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Section 8.3 ~ Estimating Population Proportions Introduction to Probability and Statistics Ms. Young.

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Presentation on theme: "Section 8.3 ~ Estimating Population Proportions Introduction to Probability and Statistics Ms. Young."— Presentation transcript:

1 Section 8.3 ~ Estimating Population Proportions Introduction to Probability and Statistics Ms. Young

2 Objective Sec. 8.3 After this section you will learn how to estimate population proportions and compute the associated margins of error and confidence intervals.

3 The Basics of Estimating a Population Proportion The process for estimating a population proportion, p, with a 95% confidence level using a sample proportion,, is the same as the process of estimating a population mean using a sample mean (section 8.2)  The only difference is the way that the margin of error is defined:  The confidence interval is written as: Sec. 8.3 or

4 Example 1 Sec. 8.3 The Nielsen ratings for television use a random sample of households. A Nielsen survey results in an estimate that a women’s World Cup soccer game had 72.3% of the entire viewing audience. Assuming that the sample consists of n = 5,000 randomly selected households, find the margin of error and the 95% confidence interval for this estimate. The 95% confidence interval is: 0.723 – 0.013 < p < 0.723 + 0.013 or 0.710 < p < 0.736 With 95% confidence, we can conclude that between 71% and 73.6% of the entire viewing audience watched the women’s World Cup soccer game.

5 Choosing Sample Size Choosing a sample size appropriate to satisfy a desired margin of error is found by manipulating this APPROXIMATE formula for margin of error: Note: any value equal to or larger than the value found using the formula would be sufficient Sec. 8.3 Used to approximate appropriate sample size

6 Example 2 Sec. 8.3 You plan a survey to estimate the proportion of students on your campus who carry a cell phone regularly. How many students should be in the sample if you want (with 95% confidence) a margin of error of no more than 4 percentage points? You should survey at least 625 students.


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