1. Surface Area LxW πr 2 ½ bh

2. Suppose you were given 100ft of string and wanted to construct a geometric shape with the greatest possible area. What shape should you create?

3. 25ft 20ft 30ft In all three cases the perimeter = 100ft C = 100ft

4. Suppose you were given 100ft of string and wanted to construct a geometric shape with the greatest possible area. What shape should you create? 25ft 20ft 30ft In all three cases the perimeter = 100ft C = 100ft A = LxW= 25ft 2 = 625ft 2 A = LxW= 20ft 2 x30ft 2 = 600ft 2 C = 2πr; r= 100/2π = 15.9ft A = πr 2 = π15.9 2 = 794ft 2 C = 2πr; r= 100/2π = 15.9ft A = πr 2 = π15.9 2 = 794ft 2

5. Three Objects of Equal Perimeter (12 units) but clearly the square has the largest surface area! You can’t cut a piece off of a rectangle and attach it turning it into a 3x3 square.

6. Square vs Circle where the perimeter/circumference is 12 units. The circle is clearly bigger. Perimeter is not directly related to surface area!

7. Square vs Circle where the perimeter/circumference is 12 units. The circle is clearly bigger. Perimeter is not directly related to surface area!

8. How do you find the surface area of a cylinder?

9. If you unravel a cylinder you have two circles (top and bottom) and a rectangle whose length is the circumference of the cirlces πr 2 2πrh πr 2 + πr 2 + 2πrh = 2πr 2 + 2πrh = 2πr(r+h)

10. HOMEWORK! Mathematically demonstrate that the area of a heart can be found using the formula: (π + 4)r 2. Show all steps!

11. HOMEWORK! Mathematically demonstrate that the area of a heart can be found using the formula: (π + 4)r 2. Show all steps! HINT!

12. Surface Area to Volume Lab! Image modified from Hewitt: Conceptual Physics

13. What happens if we double the Linear Dimensions of a 1g Object? Length Surface Area Mass Volume Density SA:V SA:M Length Surface Area Mass Volume Density SA:V SA:M

14. What happens if we double the Linear Dimensions of a 1g Object? Length4 Surface Area96 Mass8 Volume64 Density1/8 SA:V3/2 SA:M12/1 Length2 Surface Area24 Mass1 Volume8 Density1/8 SA:V3 SA:M24/1

15. What happens if we double the Linear Dimensions of a 1g Object? Length4 Surface Area96 Mass8 Volume64 Density1/8 SA:V3/2 SA:M12/1 Length2 Surface Area24 Mass1 Volume8 Density1/8 SA:V3 SA:M24/1 Doubling the linear dimensions decreases the SA:V ratio. Doubling the linear dimensions decreases the SA:M ratio. The volume and mass go up by a factor of 3 (2 3 ) or 8x as much Surface Area increases with the square and mass and volume with the cube of the increase in linear dimensions. Volume and Mass increase faster than surface area when we scale an object up.

16. What happens if we quadruple the Linear Dimensions of an object? The volume increases by a factor of? The Surface Area increases by a factor of? The mass increases by a factor of?

17. What happens if we quadruple the Linear Dimensions of an object? The volume increases by a factor of? 4 3 or 64x V B = 64V A The Surface Area increases by a factor of? 4 2 or 16x SA B = 16SA A The mass increases by a factor of? 4 3 or 64x m B = 64m A B B A A Remember, we are quadrupling the linear dimensions, not increasing the volume by 4x as much! As we see, volume and mass increase much faster than area when scaling up!

18. Surface Area to Volume Ratios and Biology Cells must be small because they rely on the process of diffusion to transport needed material in and out of the cell walls. When the surface area to volume ratio is high diffusion is more efficient and the cell is happy. If the surface area to volume ratio is low then we have a high volume/mass of material with a comparatively smaller surface area for nutrient transfer. The Cell is sad. Big Cell with Low SA:V SAD CELL! Small Cell with High SA:V HAPPY CELL! Plant Cells > Animals cells but have larger Vacuoles

19. Surface Area to Volume Ratios and Biology Unicellular Organisms: small with high SA:V ratio so diffusion works well. Once a cell gets too big it must DIVIDE! (and conquer the world!) Multicellular Organisms: are large and overcome a low SA:V ratio having lungs (gas exchange organs) and a circulatory system (blood) that helps transfer needed materials into and out of the organism. Model Cell Diffusion with Agar

20. Surface Area and Chemistry Zn + 2HCl  ZnCl 2 +H 2 (DEMO) ZINC CUBE METAL H+H+ H+H+ Cl - H+H+ H+H+ H+H+ H+H+ H+H+ H+H+ H+H+ H+H+ We are going to put a block of Zinc into a cup full of Hydrochloric Acid and model a single replacement reaction.

