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S7 - 1© 2014 Pearson Education Capacity Planning PowerPoint presentation to accompany Heizer and Render Operations Management, Global Edition, Eleventh.

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Presentation on theme: "S7 - 1© 2014 Pearson Education Capacity Planning PowerPoint presentation to accompany Heizer and Render Operations Management, Global Edition, Eleventh."— Presentation transcript:

1 S7 - 1© 2014 Pearson Education Capacity Planning PowerPoint presentation to accompany Heizer and Render Operations Management, Global Edition, Eleventh Edition Principles of Operations Management, Global Edition, Ninth Edition PowerPoint slides by Jeff Heyl 7 © 2014 Pearson Education SUPPLEMENT

2 S7 - 2© 2014 Pearson Education Capacity ► The throughput, or the number of units a facility can hold, receive, store, or produce in a period of time ► Determines fixed costs ► Determines if demand will be satisfied ► Three time horizons

3 S7 - 3© 2014 Pearson Education Planning Over a Time Horizon Figure S7.1 Modify capacityUse capacity Intermediate- range planning (aggregate planning) SubcontractAdd personnel Add equipmentBuild or use inventory Add shifts Short-range planning (scheduling) Schedule jobs Schedule personnel Allocate machinery * Long-range planning Add facilities Add long lead time equipment * * Difficult to adjust capacity as limited options exist Options for Adjusting Capacity Time Horizon

4 S7 - 4© 2014 Pearson Education Design and Effective Capacity ► Design capacity is the maximum theoretical output of a system ► Normally expressed as a rate ► Effective capacity is the capacity a firm expects to achieve given current operating constraints ► Often lower than design capacity

5 S7 - 5© 2014 Pearson Education Utilization and Efficiency Utilization is the percent of design capacity actually achieved Efficiency is the percent of effective capacity actually achieved Utilization = Actual output/Design capacity Efficiency = Actual output/Effective capacity

6 S7 - 6© 2014 Pearson Education Bakery Example Actual production last week = 148,000 rolls Effective capacity = 175,000 rolls Design capacity = 1,200 rolls per hour Bakery operates 7 days/week, 3 - 8 hour shifts Design capacity = (7 x 3 x 8) x (1,200) = 201,600 rolls

7 S7 - 7© 2014 Pearson Education Bakery Example Actual production last week = 148,000 rolls Effective capacity = 175,000 rolls Design capacity = 1,200 rolls per hour Bakery operates 7 days/week, 3 - 8 hour shifts Design capacity = (7 x 3 x 8) x (1,200) = 201,600 rolls

8 S7 - 8© 2014 Pearson Education Bakery Example Actual production last week = 148,000 rolls Effective capacity = 175,000 rolls Design capacity = 1,200 rolls per hour Bakery operates 7 days/week, 3 - 8 hour shifts Design capacity = (7 x 3 x 8) x (1,200) = 201,600 rolls Utilization = 148,000/201,600 = 73.4%

9 S7 - 9© 2014 Pearson Education Bakery Example Actual production last week = 148,000 rolls Effective capacity = 175,000 rolls Design capacity = 1,200 rolls per hour Bakery operates 7 days/week, 3 - 8 hour shifts Design capacity = (7 x 3 x 8) x (1,200) = 201,600 rolls Utilization = 148,000/201,600 = 73.4% Efficiency = 148,000/175,000 = 84.6%

10 S7 - 10© 2014 Pearson Education Bakery Example Actual production last week = 148,000 rolls Effective capacity = 175,000 rolls Design capacity = 1,200 rolls per hour Bakery operates 7 days/week, 3 - 8 hour shifts Design capacity = (7 x 3 x 8) x (1,200) = 201,600 rolls Utilization = 148,000/201,600 = 73.4% Efficiency = 148,000/175,000 = 84.6%

11 S7 - 11© 2014 Pearson Education Bakery Example Actual production last week = 148,000 rolls Effective capacity = 175,000 rolls Design capacity = 1,200 rolls per hour Bakery operates 7 days/week, 3 - 8 hour shifts Efficiency = 84.6% Efficiency of new line = 75% Expected Output = (Effective Capacity)(Efficiency) = (175,000)(.75) = 131,250 rolls

