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Le Châtelier’s Principle Chapter 14.3
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Chemical Equilibrium The point in a chemical reaction when dynamic equilibrium has been achieved and the concentration of the reactants and products remains constant
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What do you do when your stomach growls from hunger? Feed it!
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What do you do when your foot falls asleep? Adjust your legs so that the circulation will be restored to your feet.
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What do you do when your checking account is at a zero balance? Have your mom deposit more money, of course! All of these are examples of how a system at equilibrium responds to a stress in order to regain the state of equilibrium
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Le Châtelier’s Principle The principle that states that a system in equilibrium will oppose the change in a way that helps eliminate the change.
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In other words Whenever a system at equilibrium is disturbed, the system will shift in the direction which counteracts the disturbance
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Huh? Chemical reactions respond to similar stresses to the system Note: when a system returns to a state of equilibrium, there is a new equilibrium point because the original conditions have been changed.
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For Example In your classroom, as Mrs. Price is teaching, a very loud and obnoxious student wanders in. Your classroom is at dynamic equilibrium when the teacher is instructing and the students are engaged and learning (Insert laugh here!) A student disturbs the peaceful instructive classroom Mrs. Price sends the student to Mr. Francis thereby restoring order, hence equilibrium
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Stress According to Le Châtelier Stresses including changes in concentration, temperature and pressure are subject to Le Châtelier’s Principle
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Chemical Shift A chemical shift is when either the forward or reverse reaction is favored by the introduction of a stress. Equilibrium
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So... A forward shift is to the right of the reaction in response to a stress A reverse shift is to the left of the reaction in response to a stress
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Effect of Concentration N 2 + 3H 2 2NH 3 If the [N 2 ] is increased, in other words, we add more reactant, Then, the reaction will shift to the right, forward shift, in order to remove any additional nitrogen
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Forward Shift So, let’s 1 add some nitrogen and the system will become 2 reactant heavy As a result, the system will consume the nitrogen and the forward reaction will be favored; hence, the [NH 3 ] increases and the [H 2 ] decreases to once again 3 achieve equilibrium 1. N 2 + 3H 2 2NH 3 2. N 2 + 3H 2 2NH 3 3 N2 + 3H 2 2NH 3
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Reverse Shift Suppose instead of nitrogen, the [NH 3 ] is 1 increased. The reaction becomes 2 product heavy As a result, the system will decompose the ammonia and the reverse reaction will be favored; hence, the [NH 3 ] decreases and the [N 2 ] and [H 2 ] decreases to once again 3 achieve equilibrium 1. N 2 + 3H 2 2NH 3 2. N 2 + 3H 2 2NH 3 3 N2 + 3H 2 2NH 3
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Common Ion Effect In a saturated solution of an ionic compound, the ions are in equilibrium with it’s solid form AgCl(s) Ag + (aq) + Cl - (aq) If you add additional Cl - from a different ionic parent, more AgCl will be produced
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Reduction of Solubility The common ion effect reduces the solubility of slightly soluble compounds
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Effect of Volume Change What happens when you reduce the volume of a system? The pressure increases, and the particles are closer together The stress can be relieved by producing a smaller number of particles
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Example Let’s look again at the Haber process There are 4 moles of reactants and 2 moles of product Reducing the volume would shift the reaction to the right where there are fewer particles N 2 (g) + 3H 2 (g) 2NH 3 (g)
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Another Example Let’s look at the reaction of Hydrogen and Chlorine to form Hydrochloric Acid H 2 (g) + Cl 2 (g) 2HCl(g) There are 2 moles of reactant AND product so an increase or a decrease in volume would not cause the reaction to shift
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Pressure Changes Pressure changes have almost no effect on equilibrium reactions in solution Pressure effects the equilibrium of gaseous species
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Changing the Temperature We can raise the temperature of a system by adding energy in the form of heat Adding heat to a system is endothermic Removing heat from a system is exothermic
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Lower the Temperature Because an exothermic reaction releases heat, it will favor a decrease in the temperature Lower the temperature in a system and the reaction will shift to the exothermic side in order to replace some of the lost heat
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Raise the Temperature Because an endothermic reaction absorbs heat, it will favor an increase in the temperature Raise the temperature in a system and the reaction will shift to the endothermic side in order to absorb the excess
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Lower the Temperature in the Haber Process When we lower the temperature, the reaction shifts toward the exothermic side The [NH 3 ] is increased and the [N 2 ] and [H 2 ] is decreased N 2 (g) + 3H 2 (g) 2NH 3 (g) + 91.8kJ
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Effects of a Catalyst At equilibrium, a catalyst increases the forward and reverse reactions equally However, if a system is NOT at equilibrium, a catalyst will shorten the time needed to achieve equilibrium
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In General, here are the rules
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Now for the chemistry version.. 4NH 3 (g) + 5O 2 (g) --> 4NO(g) + 6H 2 O(g) + energy What would happen if you... Added more product of NO(g)? Answer: The reaction would shift to the left in order to consume some of the added NO
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Now for the chemistry version.. 4NH 3 (g) + 5O 2 (g) --> 4NO(g) + 6H 2 O(g) + energy What would happen if you... Removed an amount of the reactant O 2 (g)? Answer: the reaction would shift to the left to replace the missing O 2 (g)
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Now for the chemistry version.. 4NH 3 (g) + 5O 2 (g) --> 4NO(g) + 6H 2 O(g) + energy What would happen if you... Increase the pressure by decreasing the volume? Answer: The reaction would shift toward the left which is the side with fewest gas molecules.
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Now for the chemistry version.. 4NH 3 (g) + 5O 2 (g) --> 4NO(g) + 6H 2 O(g) + energy What would happen if you... Decreased the temperature of the system? Answer: The reaction would shift to the right which is the side that produces energy in the form of heat.
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Now for the chemistry version.. 4NH 3 (g) + 5O 2 (g) --> 4NO(g) + 6H 2 O(g) + energy What would happen if you... Added a catalyst? Answer: There would be no change in the equilibrium. A catalyst simply changes the rate of a reaction without being consumed or changed significantly.
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Summary of Effects
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