21. Surface Area and Chemistry Zn + 2HCl  ZnCl 2 +H 2 (DEMO) ZINC CUBE METAL H+H+ H+H+ Cl - H+H+ H+H+ H+H+ H+H+ H+H+ H+H+ H+H+ H+H+ Hydrogen Gas is leaving Cl - H+H+ H+H+ H+H+ H+H+ H+H+ H+H+ The zinc atoms on the surface of the Zinc react with the Chloride ions forming ZnCl 2 Cl - Zn +2

22. Surface Area and Chemistry Zn + 2HCl  ZnCl 2 +H 2 (DEMO) ZINC CUBE METAL  The Rate of any Chemical Reaction will be proportional to the Surface area of the reactants.  Supposing our Zinc cube is 2in by 2in by 2in what is its total surface area? 2”

23. Surface Area and Chemistry Zn + 2HCl  ZnCl 2 +H 2 (DEMO) ZINC CUBE METAL  The Rate of any Chemical Reaction will be proportional to the Surface area of the reactants.  Supposing our Zinc cube is 2in by 2in by 2in what is its total surface area?  A Cube has 6 sides or faces and the surface area of each one is LxW so  SA = 6(LxW) = 24in 2 2”

24. Surface Area and Chemistry Zn + 2HCl  ZnCl 2 +H 2 (DEMO) ZINC CUBE METAL  What happens to surface area if we cut the cube in half? 2” ZINC CUBE METAL SA = 24in 2

25. Surface Area and Chemistry Zn + 2HCl  ZnCl 2 +H 2 (DEMO) ZINC CUBE METAL  What happens to surface area if we cut the cube in half? 2” ZINC CUBE METAL SA = 24in 2 We have two extra sides or faces. Thus the SA goes up. SA=???

26. Surface Area and Chemistry Zn + 2HCl  ZnCl 2 +H 2 (DEMO) ZINC CUBE METAL  What happens to surface area if we cut the cube in half? 2” ZINC CUBE METAL SA = 24in 2 We have two extra sides or faces. Thus the SA goes up. SA=32in 2

27. Surface Area and Chemistry Reaction Rate is Surface Area! ZINC CUBE METAL  Continuing the Process Results in more and more Surface Area  Thus, a crushed substance or powder should react more quickly than a larger version of itself.  Mass and Volume remain constant but SA increases by crushing! 2” ZINC CUBE METAL

28. Whoosh Bottle & Combustion Alcohol is flammable. In the whoosh bottle demonstration we use 92% Isopropyl alcohol. QUESTION: Why is this reaction so spectacular whereas a cup of alcohol will simply light on fire?

29. Whoosh Bottle & Combustion Alcohol is flammable. In the whoosh bottle demonstration we use 92% Isopropyl alcohol. QUESTION: Why is this reaction so spectacular whereas a cup of alcohol will simply light on fire? ANSWER: A puddle of alcohol will evaporate into gas quicker than a puddle of water because alcohol has a low vapor pressure. Crushing a substance increases the surface area but those particles may still touch one another or be piled on one another reducing the surface area available for a reaction! Gas particles are very small and spread out leading to maximal surface area for a reaction. I swirl the jug for a bit so the alcohol evaporates into a gas and has more surface area for the reaction. The same combustion reaction of lighting a cup of alcohol occurs, but this one occurs at a much faster rate due to increased surface area! 2 C 3 H 7 OH (l) + 9 O 2 (g) ----> 6 CO 2 (g) + 8 H 2 O (g)

30. Extensions of Surface Area:  A puddle will evaporate much faster than a cup with the same amount of water.  Granular sugar will dissolve much faster in water than sugar cubes.  Small wood or kindling will burn much faster than a large log.  Table salt will dissolve and dissociate in water much quicker than rock salt.  Why? Rusting, Evaporation, Dissolving, Burning and any Chemical Reaction are all proportional to the surface area of the object DEMOS: Burning wood vs wood Dust! Burning or rusting Steel (solid) vs steel wool vs steel powder Cornstarch burned as a powder vs blown. THINK ABOUT IT: Why will steel wool combust better than steel powder?

31. Extensions of Surface Area:  A puddle will evaporate much faster than a cup with the same amount of water.  Granular sugar will dissolve much faster in water than sugar cubes.  Small wood or kindling will burn much faster than a large log.  Table salt will dissolve and dissociate in water much quicker than rock salt.  Why? Rusting, Evaporation, Dissolving, Burning and any Chemical Reaction are all proportional to the surface area of the object DEMOS: Burning wood vs. wood Dust! Burning or rusting Steel (solid) vs. steel wool vs. steel powder Cornstarch burned as a powder vs. blown. THINK ABOUT IT: Why will steel wool combust better than steel powder? In order for combustion to occur you need O 2. As a powder the steel particles are all on top of one another. There isn’t a lot of oxygen between them. Steel wool is “frizzy” and there is a lot of room and oxygen between the thin strands of metal. Video/Demo: combustion of steel wool in an oxygen rich environment.