12 S7 - 12© 2014 Pearson Education Bakery Example Actual production last week = 148,000 rolls Effective capacity = 175,000 rolls Design capacity = 1,200 rolls per hour Bakery operates 7 days/week, 3 - 8 hour shifts Efficiency = 84.6% Efficiency of new line = 75% Expected Output = (Effective Capacity)(Efficiency) = (175,000)(.75) = 131,250 rolls

13 S7 - 13© 2014 Pearson Education Capacity Considerations 1.Forecast demand accurately 2.Match technology increments and sales volume 3.Find the optimum operating size (volume) 4.Build for change

14 S7 - 14© 2014 Pearson Education Economies and Diseconomies of Scale Economies of scale Diseconomies of scale 1,300 sq ft store 2,600 sq ft store 8,000 sq ft store Number of square feet in store 1,3002,6008,000 Average unit cost (sales per square foot) Figure S7.2 © 2014 Pearson Education

15 S7 - 15© 2014 Pearson Education Managing Demand ► Demand exceeds capacity ► Curtail demand by raising prices, scheduling longer lead time ► Long term solution is to increase capacity ► Capacity exceeds demand ► Stimulate market ► Product changes ► Adjusting to seasonal demands ► Produce products with complementary demand patterns

16 S7 - 16© 2014 Pearson Education Complementary Demand Patterns 4,000 – 3,000 – 2,000 – 1,000 – J F M A M J J A S O N D J F M A M J J A S O N D J Sales in units Time (months) Combining the two demand patterns reduces the variation Snowmobile motor sales Jet ski engine sales Figure S7.3

17 S7 - 17© 2014 Pearson Education Tactics for Matching Capacity to Demand 1.Making staffing changes 2.Adjusting equipment ► Purchasing additional machinery ► Selling or leasing out existing equipment 3.Improving processes to increase throughput 4.Redesigning products to facilitate more throughput 5.Adding process flexibility to meet changing product preferences 6.Closing facilities

18 S7 - 18© 2014 Pearson Education Service-Sector Demand and Capacity Management ► Demand management ► Appointment, reservations, FCFS rule ► Capacity management ► Full time, temporary, part-time staff

19 S7 - 19© 2014 Pearson Education Bottleneck Analysis and the Theory of Constraints ► Each work area can have its own unique capacity ► Capacity analysis determines the throughput capacity of workstations in a system ► A bottleneck is a limiting factor or constraint ► A bottleneck has the lowest effective capacity in a system

20 S7 - 20© 2014 Pearson Education Bottleneck Analysis and the Theory of Constraints ► The bottleneck time is the time of the slowest workstation (the one that takes the longest) in a production system ► The throughput time is the time it takes a unit to go through production from start to end 2 min/unit4 min/unit3 min/unit ABC Figure S7.4

21 S7 - 21© 2014 Pearson Education Capacity Analysis ► Two identical sandwich lines ► Lines have two workers and three operations ► All completed sandwiches are wrapped Wrap/ Deliver 37.5 sec/sandwich Order 30 sec/sandwich BreadFill 15 sec/sandwich 20 sec/sandwich BreadFill Toaster 15 sec/sandwich20 sec/sandwich

22 S7 - 22© 2014 Pearson Education Capacity Analysis Wrap/ Deliver 37.5 sec Order 30 sec BreadFill 15 sec 20 sec BreadFill Toaster 15 sec20 sec ► The two lines each deliver a sandwich every 20 seconds ► At 37.5 seconds, wrapping and delivery has the longest processing time and is the bottleneck ► Capacity per hour is 3,600 seconds/37.5 seconds/sandwich = 96 sandwiches per hour ► Throughput time is 30 + 15 + 20 + 20 + 37.5 = 122.5 seconds

