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1 Lectures posted online after lecture. Textbook sections and/or pages posted a few days prior to each lecture.

2 In many instances there is a unique pattern of inheritance. Traits disappear and reappear in new ratios. CB 14.3

3 GenotypePhenotype CB 14.6

4 Human blood types AA or AO AB BB or BO OO CB tbl 14.2

5 Looking at the past: If Frank has B blood type, his Dad has A blood type, And his Mom has B blood type… Should Frank be worried?

6 Mom=B blood BB or BO Dad=A blood AA or AO Gametes all B / 50% B and 50% O all A / 50% A and 50% O possible genotypes Frank can be BO = B blood …no worries

7 We can also predict the future Fig 2.12

8 Mom = ABDad = AB Inheritance of blood types

9 Mom = ABDad = AB Gametes:A or B Inheritance of blood types

10 Mom = ABDad = AB Gametes: A or B AA ABBB AB Chance of each phenotype for each offspring 25% AA 50% AB 25% BB Mom Dad Inheritance of blood types

11 CB 14.7 Testcross: determining dominant/ recessive and zygosity

12 CB 5.21 Sickle-cell anemia is caused by a point mutation

13 Sickled and normal red blood cells

14 Mom = HSDad = HS H or S HH HSSS HS possible offspring 75% Normal 25% Sickle-cell Mom Dad S=sickle-cell H=normal Sickle-Cell Anemia: A dominant or recessive allele?

15 Coincidence of malaria and sickle-cell anemia CB 23.13

16 Mom = HSDad = HS H or S HH HSSS HS possible offspring Oxygen transport: 75% Normal 25% Sickle-cell Malaria resistance: 75% resistant 25% susceptible Mom Dad Sickle-Cell Anemia: A dominant or recessive allele? S=sickle-cell H=normal

17 Variation in Peas

18 Phenotype Genotype CB 14.8

19 The inheritance of genes on different chromo- somes is independent.

20 Y y rR Gene for seed color Gene for seed shape Approximate position of seed color and shape genes in peas Chrom. 1/7Chrom. 7/7

21 CB 15.2 The inheritance of genes on different chromosomes is independent: independent assortment

22 CB 15.2 meiosis I meiosis II

23 CB 15.2 The inheritance of genes on different chromosomes is independent: independent assortment

24 CB 14.8

25 Inheritance can be predicted by probability CB 14.9

26 Probability of a 4= 1/6 Probability of two 4’s in a row= 1/6x1/6=1/36

27 Probability of 3 or 4 = 1/6+1/6= 1/3

28 “and” multiply “or” add

29 Huntington’s Disease D=disease d=normal Neurological disease, symptoms begin around 40 years old.

30 Mom = ddDad = Dd d or d D or d Dd dd possible offspring 50% Huntington’s 50% Normal Mom Dad Huntington’s Disease D=disease d=normal

31 Two different people: One with Huntington’s disease = Dd Hh One without Huntington’s disease = dd Hh mate. What is the probability that their offspring will have Huntington’s disease and sickle cell anemia? (Dd hh)

32 Two people: One with Huntington’s disease = Dd Hh One without Huntington’s disease = dd Hh mate. What is the probability that their offspring will have Huntington’s disease and sickle cell anemia? Dd hh Probability of each outcome: Probability of Dd (Ddxdd) =.5 Probability of hh (HhxHh) =.25

33 Two people: One with Huntington’s disease = Dd Hh One without Huntington’s disease = dd Hh mate. What is the probability that their offspring will have Huntington’s disease and sickle cell anemia? Dd hh Probability of each outcome: Probability of Dd (Ddxdd) =.5 Probability of hh (HhxHh) =.25 Multiply both probabilities.25 X.5 = 12.5% chance Dd hh offspring

34 CB 14.11 Many traits are coded for by more than one gene.

35 Eye color: One trait controlled by multiple genes

36 Lectures posted online after lecture. Textbook sections and/or pages posted a few days prior to each lecture.


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