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Chap. 11 Graph Theory and Applications 1
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Directed Graph 2
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(Undirected) Graph 3
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Vertex and Edge Sets 4
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Walk 5
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Closed (Open) Walk 6
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Trail, Path, Circuit, and Cycle 7
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Comparison of Walk, Trail, Path, Circuit, and Cycle 8
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Theorem 11.1 Observation: 9
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Theorem 11.1 1.It suffices to show from a to b, the shortest trail is the shortest path. 2. Let be the shortest trail from a to b. 3. 4.4. 10
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Connected Graph connected graphdisconnected graph 11
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Multigraph 12
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Subgraph 13
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Spanning Subgraph 14
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Induced Subgraph 15
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Which of the following is an induced subgraph of G? O Induced Subgraph O X 16
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Components of a Graph 12 connected sugraph 17
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G-vG-v 18
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G-eG-e 19
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Complete Graph 20
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Complement of a Graph 21
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Isomorphic Graphs 22
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Isomorphic Graphs Which of the following function define a graph isomorphism for the graphs shown below? O X 23
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Isomorphic Graphs 24
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Isomorphic Graphs Are the following two graphs isomorphic? In (a), a and d each adjacent to two other vertices. In (b), u, x, and z each adjacent to two other vertices. X 25
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Vertex Degree 26
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Theorem 11.2 27
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Corollary 11.1 28
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a b c d 30
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Euler Circuit and Euler Trail 31
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Theorem 11.3 ( ⇒) 1. 2. 3. 4. 5. 6. 7. 32
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Theorem 11.3 8. 9. 33
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Theorem 11.3 ( ⇐) 1. 2. 3. 34
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Theorem 11.3 4. 5. 6. 7. 8. 35
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Theorem 11.3 9. 10. 11. 12. 13. 14. 36
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Corollary 11.2 ( ⇐) 1. 2. 3. 4. ( ⇒) The proof of only if part is similar to that of Theorem 11.3 and omitted. 37
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Incoming and Outgoing Degrees 2 38
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Theorem 11.4 The proof is similar to that of Theorem 11.3 and omitted. 39
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Planar Graph Which of the following is a planar graph? OO 40
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Euler’s Theorem v = e = r = v – e + r = 2 7 8 3 41
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Euler’s Theorem Proof. 1. Use induction on v (number of vertices). 2. Basis (v = 1): –G is a “bouquet” of loops, each a closed curve in the embedding. –If e = 0, then r = 1, and the formula holds. –Each added loop passes through a region and cuts it into 2 regions. This augments the edge count and the region count each by 1. Thus the formula holds when v = 1 for any number of edges. 42
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Euler’s Theorem 3. Induction step (v>1): –There exists an edge e that is not a loop because G is connected. –Obtain a graph G’ with v’ vertices, e’ edges, and r’ regions by contracting e. –Clearly, v’=v–1, e’=e–1, and r’=r. –v’– e’+ r’ = 2. –Therefore, v-e+r=2. e (induction hypothesis) 43
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Corollary 11.3 1. It suffices to consider connected graphs; otherwise, we could add edges. 2. If v 3, every region contains at least three edges ( L(R i ) 3r). 3. 2e= L(R i ), implying 2e 3r. 4. By Euler’s Theorem, v–e+r=2, implying e≤ 3v– 6. If also G is triangle-free, then e ≤ 2v–4. ( L(R i ) 4r) (2e 4r) (e≤ 2v–4) If G is a simple planar graph with at least three vertices, then e≤3v–6. (A simple graph is not a multigraph and does not contain any loop.) 44
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Bipartite Graph 45
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Nonplanarity of K 5 and K 3,3 K 5 (e = 10, n = 5) K 3,3 (e = 9, n = 6) These graphs have too many edges to be planar. –For K 5, we have e = 10>9 = 3n-6. –Since K 3,3 is triangle-free, we have e = 9>8 = 2n-4. 46
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Subdivision of a Graph 47
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Subdivision of a Graph 48
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Hamilton Cycle 51
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Hamilton Cycle Does the following graph contain a hamiltion cycle? X 52
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Theorem 11.8 1. 2. 3. 4. 53
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Theorem 11.8 5. 6. 7. 8. 9. 10. 11. 12. 13. 54
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Theorem 11.8 14. 15. 16. 17. 18. 19. 55
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Theorem 11.8 17. 18. 19. 20. 56
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Theorem 11.9 1. 2. 3. 4. 5. 57
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Theorem 11.9 6. 7. 8. 9. 10. 11. 58
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Proper Coloring and Chromatic Number 59
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Counting Proper Colors 1. 2. 3. 4. 60
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Theorem 11.10 1. 2. 3. 4. 5. 6. 62
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Example 11.36 63
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Example 11.37 64
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