23 S7 - 23© 2014 Pearson Education Capacity Analysis ► Standard process for cleaning teeth ► Cleaning and examining X-rays can happen simultaneously Check out 6 min/unit Check in 2 min/unit Develops X-ray 4 min/unit8 min/unit Dentist Takes X-ray 2 min/unit 5 min/unit X-ray exam Cleaning 24 min/unit

24 S7 - 24© 2014 Pearson Education Capacity Analysis ► All possible paths must be compared ► Bottleneck is the hygienist at 24 minutes ► Hourly capacity is 60/24 = 2.5 patients ► X-ray exam path is 2 + 2 + 4 + 5 + 8 + 6 = 27 minutes ► Cleaning path is 2 + 2 + 4 + 24 + 8 + 6 = 46 minutes ► Longest path involves the hygienist cleaning the teeth, patient should complete in 46 minutes Check out 6 min/unit Check in 2 min/unit Develops X-ray 4 min/unit 8 min/unit Dentist Takes X-ray 2 min/unit 5 min/unit X-ray exam Cleaning 24 min/unit

25 S7 - 25© 2014 Pearson Education Break-Even Analysis ► Technique for evaluating process and equipment alternatives ► Objective is to find the point in dollars and units at which cost equals revenue ► Requires estimation of fixed costs, variable costs, and revenue

26 S7 - 26© 2014 Pearson Education Break-Even Analysis ► Fixed costs are costs that continue even if no units are produced ► Depreciation, taxes, debt, mortgage payments ► Variable costs are costs that vary with the volume of units produced ► Labor, materials, portion of utilities ► Contribution is the difference between selling price and variable cost

27 S7 - 27© 2014 Pearson Education Break-Even Analysis ► Revenue function begins at the origin and proceeds upward to the right, increasing by the selling price of each unit ► Where the revenue function crosses the total cost line is the break-even point

28 S7 - 28© 2014 Pearson Education Profit corridor Loss corridor Break-Even Analysis Total revenue line Total cost line Variable cost Fixed cost Break-even point Total cost = Total revenue – 900 – 800 – 700 – 600 – 500 – 400 – 300 – 200 – 100 – – |||||||||||| 010020030040050060070080090010001100 Cost in dollars Volume (units per period) Figure S7.5

29 S7 - 29© 2014 Pearson Education Break-Even Analysis ► Costs and revenue are linear functions ► Generally not the case in the real world ► We actually know these costs ► Very difficult to verify ► Time value of money is often ignored Assumptions

30 S7 - 30© 2014 Pearson Education Break-Even Analysis BEP x =break-even point in units BEP $ =break-even point in dollars P =price per unit (after all discounts) x =number of units produced TR =total revenue = Px F =fixed costs V =variable cost per unit TC =total costs = F + Vx TR = TC or Px = F + Vx Break-even point occurs when BEP x = F P – V

31 S7 - 31© 2014 Pearson Education Break-Even Analysis BEP x =break-even point in units BEP $ =break-even point in dollars P =price per unit (after all discounts) x =number of units produced TR =total revenue = Px F =fixed costs V =variable cost per unit TC =total costs = F + Vx BEP $ = BEP x P = P = F (P – V)/P F P – V F 1 – V/P Profit= TR - TC = Px – ( F + Vx ) = Px – F – Vx = ( P - V ) x – F

32 S7 - 32© 2014 Pearson Education Break-Even Example Fixed costs = $10,000 Material = $.75/unit Direct labor = $1.50/unit Selling price = $4.00 per unit BEP $ = = F 1 – ( V / P ) $10,000 1 – [(1.50 +.75)/(4.00)] = = $22,857.14 $10,000.4375

33 S7 - 33© 2014 Pearson Education Break-Even Example Fixed costs = $10,000 Material = $.75/unit Direct labor = $1.50/unit Selling price = $4.00 per unit BEP $ = = F 1 – ( V / P ) $10,000 1 – [(1.50 +.75)/(4.00)] = = $22,857.14 $10,000.4375 BEP x = = = 5,714 F P – V $10,000 4.00 – (1.50 +.75)

