Download presentation
Presentation is loading. Please wait.
Published byRosalind Edwards Modified over 9 years ago
1
1 Hypothesis Testing Goodness-of-fit & Independence Chi-Squared Tests
2
2 Goodness-of-fit Test A managed forest has the following distribution of trees: Douglas Fir54% Ponderosa Pine40% Grand Fir5% Western Larch1% Mannan & Meslow (1984) made 156 observations of foraging by red-breasted nuthatches and found the following: Mannan, R.W., and E.C. Meslow. 1984. “Bird populations and vegetation characteristics in managed and old-growth forests, northeastern Oregon.” J. Wildl. Manage. 48: 1219-1238. Douglas Fir70 Ponderosa Pine 79 Grand Fir3 Western Larch4
3
3 Hypotheses Do the birds forage randomly, without regard to what species of tree they are in? To be true, the observed and expected distributions should be alike. Null: The distributions are alike (good fit, meaning birds forage randomly) Alternate: The distributions are different (lack of fit, or birds prefer certain vegetation)
4
4 Expected Values Based on the percentage distribution of trees, the expected counts for each type (out of 156) are: Douglas Fir84.24 Ponderosa Pine62.40 Grand Fir7.80 Western Larch1.56 (54% of 156 = 84.24)
5
5 Chi-Square Statistic ExpectedObservedo-e(o-e)Sq(o-e)Sq/e Douglas Fir 84.24 70-14.24 202.78 2.41 Ponderosa Pine 62.40 7916.60 275.56 4.42 Grand Fir 7.80 3-4.80 23.04 2.95 Western Larch 1.56 42.44 5.95 3.82 156.00156Chi-square =13.593 p-value =0.003514 For p-value in Excel, type =CHIDIST(13.593,3), for 3 degrees of freedom (n groups -1)
6
6 Conclusion Given the small p-value, we reject the null. These birds are not foraging randomly – they prefer certain types of trees.
7
7 Test of Independence Demographic data on 111 students is available. We wish to study gender differences, in this case pertaining to dog ownership. Data Set: Student Variables: Gender, Dog (Yes/No) Are Gender and Dog Ownership independent of each other? No Dog Have Dog Female2923 Male3524
8
8 The Hypotheses Null: The two variables are independent of each other (the occurrence of one does not influence the probability of the occurrence of the other.) Alternate: They are not independent (one influences the other)
9
9 Chi Square Test Results Tabulated statistics: Gender, Dog Rows: Gender Columns: Dog No Yes All Female 29 23 52 29.98 22.02 52.00 Male 35 24 59 34.02 24.98 59.00 All 64 47 111 64.00 47.00 111.00 Cell Contents: Count Expected count Pearson Chi-Square = 0.143, DF = 1, P-Value = 0.705 Likelihood Ratio Chi-Square = 0.143, DF = 1, P-Value = 0.705
Similar presentations
© 2025 SlidePlayer.com. Inc.
All rights reserved.