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X squared asks x cubed if he is a religious variable I do believe in higher powers, if that’s what you mean. student notes MADE for 2-2 and 2-3 Copyright © by Houghton Mifflin Company, Inc. All rights reserved. 1
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Section 2.2 Polynomial Functions of Higher Degree
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Warm up - Graph this business Copyright © by Houghton Mifflin Company, Inc. All rights reserved. 3 Psych!
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Copyright © by Houghton Mifflin Company, Inc. All rights reserved. 4 Polynomial Function A polynomial function is a function of the form where n is a nonnegative integer and each a i (i = 0, , n) is a real number. The polynomial function has a leading coefficient a n and degree n. Examples: Find the leading coefficient and degree of each polynomial function. Polynomial FunctionLeading Coefficient Degree -2 5 1 3 14 0
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Copyright © by Houghton Mifflin Company, Inc. All rights reserved. 5 Graphs of Polynomial Functions Graphs of polynomial functions are continuous. That is, they have no breaks, holes, or gaps. Polynomial functions are also smooth with rounded turns. Graphs with points or cusps are not graphs of polynomial functions. x y x y continuousnot continuouscontinuous smoothnot smooth polynomialnot polynomial x y f (x) = x 3 – 5x 2 + 4x + 4
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Copyright © by Houghton Mifflin Company, Inc. All rights reserved. 6 Power Functions Polynomial functions of the form f (x) = x n, n 1 are called power functions. If n is even, their graphs resemble the graph of f (x) = x 2. If n is odd, their graphs resemble the graph of f (x) = x 3. x y x y f (x) = x 2 f (x) = x 5 f (x) = x 4 f (x) = x 3 What do you think even functions look like? What do you think odd functions look like?
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Copyright © by Houghton Mifflin Company, Inc. All rights reserved. 7 Example: Graph of f(x) = – (x + 2) 4 Ex 1: Sketch the graph of f (x) = – (x + 2) 4. Reflect the graph of y = x 4 in the x-axis. Then shift the graph two units to the left. x y y = x 4 y = – x 4 f (x) = – (x + 2) 4
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Copyright © by Houghton Mifflin Company, Inc. All rights reserved. 8 Leading Coefficient Test As x grows positively or negatively without bound, the value f (x) of the polynomial function f (x) = a n x n + a n – 1 x n – 1 + … + a 1 x + a 0 (a n 0) grows positively or negatively without bound depending upon the sign of the leading coefficient a n and whether the degree n is odd or even. x y x y n odd n even a n positive a n negative
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Copyright © by Houghton Mifflin Company, Inc. All rights reserved. 9 Example: Right-Hand and Left-Hand Behavior Ex 2: Describe the right-hand and left-hand behaviour for the graph of f(x) = –2x 3 + 5x 2 – x + 1. As, and as, Negative-2Leading Coefficient Odd3Degree x y f (x) = –2x 3 + 5x 2 – x + 1
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Copyright © by Houghton Mifflin Company, Inc. All rights reserved. 10 Zeros of a Function A real number a is a zero of a function f (x) if and only if f (a) = 0. A turning point of a graph of a function is a point at which the graph changes from increasing to decreasing or vice versa. A polynomial function of degree n has at most n – 1 turning points and at most n zeros. Real Zeros of Polynomial Functions If a is a zero of a function f(x), then the following are true: 1. a is a solution of the polynomial equation f (x) = 0. 2. x – a is a factor of the polynomial f (x). 3. (a, 0) is an x-intercept of the graph of y = f (x).
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Copyright © by Houghton Mifflin Company, Inc. All rights reserved. 11 Repeated Zeros For any factor (x – a) k of f (x) a is a zero of the function and k is called the multiplicity. 1. If k is odd the graph of f (x) crosses the x-axis at (a, 0). 2. If k is even the graph of f (x) touches, but does not cross through, the x-axis at (a, 0).
