Download presentation
Presentation is loading. Please wait.
Published byPrimrose Stanley Modified over 9 years ago
1
1968-70 Georges Charpak develops the multiwire proportional chamber 1992 Charpak receives the Nobel Prize in Physics for his invention
3
100 MHz 50 MHz 0. 0.4 0.8 1.2 1.6 2.0 2.4 2.8 800 600 400 200 0 1000 800 600 400 200 0
4
20 m dia 2 mm spacing argon-isobutane spatial resolutions < 1mm possible
7
DO
10
DØ 5500 tons 120,000 digitized readout channels
11
– 2T super conducting solenoid – disk/barrel silicon detector – 8 layers of scintillating fiber tracker – preshower detectors Shielding New Solenoid & Tracking: Silicon, SciFi, Preshowers + New Electronics, Trigger, DAQ Forward Scintillator Forward Mini- drift chambers
16
The Detector in various stages of assembly 5500 tons 120,000 digitized readout channels
21
Fermilab, Batavia, Illinois CERN, Geneva, Switzerland Protons Anti-protons
22
For “free” particles (unbounded in the “continuum”) the solutions to Schrödinger’s equation with no potential Sorry!…this V is a volume appearing for normalization
23
q q pipi pipi q = k i k f =(p i -p f )/ħ momentum transfer the momentum given up (lost) by the scattered particle
24
We’ve found (your homework!) the time evolution of a state from some initial (time, t 0 ) unperturbed state can in principal be described using: complete commuting set of observables, e.g. E n, etc… Where the | t are eigenstates satisfying Schrödingers equation: Since the set is “complete” we can even express the final state of a system in terms of the complete representation of the initial, unperturbed eigenstates | t 0 .
25
give the probability amplitudes (which we’ll relate to the rates) of the transitions | t 0 | ″ t during the interval ( t 0, t ). You’ve also shown the “matrix elements” of this operator (the “overlap” of initial and potential “final” states) to use this idea we need an expression representing U !
26
HI(t)HI(t)HI(t)HI(t) Operator on both sides, by the Hamiltonian of the perturbing interaction: Then integrate over (t 0,t) HI(t′)HI(t′) HI(t′)HI(t′) t0t0 t dt′ t′t′ t0t0 t t′t′ t0t0 t t't' t 0 t
27
Which notice has lead us to an iterative equation for U I U U I U(t t o ) =U U
28
If at time t 0 =0 the system is in a definite energy eigenstate of H 0 ( intitial state is, for example, a well-defined beam ) H o |E n,t 0 > = E n |E n,t o > then to first order U(t t o )|E n,t 0 > = and the transition probability ( for f 0 ) Note: probability to remain unchanged = 1 – P !!
29
recall: ( homework !) H 0 † = H 0 (Hermitian!) where each operator acts separately on: † So:
30
If we simplify the action (as we do impulse in momentum problems) to an average, effective potential V(t) during its action from (t 0,t) ≈ factor out
31
E =2 h / t
32
The probability of a transition to a particular final state |E f t> The total transition probability: If ~ constant over the narrowly allowed E
33
for scattering, the final state particles are free, & actually in the continuum n=1 n=2 n=3 n=n=
34
With the change of variables:
35
Notice the total transition probability t and the transition rate
36
n=1 n=2 n=3 n=n= E dN/dE Does the density of states vary through the continuum?
37
vxvx vyvy vzvz Classically, for free particles E = ½ mv 2 = ½ m(v x 2 + v y 2 + v z 2 ) Notice for any fixed E, m this defines a sphere of velocity points all which give the same kinetic energy. The number of “states” accessible by that energy are within the infinitesimal volume (a shell a thickness dv on that sphere). dV = 4 v 2 dv
Similar presentations
© 2025 SlidePlayer.com. Inc.
All rights reserved.