1. PMIT-6102 Advanced Database Systems By- Jesmin Akhter Assistant Professor, IIT, Jahangirnagar University

2. Lecture 04 Relational Database Design Normalization

3. Outline Overview of Relational DBMS  Normalization

4. Example 1: Determine NF ISBN  Title ISBN  Publisher Publisher  Address All attributes are directly or indirectly determined by the primary key; therefore, the relation is at least in 1 NF

5. Example 1: Determine NF ISBN  Title ISBN  Publisher Publisher  Address The relation is at least in 1NF. There is no COMPOSITE primary key, therefore there can’t be partial dependencies. Therefore, the relation is at least in 2NF

6. Example 1: Determine NF ISBN  Title ISBN  Publisher Publisher  Address Publisher is a non-key attribute, and it determines Address, another non-key attribute. Therefore, there is a transitive dependency, which means that the relation is NOT in 3 NF.

7. Example 1: Determine NF ISBN  Title ISBN  Publisher Publisher  Address We know that the relation is at least in 2NF, and it is not in 3 NF. Therefore, we conclude that the relation is in 2NF.

8. Example 1: Determine NF ISBN  Title ISBN  Publisher Publisher  Address In your solution you will write the following justification: 1) No M/V attributes, therefore at least 1NF 2) No partial dependencies, therefore at least 2NF 3) There is a transitive dependency (Publisher  Address), therefore, not 3NF Conclusion: The relation is in 2NF

9. Product_ID  Description Example 2: Determine NF All attributes are directly or indirectly determined by the primary key; therefore, the relation is at least in 1 NF

10. Product_ID  Description Example 2: Determine NF The relation is at least in 1NF. There is a COMPOSITE Primary Key (PK) (Order_No, Product_ID), therefore there can be partial dependencies. Product_ID, which is a part of PK, determines Description; hence, there is a partial dependency. Therefore, the relation is not 2NF. No sense to check for transitive dependencies!

11. Product_ID  Description Example 2: Determine NF We know that the relation is at least in 1NF, and it is not in 2 NF. Therefore, we conclude that the relation is in 1 NF.

12. Product_ID  Description Example 2: Determine NF In your solution you will write the following justification: 1) No M/V attributes, therefore at least 1NF 2) There is a partial dependency (Product_ID  Description), therefore not in 2NF Conclusion: The relation is in 1NF

13. Example 3: Determine NF Part_ID  Description Part_ID  Price Part_ID, Comp_ID  No Comp_ID and No are not determined by the primary key; therefore, the relation is NOT in 1 NF. No sense in looking at partial or transitive dependencies. Part_IDDescrPriceComp_IDNo

14. Example 3: Determine NF Part_ID  Description Part_ID  Price Part_ID, Comp_ID  No In your solution you will write the following justification: 1) There are M/V attributes; therefore, not 1NF Conclusion: The relation is not normalized.

15. Bringing a Relation to 1NF

16. Option 1: Make a determinant of the repeating group (or the multivalued attribute) a part of the primary key. Composite Primary Key

17. Bringing a Relation to 1NF Option 2: Remove the entire repeating group from the relation. Create another relation which would contain all the attributes of the repeating group, plus the primary key from the first relation. In this new relation, the primary key from the original relation and the determinant of the repeating group will comprise a primary key.

18. Bringing a Relation to 1NF

19. Bringing a Relation to 2NF Composite Primary Key

20. Bringing a Relation to 2NF Composite Primary Key Goal: Remove Partial Dependencies Partial Dependencies

21. Bringing a Relation to 2NF Remove attributes that are dependent from the part but not the whole of the primary key from the original relation. For each partial dependency, create a new relation, with the corresponding part of the primary key from the original as the primary key.

22. Bringing a Relation to 2NF

23. Bringing a Relation to 3NF Goal: Get rid of transitive dependencies. Transitive Dependency

24. Bringing a Relation to 3NF Remove the attributes, which are dependent on a non-key attribute, from the original relation. For each transitive dependency, create a new relation with the non-key attribute which is a determinant in the transitive dependency as a primary key, and the dependent non-key attribute as a dependent.

25. Bringing a Relation to 3NF

26. Unnormalised Normal Form (UNF) ORDER (order-no, order-date, cust-no, cust-name, cust-add, (prod-no, prod-desc, unit-price, ord-qty, line-total)*, order-total

27. First Normal Form (1NF) Definition: A relation is in 1NF if, and only if, all its underlying attributes contain atomic values only. Steps from UNF to 1NF:  Remove the outermost repeating group (and any nested repeated groups it may contain) and create a new relation to contain it.  Add to this relation a copy of the PK of the relation immediately enclosing it.  Name the new entity (appending the number 1 to indicate 1NF)  Determine the PK of the new entity  Repeat steps until no more repeating groups. Remove repeating groups into a new relation A repeating group is shown by a pair of brackets within the relational schema. ORDER (order-no, order-date, cust-no, cust-name, cust-add, (prod-no, prod-desc, unit-price, ord-qty, line-total)*, order-total

