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Time-independent Schrodinger eqn QM Ch.2, Physical Systems, 12.Jan.2003 EJZ Assume the potential V(x) does not change in time. Use * separation of variables and * boundary conditions to solve for . Once you know , you can find any expectation value!
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Outline: “Derive” Schroedinger Eqn (SE) Stationary states ML1 by Don and Jason R, Problem #2.2 Infinite square well Harmonic oscillator, Problem #2.13 ML2 by Jason Wall and Andy, Problem #2.14 Free particle and finite square well Summary
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Schroedinger Equation
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Stationary States - introduction If evolving wavefunction (x,t) = (x) f(t) can be separated, then the time-dependent term satisfies (ML1 will show - class solve for f) Separable solutions are stationary states...
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Separable solutions: (1) are stationary states, because * probability density is independent of time [2.7] * therefore, expectation values do not change (2) have definite total energy, since the Hamiltonian is sharply localized: [2.13] (3) i = eigenfunctions corresponding to each allowed energy eigenvalue E i. General solution to SE is [2.14]
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ML1: Stationary states are separable Guess that SE has separable solutions (x,t) = (x) f(t) sub into SE=Schrodinger Eqn Divide by f: LHS(t) = RHS(x) = constant=E. Now solve each side: You already found solution to LHS: f(t)=_________ RHS solution depends on the form of the potential V(x).
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ML1: Problem 2.2, p.24
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Now solve for (x) for various V(x) Strategy: * draw a diagram * write down boundary conditions (BC) * think about what form of (x) will fit the potential * find the wavenumbers k n =2 * find the allowed energies E n * sub k into (x) and normalize to find the amplitude A * Now you know everything about a QM system in this potential, and you can calculate for any expectation value
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Square well: V(0<x<a) = 0, V= outside What is probability of finding particle outside? Inside: SE becomes * Solve this simple diffeq, using E=p 2 /2m, * (x) =A sin kx + B cos kx: apply BC to find A and B * Draw wavefunctions, find wavenumbers: k n a= n * find the allowed energies: * sub k into (x) and normalize: * Finally, the wavefunction is
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Square well: homework 2.4: Repeat the process above, but center the infinite square well of width a about the point x=0. Preview: discuss similarities and differences
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Ex: Harmonic oscillator: V(x) =1/2 kx 2 Tipler’s approach: Verify that 0 =A 0 e -ax^2 is a solution Analytic approach (2.3.2): rewrite SE diffeq and solve Algebraic method (2.3.1): ladder operators
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HO: Tipler’s approach: Verify solution to SE:
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HO: Tipler’s approach..
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HO analytically: solve the diffeq directly Rewrite SE using * At large ~x, has solutions * Guess series solution h( ) * Consider normalization and BC to find that h n =a n H n ( ) where H n ( ) are Hermite polynomials * The ground state solution 0 is the same as Tipler’s * Higher states can be constructed with ladder operators
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HO algebraically: use a ± to get n Ladder operators a ± generate higher-energy wave- functions from the ground state 0. Work through Section 2.3.1 together Result: Practice on Problem 2.13
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Harmonic oscillator: Prob.2.13 Worksheet
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ML2: HO, Prob. 2.14 Worksheet
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Ex: Free particle: V=0 Looks easy, but we need Fourier series If it has a definite energy, it isn’t normalizable! No stationary states for free particles Wave function’s v g = 2 v p, consistent with classical particle: check this.
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Finite square well: V=0 outside, -V 0 inside BC: NOT zero at edges, so wavefunction can spill out of potential Wide deep well has many, but finite, states Shallow, narrow well has at least one bound state
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Summary: Time-independent Schrodinger equation has stationary states (x) k, (x), and E depend on V(x) (shape & BC) wavefunctions oscillate as e i t wavefunctions can spill out of potential wells and tunnel through barriers
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