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Published byMilo Blake Modified over 9 years ago
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Warm–up #1
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Warm–up #1 Solutions Isolate Abs Val Check in original!! NOT a soln!
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Abs Val either (+) or zero But, NEVER (–) NO SOLUTION Warm–up #1 Solutions
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Homework Log Thurs 10/1 Lesson 2 – 1 Learning Objective: To solve absolute values & solve for variables Hw: #202 Pg.102 #33 – 59 odd, 67, 69
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10/1/15 Lesson 2 – 1 Absolute Values & Formulas Day 2 Advanced Math/Trig
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Learning Objective To solve absolute value equations To solve for variables
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Solving for a Variable
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Absolute Value Equations
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Amount of Loan A: amt owed on loan P: principal r: interest rate t: time % decimal
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Amount of Loan interest = 11% r =.11 t = 3 A = 4522 P = ? 4. A sum of $ is borrowed at 11% per year & amt required to pay off loan after 3 years is $4522. How much $ is borrowed? principal A = P(1 + rt) 4522 = P(1+ (.11)(3)) 4522 = P(1.33) P = $ 3400
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Discount Rate A: maturity value P: proceeds r: discount rate n: years discounted % decimal
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Discount Rate n = 2 P = 889.20 rate = 11% r =.11 A = ? 5. Find the maturity value of a note discounted for 2 years if the proceeds are $889.20 and discount rate is 11%. P = A(1 – rn) 889.20 = A(1 – (.11)(2)) 889.20 = A(.78) A = $ 1140
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Discount Rate n = 5 P = 225 A = 1500 r = ? 6. The maturity value of a note discounted for 5 years is $1500 with the proceeds of $225. Find the discount rate P = A(1 – rn) 225 = 1500(1 – (r)(5)) 225 = 1500 – 7500r –1275 = –7500r 0.17 = rr = 17%
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Absolute Value Equations
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Check for Extraneous Solutions
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Solving an Absolute Value Equation
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Ticket Out the Door
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Homework #202 Pg. 102 #33 – 59 odd, 67, 69
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