34 S7 - 34© 2014 Pearson Education Break-Even Example 50,000 – 40,000 – 30,000 – 20,000 – 10,000 – – |||||| 02,0004,0006,0008,00010,000 Dollars Units Fixed costs Total costs Revenue Break-even point

35 S7 - 35© 2014 Pearson Education Break-Even Example Multiproduct Case where V = variable cost per unit P = price per unit F = fixed costs W = percent each product is of total dollar sales expressed as a decimal i = each product Break-even point in dollars ( BEP $)

36 S7 - 36© 2014 Pearson Education Multiproduct Example Fixed costs = $3,000 per month ITEMPRICECOSTANNUAL FORECASTED SALES UNITS Sandwich$5.00$3.009,000 Drink1.50.509,000 Baked potato2.001.007,000 12345678 ITEM ( i ) SELLING PRICE ( P ) VARIABLE COST ( V )(V/P)(V/P)1 - ( V / P ) ANNUAL FORECASTED SALES $ % OF SALES WEIGHTED CONTRIBUTION (COL 5 X COL 7) Sandwich$5.00$3.00.60.40$45,000.621.248 Drinks1.500.50.33.6713,500.186.125 Baked potato2.001.00.50 14,000.193.097 $72,5001.000.470

37 S7 - 37© 2014 Pearson Education Multiproduct Example Fixed costs = $3,000 per month ITEMPRICECOSTANNUAL FORECASTED SALES UNITS Sandwich$5.00$3.009,000 Drink1.50.509,000 Baked potato2.001.007,000 12345678 ITEM ( i ) SELLING PRICE ( P ) VARIABLE COST ( V )(V/P)(V/P)1 - ( V / P ) ANNUAL FORECASTED SALES $ % OF SALES WEIGHTED CONTRIBUTION (COL 5 X COL 7) Sandwich$5.00$3.00.60.40$45,000.621.248 Drinks1.500.50.33.6713,500.186.125 Baked potato2.001.00.50 14,000.193.097 $72,5001.000.470 = = $76,596 $3,000 x 12.47 Daily sales = = $245.50 $76,596 312 days.621 x $245.50 $5.00 = 30.5  31 Sandwiches each day

38 S7 - 38© 2014 Pearson Education Reducing Risk with Incremental Changes (a)Leading demand with incremental expansion Demand Expected demand New capacity (d)Attempts to have an average capacity with incremental expansion Demand New capacity Expected demand (c)Lagging demand with incremental expansion Demand New capacity Expected demand Figure S7.6 (b)Leading demand with a one-step expansion Demand Expected demand New capacity

39 S7 - 39© 2014 Pearson Education Reducing Risk with Incremental Changes (a)Leading demand with incremental expansion Expected demand Figure S7.6 New capacity Demand Time (years) 123

40 S7 - 40© 2014 Pearson Education Reducing Risk with Incremental Changes (b)Leading demand with a one-step expansion Expected demand Figure S7.6 New capacity Demand Time (years) 123

41 S7 - 41© 2014 Pearson Education Reducing Risk with Incremental Changes (c)Lagging demand with incremental expansion Expected demand Demand Time (years) 123 New capacity Figure S7.6

42 S7 - 42© 2014 Pearson Education Reducing Risk with Incremental Changes (d)Attempts to have an average capacity with incremental expansion Expected demand New capacity Demand Time (years) 123 Figure S7.6

43 S7 - 43© 2014 Pearson Education Applying Expected Monetary Value (EMV) and Capacity Decisions ► Determine states of nature ► Future demand ► Market favorability ► Assign probability values to states of nature to determine expected value

44 S7 - 44© 2014 Pearson Education EMV Applied to Capacity Decision ▶ Southern Hospital Supplies capacity expansion EMV (large plant)= (.4)($100,000) + (.6)(–$90,000) = –$14,000 EMV (medium plant)= (.4)($60,000) + (.6)(–$10,000) = +$18,000 EMV (small plant)= (.4)($40,000) + (.6)(–$5,000) = +$13,000 EMV (do nothing)= $0


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