28. Example - UNF to 1NF ORDER (order-no, order-date, cust-no, cust-name, cust-add, (prod-no, prod-desc, unit-price, ord-qty, line-total)*, order-total 1. Remove the outermost repeating group (and any nested repeated groups it may contain) and create a new relation to contain it. (rename original to indicate 1NF) ORDER-1 (order-no, order-date, cust-no, cust-name, cust-add, order-total (prod-no, prod-desc, unit-price, ord-qty, line-total) 2. Add to this relation a copy of the PK of the relation immediately enclosing it. ORDER-1 (order-no, order-date, cust-no, cust-name, cust-add, order-total (order-no, prod-no, prod-desc, unit-price, ord-qty, line-total) 3. Name the new entity (appending the number 1 to indicate 1NF) ORDER-LINE-1 (order-no, prod-no, prod-desc, unit-price, ord-qty, line-total) 4. Determine the PK of the new entity ORDER-LINE-1 (order-no, prod-no, prod-desc, unit-price, ord-qty, line-total)

29. Second Normal Form (2NF) Definition: A relation is in 2NF if, and only if, it is in 1NF and every non-key attribute is fully dependent on the primary key. Steps from 1NF to 2NF:  Remove the offending attributes that are only partially functionally dependent on the composite key, and place them in a new relation.  Add to this relation a copy of the attribute(s) which are the determinants of these offending attributes. These will automatically become the primary key of this new relation.  Name the new entity (appending the number 2 to indicate 2NF)  Rename the original entity (ending with a 2 to indicate 2NF) Remove partial functional dependencies into a new relation

30. Example - 1NF to 2NF ORDER-LINE-1 (order-no, prod-no, prod-desc, unit-price, ord-qty, line-total) 1. Remove the offending attributes that are only partially functionally dependent on the composite key, and place them in a new relation. ORDER-LINE-1 (order-no, prod-no, ord-qty, line-total) (prod-desc, unit-price) 2. Add to this relation a copy of the attribute(s) which determines these offending attributes. These will automatically become the primary key of this new relation.. (prod-no, prod-desc, unit-price) ORDER-LINE-1 (order-no, prod-no, ord-qty, line-total) 3. Name the new entity (appending the number 2 to indicate 2NF) PRODUCT-2 (prod-no, prod-desc, unit-price) 4. Rename the original entity (ending with a 2 to indicate 2NF) ORDER-LINE-2 (order-no, prod-no, ord-qty, line-total)

31. Third Normal Form (3NF) Definition: A relation is in 3NF if, and only if, it is in 2NF and every non-key attribute is non-transitively dependent on the primary key. Steps from 2NF to 3NF:  Remove the offending attributes that are transitively dependent on non-key attribute(s), and place them in a new relation.  Add to this relation a copy of the attribute(s) which are the determinants of these offending attributes. These will automatically become the primary key of this new relation.  Name the new entity (appending the number 3 to indicate 3NF)  Rename the original entity (ending with a 3 to indicate 3NF) Remove transitive dependencies into a new relation

32. Example - 2NF to 3NF ORDER-2 (order-no, order-date, cust-no, cust-name, cust-add, order-total 1. Remove the offending attributes that are transitively dependent on non-key attributes, and place them in a new relation. (cust-name, cust-add ) ORDER-2 (order-no, order-date, cust-no, order-total 2. Add to this relation a copy of the attribute(s) which determines these offending attributes. These will automatically become the primary key of this new relation.. (cust-no, cust-name, cust-add ) ORDER-2 (order-no, order-date, cust-no, order-total 3. Name the new entity (appending the number 3 to indicate 3NF) CUSTOMER-3 (cust-no, cust-name, cust-add ) 4. Rename the original entity (ending with a 3 to indicate 3NF) ORDER-3 (order-no, order-date, cust-no, order-total

33. Example - Relations in 3NF CUSTOMER-3 (cust-no, cust-name, cust-add ) ORDER-3 (order-no, order-date, cust-no, order-total ORDER-LINE-2 (order-no, prod-no, ord-qty, line-total) PRODUCT-2 (prod-no, prod-desc, unit-price) CUSTOMER ORDER ORDER-LINE PRODUCT places placed by contains part of shows belongs to cust-no order-no prod-no order-no, prod-no

34. Case Study on Normalization Consider the table EMP_DEPT_PROJ And the following dependencies which exist in the above table: Slide 34

35. Steps to Normalize the database D Thus we will have 3 tables Slide 35

36. Step 2  Let us now identify the transitive dependency and remove it. Slide 36 Steps to Normalize the database

37. Step 3:  Let us now identify the non key determinants and remove them.  Thus we will have 5 tables Slide 37 Steps to Normalize the database

38. BCNF Slide 38

39. Slide 39 BCNF

40. Slide 40 BCNF

41. Slide 41 BCNF

42. Thank You