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6.3 Dividing Polynomials (Day 1)

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Presentation on theme: "6.3 Dividing Polynomials (Day 1)"— Presentation transcript:

1 6.3 Dividing Polynomials (Day 1)

2 Quotient Divisor Dividend So is 6 a factor of 24? Yes, 6 x 4 = 24
The remainder is 0 So is 9 a factor of 6413? No, 9 x 712 = 6413 The remainder is 5 not 0

3 Polynomial Long Division
Divide using long division. Check your answers. R 5 Process to get quotient answers. So is x – 4 a factor of x2 – 3x + 1? No, (x – 4)(x + 1) = x2 – 3x + 1 The remainder is 5 not 0.

4 White Boards Divide using long division. Check your answers.
Quotient? Quotient? Is x+ 4 a factor? Yes Is x – 2 a factor? No

5 Synthetic Division The Shortcut of Long Division
A simplified process to divide by a linear factor. You omit all variables and exponents. By reversing the sign in the divisor, you can add throughout the process instead of subtracting. add add add multiply Quotient?

6 Divide using synthetic division.
White Boards 6. Quotient?

7 6.3 Dividing Polynomials (Day 2)

8 1. 2. Divide using synthetic division. White Boards Quotient? add add
multiply Quotient? 2.

9 Divide using synthetic division.
White Boards 2. Quotient?

10 3. Find P(-1) Remainder Theorem: If a polynomial P(x) of degree n > 1 is divided by (x – a), where a is a constant, then the remainder is P(a) P( – 1) = 2

11 = -22 = 168 Use Synthetic Division and the Remainder Theorem to find:
White Boards Use Synthetic Division and the Remainder Theorem to find: = -22 = 168


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