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ECE 875: Electronic Devices
Prof. Virginia Ayres Electrical & Computer Engineering Michigan State University
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Lecture 15, 12 Feb 14 Hw 04: FRI: Pr. 2.07 Chp. 02: pn junction:
Experimental measurements for concentration: Hall effect – Chp. 01: material: measure VAB, and I, choose dimensions and Bext C-V – Chp. 02: pn junction Two realistic configurations beyond abrupt linear pn junction: Linearly graded junction Double layer junction: important, develops at interfaces VM Ayres, ECE875, S14
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Lecture 15, 12 Feb 14 Hw 04: FRI: Pr. 2.07 Chp. 02: pn junction:
Experimental measurements for concentration: Hall effect – Chp. 01: material: measure VAB, and I, choose dimensions and Bext C-V – Chp. 02: pn junction Two realistic configurations beyond abrupt linear pn junction: Linearly graded junction Double layer junction: important, develops at interfaces VM Ayres, ECE875, S14
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Example: Sweep the voltage Instrument reads out C typically in Farads
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Example: Sze Fig: V = Vbattery
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Where is C: depletion region of a pn junction:
Can show equivalence to parallel plate capacitor: - Qtotal es + Qtotal
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Where is C: depletion region of a pn junction:
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Where you measure: C-V = same as I-V:
= SMU +Vext- Sweep the voltage p+ n WD = WDp + WDn
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Lecture 15, 12 Feb 14 Hw 04: FRI: Pr. 2.07 Chp. 02: pn junction:
Experimental measurements for concentration: Hall effect – Chp. 01: material: measure VAB, and I, choose dimensions and Bext C-V – Chp. 02: pn junction VM Ayres, ECE875, S14
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pn junction at equilibrium: ECE 474: Streetman & Bannerjee
VM Ayres, ECE875, S14
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pn junction at equilibrium: ECE 474: Streetman & Bannerjee
Q = charge density r x Vol r = q with sign (ND+ or NA-) Poisson equation relates charge to electric field E : dE /dx = r/ese0 (material is not polarized or magnetic) VM Ayres, ECE875, S14
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Abrupt pn junction at equilibrium: ECE 875: Sze:
Q = charge density r x Vol r = q with sign (ND+ or NA-) p n Poisson equation dE /dx = r/ese0 Solve for E Solve for built in potential ybi V0 Any potential: = Area VM Ayres, ECE875, S14
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Abrupt pn junction at equilibrium: Sze: names:
Potential V0 ybi Potential barrier qV0 qybi p-side: Ei – EF qyBp n-side: EF – Ei qyBn p-side: EF – EV qfp n-side: EC – EF qfn Potential drop across depletion region WD= Pot’l drop across p-side of WD + pot’l drop across n-side of WD : ybi = yp + |yn| Potential drop from 0 to x in WD: yi(x) VM Ayres, ECE875, S14
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Important questions are:
What is the magnitude and direction of the internal electric field? What are the values of the various potential drops that matter? Can I get an experimental measure of anything? VM Ayres, ECE875, S14
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What is the magnitude and direction of the internal electric field
What is the magnitude and direction of the internal electric field? Can I get an experimental measure of anything? An antenna probe won’t work inside a solid -no direct experimental measure of E (x) -x E direction -WDp = = WDn VM Ayres, ECE875, S14
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E direction E magnitude: f(x)
What is the magnitude and direction of the internal electric field? Can I get an experimental measure of anything? -x E direction About the directions: E (x) direction = -x dx from/to direction = +x x is + from 0 to WDn x is – from –WDp to 0 E magnitude: f(x) -WDp = = WDn
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What are the values of the various potential drops that matter
What are the values of the various potential drops that matter? Can I get an experimental measure of anything? Yes: can get an experimental measure of potential. The loop will include the built-in potential ybi and Vext and any IR drops. Total potential drop Vp-to-n is mainly across W ybi Vext VM Ayres, ECE875, S14 = SMU
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Potential energy barrier and built-in potential in terms of dopants:
But what if doping concentrations are not what you think? VM Ayres, ECE875, S14
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Internal electric field E (x): in WD:
VM Ayres, ECE875, S14
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Internal electric field E (x):
Note: Linear: VM Ayres, ECE875, S14
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Internal electric field E (x):
Can solve for maximum value of E -field: VM Ayres, ECE875, S14
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Internal electric field E (x):
VM Ayres, ECE875, S14
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Internal electric field E (x):
Note: Linear: VM Ayres, ECE875, S14
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Go from electric field E (x) to potential yi(x)
Go from electric field E (x) to potential yi(x). Why: you may be able to measure a potential drop. + Can integrate this! = E 0 x + C VM Ayres, ECE875, S14
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Must separate this into p-side and n-side of depletion region answers:
p-side of depletion region: VM Ayres, ECE875, S14
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