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BMayer@ChabotCollege.edu ENGR-25_Prob_2-24_Solution.ppt 1 Bruce Mayer, PE ENGR/MTH/PHYS25: Computational Methods Bruce Mayer, PE Registered Electrical & Mechanical Engineer BMayer@ChabotCollege.edu Engineering 43 Chp 2 Tutorial Problem 2-24 Solution
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BMayer@ChabotCollege.edu ENGR-25_Prob_2-24_Solution.ppt 2 Bruce Mayer, PE ENGR/MTH/PHYS25: Computational Methods Amplifier Driving Speaker Consider an Amplifier Circuit connected to a Speaker Driving Circuit a.k.a. the “SOURCE” Speaker a.k.a. the “LOAD”
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BMayer@ChabotCollege.edu ENGR-25_Prob_2-24_Solution.ppt 3 Bruce Mayer, PE ENGR/MTH/PHYS25: Computational Methods Circuit Simplification Thévenin’s Equivalent Circuit Theorem (c.f. ENGR43) Allows Tremendous Simplification of the Amp Ckt Thevenin + R S V S
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BMayer@ChabotCollege.edu ENGR-25_Prob_2-24_Solution.ppt 4 Bruce Mayer, PE ENGR/MTH/PHYS25: Computational Methods Maximum Power Transfer The Simplest Model for a Speaker is to Consider it as a RESISTOR only Since the “Load” Does the “Work” We Would like to Transfer the Maximum Amount of Power from the “Source” to the “Load” BASIC MODEL FOR THE ANALYSIS OF POWER TRANSFER + ─ R S V S SPEAKER MODEL R L Anything Less Results in Lost Energy in the Driving Ckt in the form of Heat
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BMayer@ChabotCollege.edu ENGR-25_Prob_2-24_Solution.ppt 5 Bruce Mayer, PE ENGR/MTH/PHYS25: Computational Methods The Final Ckt Model Driving Circuit The Speaker
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BMayer@ChabotCollege.edu ENGR-25_Prob_2-24_Solution.ppt 6 Bruce Mayer, PE ENGR/MTH/PHYS25: Computational Methods Electrical Power Physics For ANY Electrical Device with a: Potential, V, across it A current, I, thru it V I Then the Power Used by the Device: Now OHM’s Law Relates the Voltage- across and Current- Thru a resistor
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BMayer@ChabotCollege.edu ENGR-25_Prob_2-24_Solution.ppt 7 Bruce Mayer, PE ENGR/MTH/PHYS25: Computational Methods Voltage Division Recall the Reduced Ckt Model This SINGLE LOOP Ckt effectively divides V S across R S and R L Analysis of this “Voltage Divider” Ckt produces a Relationship between V S & V L
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BMayer@ChabotCollege.edu ENGR-25_Prob_2-24_Solution.ppt 8 Bruce Mayer, PE ENGR/MTH/PHYS25: Computational Methods Summary to This Point What we KNOW By Thévenin Analysis of the Driving Ckt we determined V S & R S Note that V S & R S are FIXED and beyond our Control as Speaker Designers The Speaker Designer CAN, however control the Load Resistance, R L Thus Our Goal Find R L such the Driving Ckt Operates at the Highest Efficiency; i.e., we seek R L that will MAXIMIZE Driver → Load Power Transfer
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BMayer@ChabotCollege.edu ENGR-25_Prob_2-24_Solution.ppt 9 Bruce Mayer, PE ENGR/MTH/PHYS25: Computational Methods Analytical Game Plan Goal Find R L to Maximize P L (R L ) From the Physics we Know
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BMayer@ChabotCollege.edu ENGR-25_Prob_2-24_Solution.ppt 10 Bruce Mayer, PE ENGR/MTH/PHYS25: Computational Methods The MATLAB Problem RS = 10Ω, 15Ω, 20Ω, 25Ω RL = 10Ω, 15Ω, 20Ω, 25Ω, 30Ω And Define Transfer Ratio, r Then So to Maximize P L need to Maximize r
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BMayer@ChabotCollege.edu ENGR-25_Prob_2-24_Solution.ppt 11 Bruce Mayer, PE ENGR/MTH/PHYS25: Computational Methods MATLAB Game Plan Concept Test ALL possible Resistor Combinations then Check for Best Because we have a small number of allowable values for RS and RL, the most direct way to choose RL is to compute the values of r for each combination of RS and RL. Since there are four possible values of RS and five values of RL, there are 4(5) = 20 combinations.
