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Warm–up #1. Warm–up #1 Solutions Isolate Abs Val Check in original!! NOT a soln!

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Presentation on theme: "Warm–up #1. Warm–up #1 Solutions Isolate Abs Val Check in original!! NOT a soln!"— Presentation transcript:

1 Warm–up #1

2 Warm–up #1 Solutions Isolate Abs Val Check in original!! NOT a soln!

3 Abs Val either (+) or zero But, NEVER (–) NO SOLUTION Warm–up #1 Solutions

4 Homework Log Thurs 10/1 Lesson 2 – 1 Learning Objective: To solve absolute values & solve for variables Hw: #202 Pg.102 #33 – 59 odd, 67, 69

5 10/1/15 Lesson 2 – 1 Absolute Values & Formulas Day 2 Advanced Math/Trig

6 Learning Objective To solve absolute value equations To solve for variables

7 Solving for a Variable

8

9 Absolute Value Equations

10

11 Amount of Loan A: amt owed on loan P: principal r: interest rate t: time %  decimal

12 Amount of Loan interest = 11%  r =.11 t = 3 A = 4522 P = ? 4. A sum of $ is borrowed at 11% per year & amt required to pay off loan after 3 years is $4522. How much $ is borrowed? principal A = P(1 + rt) 4522 = P(1+ (.11)(3)) 4522 = P(1.33) P = $ 3400

13 Discount Rate A: maturity value P: proceeds r: discount rate n: years discounted %  decimal

14 Discount Rate n = 2 P = 889.20 rate = 11%  r =.11 A = ? 5. Find the maturity value of a note discounted for 2 years if the proceeds are $889.20 and discount rate is 11%. P = A(1 – rn) 889.20 = A(1 – (.11)(2)) 889.20 = A(.78) A = $ 1140

15 Discount Rate n = 5 P = 225 A = 1500 r = ? 6. The maturity value of a note discounted for 5 years is $1500 with the proceeds of $225. Find the discount rate P = A(1 – rn) 225 = 1500(1 – (r)(5)) 225 = 1500 – 7500r –1275 = –7500r 0.17 = rr = 17%

16 Absolute Value Equations

17 Check for Extraneous Solutions

18 Solving an Absolute Value Equation

19 Ticket Out the Door

20 Homework #202 Pg. 102 #33 – 59 odd, 67, 69


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