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Factor Theorem Using Long Division, Synthetic Division, & Factoring to Solve Polynomials.

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Presentation on theme: "Factor Theorem Using Long Division, Synthetic Division, & Factoring to Solve Polynomials."— Presentation transcript:

1 Factor Theorem Using Long Division, Synthetic Division, & Factoring to Solve Polynomials

2 Long Division Review

3 Synthetic Division Review 1-303-1 1| 1 1 -2 1 1 0 Since,, that means our first term is an x 3.

4 The Remainder Theorem  If a polynomial is divided by another polynomial and it equals the quotient with NO Remainder, then the divisor and the quotient are factors of the dividend. and are factors of

5 The Factor Theorem  A polynomial f(x) has a factor x – k, if and only if f(k) = 0.  Which means two things: 1.f(x) divided by x – k has no remainder. 2.k is a root (zero, x-intercept) of f(x).`

6 Using the Factor Theorem  Divide f(x) by x + 4 to find the remaining factor.  Also, -4 is a root of f(x). Solve given that

7 Solve given that f(-4)=0.

8 Solve given that f(-3)=0. 1-6-1342 -3| 1 -3 -9 27 14 -42 0

9 You Try One! Solve given that Don’t Forget

10 Solve given that f(-1)=0 and f(1) = 0. Use Quadratic Formula to find the last two zeroes. The zeroes are –1, 1,.


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