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Copyright © by Houghton Mifflin Company, Inc. All rights reserved. 12 Repeated Zeros Ex 3: Determine end behavior and the multiplicity of the zeros, the graph: f (x) = (x – 2) 3 (x +1) 4. Zero Multiplicity Behavior 2 –1 3 4 odd even crosses x-axis at (2, 0) touches x-axis at (–1, 0) Repeated Zeros For any factor (x – a) k of f (x) a is a zero of the function and k is called the multiplicity. 1. If k is odd the graph of f (x) crosses the x-axis at (a, 0). 2. If k is even the graph of f (x) touches, but does not cross through, the x-axis at (a, 0). x y As, and as,
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Now graph this business Copyright © by Houghton Mifflin Company, Inc. All rights reserved. 13
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Copyright © by Houghton Mifflin Company, Inc. All rights reserved. 14 Example: Real Zeros Ex 4: Find the end behavior, all the real zeros and turning points of the graph of f (x) = x 4 – x 3 – 2x 2. Factor completely: f (x) = x 4 – x 3 – 2x 2 = x 2 (x + 1)(x – 2). The real zeros are x = –1, x = 0, and x = 2. These correspond to the x-intercepts (–1, 0), (0, 0) and (2, 0). The graph shows that there are three turning points. Since the degree is four, this is the maximum number possible. y x f (x) = x 4 – x 3 – 2x 2 Turning point
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Copyright © by Houghton Mifflin Company, Inc. All rights reserved. 15 Example: Graph of f(x) = 4x 2 – x 4 Ex 5: Sketch the graph of f (x) = 4x 2 – x 4. 1. Write the polynomial function in standard form: f (x) = –x 4 + 4x 2 The leading coefficient is negative and the degree is even. 2. Find the zeros of the polynomial by factoring. f (x) = –x 4 + 4x 2 = –x 2 (x 2 – 4) = – x 2 (x + 2)(x –2) Zeros: x = –2, 2 multiplicity 1 x = 0 multiplicity 2 x-intercepts: (–2, 0), (2, 0) crosses through (0, 0) touches only Example continued as, x y (2, 0) (0, 0) (–2, 0)
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Copyright © by Houghton Mifflin Company, Inc. All rights reserved. 16 Example Continued Ex 5 continued: Sketch the graph of f (x) = 4x 2 – x 4. 3. Since f (–x) = 4(–x) 2 – (–x) 4 = 4x 2 – x 4 = f (x), the graph is symmetrical about the y-axis. 4. Plot additional points and their reflections in the y-axis: (1.5, 3.9) and (–1.5, 3.9 ), ( 0.5, 0.94 ) and (–0.5, 0.94) 5. Draw the graph. x y (1.5, 3.9) (–1.5, 3.9 ) (– 0.5, 0.94 ) (0.5, 0.94)
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g(t) = t 5 – 6t 3 + 9t g(t) = t(t 4 – 6t 2 + 9) g(t) = t(t 2 – 3) 2 Ex 6: Find the zeros and determine their multiplicity
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The Intermediate Value Theorem Let a and b be real numbers such that a < b. If f is a polynomial function such that f(a) ≠ f(b) then in the interval [a, b], f takes on every value between f(a) and f(b).
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The Intermediate Value Theorem Think of an elevator: –If it reaches the 2 nd floor and the 30 th floor, it must reach every floor in between the 2 nd and 30 th.
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The Intermediate Value Theorem
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Why do we care? Since f(1)= -6 f(3) = 4 We know that for 1< x < 3 There is an x such that f(x)=0
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1-8 A Matching 1.f(x) = -2x + 3 2.f(x) = x 2 – 4x 3.f(x) = -2x 2 – 5x 4.f(x) = 2x 3 – 3x + 1 5.f(x) = -¼ x 4 + 3x 2 6.f(x) = -1/3 x 3 + x 2 – 4/3 7.f(x) = x 4 + 2x 3 8.f(x) = 1/5 x 5 -2x 3 + 9/5 x A
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1-8 B Matching 1.f(x) = -2x + 3 2.f(x) = x 2 – 4x 3.f(x) = -2x 2 – 5x 4.f(x) = 2x 3 – 3x + 1 5.A 6.f(x) = -1/3 x 3 + x 2 – 4/3 7.f(x) = x 4 + 2x 3 8.f(x) = 1/5 x 5 -2x 3 + 9/5 x B
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1-8 C Matching 1.f(x) = -2x + 3 2.f(x) = x 2 – 4x 3.f(x) = -2x 2 – 5x 4.f(x) = 2x 3 – 3x + 1 5. A 6.f(x) = -1/3 x 3 + x 2 – 4/3 7.f(x) = x 4 + 2x 3 8.B C
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1-8 D Matching 1.C 2.f(x) = x 2 – 4x 3.f(x) = -2x 2 – 5x 4.f(x) = 2x 3 – 3x + 1 5.A 6.f(x) = -1/3 x 3 + x 2 – 4/3 7.f(x) = x 4 + 2x 3 8.B D
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1-8 E Matching 1. C 2.f(x) = x 2 – 4x 3.f(x) = -2x 2 – 5x 4.f(x) = 2x 3 – 3x + 1 5.A 6.f(x) = -1/3 x 3 + x 2 – 4/3 7.D 8.B E
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1-8 F Matching 1. C 2.f(x) = x 2 – 4x 3.f(x) = -2x 2 – 5x 4.f(x) = 2x 3 – 3x + 1 5.A 6.E 7.D 8.B F
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1-8 G Matching 1. C 2.f(x) = x 2 – 4x 3.f(x) = -2x 2 – 5x 4.F 5.A 6.E 7.D 8.B G
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1-8 H Matching 1. C 2.G 3.f(x) = -2x 2 – 5x 4.F 5.A 6.E 7.D 8.B H
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H Dub 2.2 Page 148 #1-8all, 13-21ODD, 27- 41ODD (part c by hand – no calculators!!!), 65, 66, 92
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