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1968-70 Georges Charpak develops the multiwire proportional chamber 1992 Charpak receives the Nobel Prize in Physics for his invention.

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Presentation on theme: "1968-70 Georges Charpak develops the multiwire proportional chamber 1992 Charpak receives the Nobel Prize in Physics for his invention."— Presentation transcript:

1 1968-70 Georges Charpak develops the multiwire proportional chamber 1992 Charpak receives the Nobel Prize in Physics for his invention

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3 100 MHz 50 MHz 0. 0.4 0.8 1.2 1.6 2.0 2.4 2.8 800 600 400 200 0 1000 800 600 400 200 0

4 20  m dia 2 mm spacing argon-isobutane spatial resolutions < 1mm possible

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7 DO

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10 DØ 5500 tons 120,000 digitized readout channels

11 – 2T super conducting solenoid – disk/barrel silicon detector – 8 layers of scintillating fiber tracker – preshower detectors Shielding New Solenoid & Tracking: Silicon, SciFi, Preshowers + New Electronics, Trigger, DAQ Forward Scintillator Forward Mini- drift chambers

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16 The Detector in various stages of assembly 5500 tons 120,000 digitized readout channels

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21 Fermilab, Batavia, Illinois CERN, Geneva, Switzerland Protons Anti-protons

22 For “free” particles (unbounded in the “continuum”) the solutions to Schrödinger’s equation with no potential Sorry!…this V is a volume appearing for normalization

23 q q pipi pipi q = k i  k f =(p i -p f )/ħ momentum transfer the momentum given up (lost) by the scattered particle

24 We’ve found (your homework!) the time evolution of a state from some initial (time, t 0 ) unperturbed state can in principal be described using: complete commuting set of observables, e.g. E n, etc… Where the |  t  are eigenstates satisfying Schrödingers equation: Since the set is “complete” we can even express the final state of a system in terms of the complete representation of the initial, unperturbed eigenstates |  t 0 .

25 give the probability amplitudes (which we’ll relate to the rates) of the transitions |  t 0  |  ″ t  during the interval ( t 0, t ). You’ve also shown the “matrix elements” of this operator (the “overlap” of initial and potential “final” states) to use this idea we need an expression representing U !

26 HI(t)HI(t)HI(t)HI(t) Operator on both sides, by the Hamiltonian of the perturbing interaction: Then integrate over (t 0,t) HI(t′)HI(t′) HI(t′)HI(t′)  t0t0 t dt′ t′t′  t0t0 t t′t′  t0t0 t t't'  t 0 t

27 Which notice has lead us to an iterative equation for U I U U I U(t t o ) =U U

28 If at time t 0 =0 the system is in a definite energy eigenstate of H 0 ( intitial state is, for example, a well-defined beam ) H o |E n,t 0 > = E n |E n,t o > then to first order U(t t o )|E n,t 0 > = and the transition probability ( for f  0 ) Note: probability to remain unchanged = 1 – P !!

29 recall: ( homework !) H 0 † = H 0 (Hermitian!) where each operator acts separately on: † So:

30 If we simplify the action (as we do impulse in momentum problems) to an average, effective potential V(t) during its action from (t 0,t) ≈ factor out

31  E =2 h /  t

32 The probability of a transition to a particular final state |E f t> The total transition probability: If ~ constant over the narrowly allowed  E

33 for scattering, the final state particles are free, & actually in the continuum n=1 n=2 n=3 n=n= 

34 With the change of variables:  

35 Notice the total transition probability  t and the transition rate

36 n=1 n=2 n=3 n=n= E dN/dE Does the density of states vary through the continuum?

37 vxvx vyvy vzvz Classically, for free particles E = ½ mv 2 = ½ m(v x 2 + v y 2 + v z 2 ) Notice for any fixed E, m this defines a sphere of velocity points all which give the same kinetic energy. The number of “states” accessible by that energy are within the infinitesimal volume (a shell a thickness dv on that sphere). dV = 4  v 2 dv


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