1. Chemistry An Introduction to General, Organic, and Biological Chemistry, Eleventh Edition Copyright © 2012 by Pearson Education, Inc. Chapter 6 Gases 6.7 Volume and Moles Avogadro’s Law 1

2. Chemistry An Introduction to General, Organic, and Biological Chemistry, Eleventh Edition Copyright © 2012 by Pearson Education, Inc. Avogadro’s Law: Volume and Moles In Avogadro’s law, the volume of a gas is directly related to the number of moles (n) of gas. T and P are constant. V 1 = V 2 n 1 n 2 2

3. Chemistry An Introduction to General, Organic, and Biological Chemistry, Eleventh Edition Copyright © 2012 by Pearson Education, Inc. Calculations Using Avogadro’s Law If 0.75 mole of helium gas occupies a volume of 1.5 L, what volume (L) will 1.2 moles of helium occupy at the same temperature and pressure? A.0.94 L B.1.8 L C.2.4 L 3

4. Chemistry An Introduction to General, Organic, and Biological Chemistry, Eleventh Edition Copyright © 2012 by Pearson Education, Inc. Calculations Using Avogadro’s Law If 0.75 mole of helium gas occupies a volume of 1.5 L, what volume (L) will 1.2 moles of helium occupy at the same temperature and pressure? Step 1 Organize the data into a table of initial and final conditions. Conditions Initial Final V 1 = 1.5 L V 2 = ? n 1 = 0.75 mol n 2 = 1.2 moles 4

5. Chemistry An Introduction to General, Organic, and Biological Chemistry, Eleventh Edition Copyright © 2012 by Pearson Education, Inc. Calculations Using Combined Gas Law If 0.75 mole of helium gas occupies a volume of 1.5 L, what volume (L) will 1.2 moles of helium occupy at the same temperature and pressure? Step 2 Rearrange to solve for unknown quantity: V 2 V 2 = V 1  n 2 n 1 Step 3 Substitute the values into the gas law equation and calculate. V 2 = 1.5 L  1.2 moles = 2.4 L The answer is C. 0.75 mole 5

6. Chemistry An Introduction to General, Organic, and Biological Chemistry, Eleventh Edition Copyright © 2012 by Pearson Education, Inc. STP: Standard Temperature and Pressure The volumes of gases can be compared at STP, Standard Temperature and Pressure, when they have the same temperature standard temperature (T) 0  C or 273 K the same pressure standard pressure (P) 1 atm (760 mmHg) 6

7. Chemistry An Introduction to General, Organic, and Biological Chemistry, Eleventh Edition Copyright © 2012 by Pearson Education, Inc. Molar Volume At standard temperature and pressure (STP), 1 mole of a gas occupies a volume of 22.4 L, which is called its molar volume. Use this equality as a conversion factor: At STP, 22.4 L = 1 mole22.4 L and 1 mole 1 mole 22.4 L 7

8. Chemistry An Introduction to General, Organic, and Biological Chemistry, Eleventh Edition Copyright © 2012 by Pearson Education, Inc. Molar Volume 8

9. Chemistry An Introduction to General, Organic, and Biological Chemistry, Eleventh Edition Copyright © 2012 by Pearson Education, Inc. Guide to Using Molar Volume 9

10. Chemistry An Introduction to General, Organic, and Biological Chemistry, Eleventh Edition Copyright © 2012 by Pearson Education, Inc. Calculations Using Molar Volume What is the volume occupied by 2.75 moles of N 2 gas at STP? Step 1State the given and needed quantities. Given: 2.75 moles N 2 Needed: Volume of N 2 gas at STP Step 2 Write a plan. The molar volume is used to convert moles to liters. Molar Moles N 2 Volume Volume N 2 10

11. Chemistry An Introduction to General, Organic, and Biological Chemistry, Eleventh Edition Copyright © 2012 by Pearson Education, Inc. Calculations Using Molar Volume What is the volume occupied by 2.75 moles of N 2 gas at STP? Step 3 Write conversion factors including 22.4 L/mole at STP. At STP, 22.4 L = 1 mole22.4 L and 1 mole 1 mole 22.4 L Step 4 Set up problem with factors to cancel units. 2.75 moles N 2  22.4 L = 61.6 L 1 mole N 2 11

12. Chemistry An Introduction to General, Organic, and Biological Chemistry, Eleventh Edition Copyright © 2012 by Pearson Education, Inc. Learning Check 1. What is the volume at STP of 4.00 g of CH 4 ? A. 5.60 LB. 11.2 LC. 44.8 L 2. How many grams of He are present in 8.00 L of gas at STP? A. 25.6 gB. 0.357 gC. 1.43 g 12

13. Chemistry An Introduction to General, Organic, and Biological Chemistry, Eleventh Edition Copyright © 2012 by Pearson Education, Inc. Solution Step 1 State given and needed quantities. 1. What is the volume at STP of 4.00 g of CH 4 ? Given: 4.00 grams CH 4 Needed: Volume of CH 4 gas at STP 2. How many grams of He are present in 8.00 L of gas at STP? Given: 8.00 L of He at STP Needed: grams of He 13

14. Chemistry An Introduction to General, Organic, and Biological Chemistry, Eleventh Edition Copyright © 2012 by Pearson Education, Inc. Solution Step 2 Write a plan. 1.What is the volume at STP of 4.00 g of CH 4 ? The molar volume is used to convert moles to liters. mass CH 4 moles CH 4 volume CH 4 2.How many grams of He are present in 8.00 L of gas at STP? volume He moles He mass He 14

15. Chemistry An Introduction to General, Organic, and Biological Chemistry, Eleventh Edition Copyright © 2012 by Pearson Education, Inc. Solution Step 3 Write conversion factors including 22.4 L/mole at STP. 1. What is the volume at STP of 4.00 g of CH 4 ? At STP, 22.4 L = 1 mole 22.4 L and 1 mole 1 mole 22.4 L 1 mole of CH 4 = 16.05 g of CH 4 1 mole CH 4 and 16.05 g CH 4 16.05 g CH 4 1 mole CH 4 15

16. Chemistry An Introduction to General, Organic, and Biological Chemistry, Eleventh Edition Copyright © 2012 by Pearson Education, Inc. Solution Step 3 Write conversion factors including 22.4 L/mole at STP. 2. How many grams of He are present in 8.00 L of gas at STP? At STP, 22.4 L = 1 mole 22.4 L and 1 mole 1 mole 22.4 L 1 mole of He = 4.00 g He 1 mole He and 4.00 g He 4.00 g He 1 mole He 16

17. Chemistry An Introduction to General, Organic, and Biological Chemistry, Eleventh Edition Copyright © 2012 by Pearson Education, Inc. Solution Step 4 Set up problem with factors to cancel units. 1. What is the volume at STP of 4.00 g of CH 4 ? 4.00 g CH 4  1 mole CH 4  22.4 L (STP) = 5.60 L 16.0 g CH 4 1 mole CH 4 The answer is A, 5.60 L. 2. How many grams of He are present in 8.00 L of gas at STP? 8.00 L  1 mole He  4.00 g He = 1.43 g He 22.4 L (STP) 1 mole He The answer is C, 1.43 g. 17