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 Vi = 0 m/s  T = 10 s  Find d =  Find v f =. Guided Practice Problems.

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Presentation on theme: " Vi = 0 m/s  T = 10 s  Find d =  Find v f =. Guided Practice Problems."— Presentation transcript:

1  Vi = 0 m/s  T = 10 s  Find d =  Find v f =

2 Guided Practice Problems

3  Find the uniform acceleration that causes a car’s velocity to change from 32m/s to change to 76 m/s. In an 8.0 s period.

4  Given:  V i = 32 m/s  V f = 76 m/s  T = 8.0 s  Unknown:  a =

5  Equation:  A = Δv  Δt

6  Answer: 5.5 m/s/s

7  Solution:  76m/s-32m/s / 8 s =

8  A supersonic jet flying at 155 m/s is accelerated uniformly at the rate of 23.1 m/s 2 for 30 s.  A. What is its final velocity?  B. The speed of sound in air is 331 m/s. How many times the speed of sound is the plane’s final speed?

9  Given:  Time = 30 s  A = 23.1 m/s 2  V i = 155 m/s  ______________  V f =  Speed of sound is 331 m/s  Unknown:  V f =

10  Equation: A  V f = v i + at

11  Equation B:  N= 848 m/s/331m/s=

12  Answer to A = 848 m/s

13  Answer to B:2.56 times

14  Solutions for A:  155m/s + (23.1 m/s/s)(30.0 s) =vf

15  Solution for B :  848 m/s/331m/s =

16  Determine the displacement of a plane that is uniformly accelerated from 66 m/s to 88 m/s in 14 s.

17  Given: 66 m/s = V i  88 m/s = V f  T = 14 s  Unknown: d

18  Equation  D=(vf + vi)t/2 =

19  Answer #3: 550 m

20  Solution #3 :  (88 m/s + 66 m/s)14 s/2 =

21  If a bullet leaves the muzzle of a gun with a speed of 500 m/s, and the barrel of the rifle is.9 m long. What is the acceleration of the bullet while in the barrel?

22  Given:  V f = 500 m/s  D =.9 m  V i = 0 m/s  Unknown:  A =

23  Equation:  a = V f 2 – v i 2 /2d

24  Answer :1.38 X 10 5 m/s/s

25  Solution:  (500 m/s )2 -0 /(2) (0.9 m) =

26  A plane travels 600 m while being accelerated uniformly from rest at the rate of 5.0 m/s 2. What final velocity does it attain?

27  Given: d = 600 m  a= 5.0 m/s 2  V i = 0 m/s  Unknown:  V f =

28  Equation:  V f 2 =v i 2 + 2ad

29  Answer: 77.5 m/s

30  Solution:  Sq root 0 +2(5.0 m/s/s)(600 m) =

31  Page 82: 1,5,  Page 83 : 8,9,10, 16  Page 84: 24,  Reviewing concepts: 1,2,3,8,  Applying concepts: 3, 8, 9  Due thursday

32  V f = v i + at  d = ½ (v f + V i )t  d = v i t + ½ at 2  V f 2 = v i 2 + 2ad  V i v f a t  V i d v f t  V i d a t  V f d v i a


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