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BMayer@ChabotCollege.edu ENGR-25_Prob_2-24_Solution.ppt 12 Bruce Mayer, PE ENGR/MTH/PHYS25: Computational Methods MATLAB Plan (2) We can use an array operation in MATLAB to compute r for each of these combinations by defining two 5 × 4 2D-Arrays R_L and R_S. The five rows of R_L contain the five values of RL, and its four columns are identical. The four columns of R_S contain the four values of RS, and its five rows are identical.
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BMayer@ChabotCollege.edu ENGR-25_Prob_2-24_Solution.ppt 13 Bruce Mayer, PE ENGR/MTH/PHYS25: Computational Methods MATLAB Plan (3) The Arrays we Need These Arrays MUST have the same size so that we can perform element-by- element operations with them.
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BMayer@ChabotCollege.edu ENGR-25_Prob_2-24_Solution.ppt 14 Bruce Mayer, PE ENGR/MTH/PHYS25: Computational Methods The MATLAB Code % Bruce Mayer, PE % ENGR22 * 20Jan07 * Rev. 13Sep08 % Prob 2.24 * file Demo_Prob2_24_0809.m % % Since all COLUMNS in RL are the same, Define one Col and Replicate in Row Vector % Define RL col a = [10;15;20;25;30]; % Make Array R_L by using a in 4-element Row Vector R_L = [a,a,a,a] % % Since all ROWS in RS are the same, Define one Row and Replicate in Col Vector % Define RS row b = [10,15,20,25]; % Make Array R_S by using a in 5-element Col Vector R_S=[b;b;b;b;b] % % Use Element-by-Element Operations to Calc r % First Sum RS & RL for the 20 combos Rsum = R_S+R_L % Now sq the 20 sums RsumSq = Rsum.^2 % need "dot" as this is element-by-element % Finally Divide RL by SQd sums r = R_L./RsumSq % % Use the max(A) command to find the max value in each COL, and the ROW in in Which the max Values Occurs [max_ratio, row] = max(r)
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BMayer@ChabotCollege.edu ENGR-25_Prob_2-24_Solution.ppt 15 Bruce Mayer, PE ENGR/MTH/PHYS25: Computational Methods The.m-File OutPut R_L = 10 15 20 25 30 R_S = 10 15 20 25 10 15 20 25 10 15 20 25 10 15 20 25 10 15 20 25 Rsum = 20 25 30 35 25 30 35 40 30 35 40 45 35 40 45 50 40 45 50 55 r = 0.0250 0.0160 0.0111 0.0082 0.0240 0.0167 0.0122 0.0094 0.0222 0.0163 0.0125 0.0099 0.0204 0.0156 0.0123 0.0100 0.0187 0.0148 0.0120 0.0099 max_ratio = 0.0250 0.0167 0.0125 0.0100 row = 1 2 3 4 RS = 10RS = 15RS = 20RS = 25 RL = 10 RL = 15 RL = 20 RL = 25 RL = 30
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BMayer@ChabotCollege.edu ENGR-25_Prob_2-24_Solution.ppt 16 Bruce Mayer, PE ENGR/MTH/PHYS25: Computational Methods
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BMayer@ChabotCollege.edu ENGR-25_Prob_2-24_Solution.ppt 17 Bruce Mayer, PE ENGR/MTH/PHYS25: Computational Methods
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BMayer@ChabotCollege.edu ENGR-25_Prob_2-24_Solution.ppt 18 Bruce Mayer, PE ENGR/MTH/PHYS25: Computational Methods 3 3
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BMayer@ChabotCollege.edu ENGR-25_Prob_2-24_Solution.ppt 19 Bruce Mayer, PE ENGR/MTH/PHYS25: Computational Methods
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BMayer@ChabotCollege.edu ENGR-25_Prob_2-24_Solution.ppt 20 Bruce Mayer, PE ENGR/MTH/PHYS25: Computational Methods
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