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Published byRhoda Arnold Modified over 9 years ago
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Avogadro’s Number 6.02 X 10 23
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1 Mole of anything 6.02 X 10 23 of that thing
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Can be: - atoms - molecules - ions Particles
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0.5 Mole 3.01 X 10 23
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0.25 Mole 1.50 X 10 23
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2.0 Mole 12.04 X 10 23 Or 1.204 X 10 24
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1.0 Mole of any gas at STP 22.4 Liters
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STP Standard Temperature = 0 C Standard Pressure = 1 atm
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0.5 mole of any gas 11.2 Liters
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2.0 mole of any gas 44.8 Liters
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3.0 mole of any gas 67.2 Liters
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0.25 mole of any gas 5.6 Liters
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Formula Mass Sum of the masses of the elements in the compound. Expressed in atomic mass units
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Formula Mass of H 2 O 2 X H = 2 X 1.0 = 2.0 1 X O = 1 X 16.0 = 16.0 Sum = 18.0 amu’s
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Formula Mass of NH 3 3 X H = 3 X 1.0 = 3.0 1 X N = 1 X 14.0 = 14.0 Sum = 17.0 amu
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Formula Mass of CO 2 1 X C = 1 X 12.0 = 12.0 2 X O = 2 X 16.0 = 32.0 Sum = 44.0 amu
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Gram Formula Mass Formula mass expressed in grams. Equals the molar mass of the compound.
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Molar Mass Mass of one mole of the substance.
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Molar Mass H 2 O = NH 3 = CO 2 = 18.0 grams 17.0 grams 44.0 grams
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Count up the atoms in (NH 4 ) 2 SO 4 For Paren: Sub Inside X Sub outside N: 2S: 1 H: 8O: 4
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Count up the atoms in 2Mg 3 (PO 4 ) 2 For Paren: Sub Inside X Sub outside Coefficients X subs in formula Mg: 6P: 4O: 16 The “2” applies to every element in the formula.
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# of Moles # of Grams # of Particles # of Liters (gas) X 6.02 X 10 23 X Formula Mass X 22.4 L/mole by 6.02 X 10 23 by formula mass by 22.4
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Percent Part X 100% Whole
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Percent H in H 2 O Part X 100% = 2 X 100% Whole 18
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Percent O in H 2 O Part X 100% = 16 X 100% Whole 18
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Empirical Formula smallest whole number ratio of the elements in a compound
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Molecular Formula Gives exact composition of molecule
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Covalent Compound Formula contains all nonmetals
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Molecular (vast majority) & Network (SiO 2, SiC, C dia, C graph ) Types of covalent substances
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Ionic Compound Formula contains metal plus nonmetal
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Hydrate Ionic compound that has H 2 O molecules incorporated into its structure.
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Anhydrate Substance that remains after the water is removed from a hydrate.
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CuSO 45H 2 O Formula of a hydrated salt. means “is associated with.” H 2 O molecules are stuffed in the empty spaces.
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CuSO 4 ·5H 2 O ? CuSO 4 + 5H 2 O Heat to constant mass Evaporates into air anhydrate hydrate
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Formula mass of CuSO 45H 2 O Mass of CuSO 4 plus mass of 5 water molecules. 249.6 grams/mole
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Percent H 2 O in CuSO 4 5H 2 O (from the formula) Part X 100% = 90 X 100% Whole249.6
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Metals All elements to the left of the staircase except H
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Nonmetals All elements to the right of the staircase plus H
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Binary Compound Compound made from 2 elements
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Which formulas are empirical? H 2 OH 2 O 2 CH 4 C 2 H 6 C 6 H 12 O 6 KClP 4 O 10 CaF 2
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Crystal Lattices Ionic Compounds, Metals, & Network Solids make….
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Smallest repetitive unit in a crystal lattice Formula Unit
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Have distinctly different properties than molecular substances. Substances with crystal lattices…
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Types of Substances Ionic May be Binary Or may have > 2 elements May contain a transition metal Metallic Cu CuAl 2 Covalent May be Molecular or Network (SiO 2, SiC, C dia, C graph )
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Ionic, Metallic, and Network solids What kind of substances have Crystal Lattices?
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Empirical formulas only Substances that make crystal lattices have
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Have both empirical & molecular formulas. The molecular formula is a whole- number multiple of the empirical formula. Molecular Covalent Substances
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Given empirical formula & Formula Mass, find Molecular Formula 1)Find empirical mass 2)Divide formula mass/empirical mass 3)Multiply subscripts in empirical formula by answer in step 2
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Empirical formula = CH & Formula Mass = 78, find Molecular Formula 1)Empirical mass = 13 2)Divide formula mass/empirical mass = 78/13 = 6 3)Multiply subscripts: C 6 H 6
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12 grams of hydrated salt is heated to constant mass. After heating the mass is 8.0 grams. What is the percent salt & the percent H 2 O? 1)Mass of H 2 O = 12 – 8 = 4 g 2)Percent H 2 O = 4/12 X 100% 3)Percent salt = 8/12 X 100% Percent water in hydrate from experimental data.
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He 1 atom of He or 1 mole of He 1 atom per molecule
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O2O2 1 molecule of O 2 or 1 mole of O 2 2 atoms per molecule
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O3O3 1 molecule of O 3 or 1 mole of O 3 3 atoms per molecule
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Percent composition to empirical formula 1.Convert to mass. 2.Convert to moles. 3.Divide by small. 4.Multiply ‘til whole.
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Find the empirical formula: 45.27% C, 9.50% H, 45.23% O 1)45.27 g C, 9.50 g H, and 45.23 g O 2)3.773 mol C, 9.50 mol H, and 2.827 mol O 3)Divide by 2.827: C 1.33 H 3.36 O 1 4)Multiply by 3: C 4 H 10 O 3
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