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System of Particles: Center-of-Mass
The center-of-mass of a system of particles is the point that moves as though (1) all of the systems mass were concentrated there and (2) all external forces were applied there. Location of the Center-of-Mass: (total mass of the system) Center-of-Mass Velocity of the Center-of-Mass: (total momentum of the system) Acceleration of the Center-of-Mass: (net force acting on the system of particles) R. Field 10/10/ University of Florida PHY 2053
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Center-of-Mass: Superposition
If object A has mass MA and its center-of-mass is located at and object B has mass MB and its center-of-mass is located at then the center of mass of the system A+B is located at Example: What is the x-coordinate of the center-of-mass of the circular disk of radius 2R with a circular hole of radius R as shown in the figure? Assume the disk has a uniform mass density r. Answer: R/3 Let object A+B be a uniform disk of radius 2R, height h, and center at x=y=0. Let object A be the disk with the hole in it. Let object B be a uniform disk with radius R, height h, and center at y=0, x=-R. R. Field 10/10/ University of Florida PHY 2053
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Center-of-Mass: Example
Fall 2011 Exam 2 Problem 22: z y x The figure shows a cubical box with each side consisting of a uniform metal plate of negligible thickness. Each of the four sides have mass, M, and the bottom has mass Mbottom. The box is open at the top (at z = L) and has edge length L. If the the z-coordinate of the center-of-mass is at zCM = L/3, what is Mbottom? Answer: 2M % Right: 24% R. Field 10/10/ University of Florida PHY 2053
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Collisions in 1 Dimension: Elastic
Elastic Collision: An elastic collision is one in which the kinetic energy is conserved (i.e. the initial total kinetic energy is equal to the final total kinetic energy). If a projectile with mass M1 and speed v1 traveling to the right along the x-axis collides with a target particle at rest with mass M2, what are the velocities of the two particles after they undergo an elastic collision? (momentum conservation) (1) Note: a2 - b2 = (a-b)(a+b) (energy conservation) (2) Divide eq. 2 by eq. 1 and multiply by 2 (4) (3) Multiply eq. 3 by M1 and add it to eq. 1 Insert eq. 5 into eq.4 (5) R. Field 10/10/ University of Florida PHY 2053
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1d Collisions: Completely Inelastic
Completely Inelastic Collision (Lab Frame): A projectile with mass M1 and speed v1 traveling to the right along the x-axis collides with a target particle at rest with mass M2. If the two particles stick together to form a single particle of mass M1+M2, what is its velocity? What is the velocity of the center-of-mass of the two particles system before the collision? What is the change in the kinetic energy before and after the collision? (momentum conservation) Completely Inelastic Collision (CM Frame): In the CM frame the initial two particles have equal and opposite momentum. They stick together and are at rest with zero final momentum and zero final kinetic energy. This corresponds to the maximal loss of kinetic energy consistent with momentum conservation. R. Field 10/10/ University of Florida PHY 2053
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