD = no objects in medium ANECHOIC CHAMBER = room with highly absorptive walls; an attempt to create a free field.
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Sound Fields (cont’d) SOUND TREATED ROOM = has somewhat absorptive walls, produces some reflections REVERBERATION ROOM = highly reflective walls set at odd angles; many reflections and complex interactions. Creates a uniform (diffuse) sound field.
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Reverberation: Persistence of sound in a sound field after the source is turned off = time taken for intensity to drop to 1 millionth of initial value Reverberation ≈ ROOM VOL./ABSORPTION COEF.
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Reverberation Time Least for Anechoic Chamber Most for Reverberation Room Longer for larger rooms with reflective walls
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Earphones Miniature loudspeakers to introduce sound into the ear. Supra-aural (sits on the pinna) Insert (sits within external canal) Calibrated in “artificial ears” (6cc or 2cc couplers)
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The Doppler Effect w Change in the effective frequency produced by motion of the sound source. w (or by motion of the listener) w Toward >>higher frequency w Away >> lower frequency
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The Doppler Effect 1
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The Doppler Effect 2
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Resonance Helmholtz Resonators simulate influence of mass and compliance (stiffness) on resonance. Tube and Cavity. Mass component--inversely proportional to resonant freq Compliance component--directly prop. to resonant freq Resistance -- doesn’t affect resonant freq, but produces broader tuning
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Standing Waves Interaction between incident and reflected waves Produces areas of : constructive interf. --ANTINODE destructive interf. --NODE
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Incident & Reflected Sound Meet w Incident in Black w Reflected in Pink w Type of Interference varies with position.
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Standing Wave Illustration
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Standing Waves (cont’d) Intensity varies with position Position of nodes, antinodes depends on frequency Distance from node to antinode is 1/4 λ Distance from one node to the next is ½ λ
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Pipes produce standing waves w closed pipes —antinode at open end and node at closed end w open pipes — antinode at each open end w closed pipe, length = ¼ λ w open pipe, length = ½ λ
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Standing Waves in Pipes
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A closed pipe only produces odd harmonics. w Frequency of harmonics = (n c)/4 L, w Where n=1, 3, 5,... w c = speed of sound w L is the length of the pipe. w In music, harmonics are called overtones.
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