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3.6 Distance. 3.6 – Equations & Problem Solving Goals / “I can…” Define a variable in terms of another variable Model distance-rate-time problems.

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Presentation on theme: "3.6 Distance. 3.6 – Equations & Problem Solving Goals / “I can…” Define a variable in terms of another variable Model distance-rate-time problems."— Presentation transcript:

1 3.6 Distance

2 3.6 – Equations & Problem Solving Goals / “I can…” Define a variable in terms of another variable Model distance-rate-time problems

3 First Things First!!

4 1) Solve 2x - 4y = 7 for x To get x by itself, what is the first step? 1. Add 2x 2. Subtract 2x 3. Add 4y 4. Subtract 4y Answer Now

5 Ask yourself, What is the first thing we are doing to x? What is the second thing? 1) Solve 2x - 4y = 7 for x Use a DO-UNDO chart to help determine the steps DO UNDO · 2 -4y Follow the steps in the ‘undo’ column to isolate the variable. +4y ÷ 2 Complete the undo column by writing the opposite operations in opposite order.

6 1) Solve 2x - 4y = 7 for x 1. Draw “the river” 2. Add 4y to both sides 3. Simplify 4. Divide both sides by 2 5. Does it simplify? D U · 2 -4y +4y ÷ 2 + 4y + 4y 2x = 7 + 4y 2 2 This fraction cannot be simplified because both terms in the numerator are not divisible by 2.

7 3) Solve for y. What is the first step? 1. Multiply by 3 2. Divide by 3 3. Add a 4. Subtract a Answer Now

8 3) Solve for y: 1.Draw “the river” 2.Clear the fraction – multiply both sides by 3 3.Simplify 4.Subtract a from both sides 5.Simplify D U + a ÷ 3 · 3 - a y + a = 3c -a -a y = 3c - a

9 3.6 – Equations & Problem Solving Consecutive Integers are numbers that differ by 1.

10 3.6 – Equations & Problem Solving Example 1: The sum of three consecutive numbers is 72. Find them. The three numbers are x, x + 1, x + 2. (x) + (x + 1) + (x + 2) = 72

11 3.6 – Equations & Problem Solving Distance – Rate – Time Problems One of the most common and powerful formulas in math and science is d = rt. This stands for distance = rate x time. There are three types of uniform motion problems: same direction, different direction, round trip. HINT: How are the distances related?

12 The 3 formulas for Speed, Time & Distance: Speed = Distance Time Time = Distance Speed Distance =Speed xTime Remember them from this triangle: D ST Solving for SpeedSolving for TimeSolving for Distance

13 D ST A windsurfer travelled 28 km in 1 hour 45 mins. Calculate his speed. Speed = Distance Time 28 175 = = 16 km/h 1 hour 45 mins Answer: His speed was 16 km / hour

14 2 hour 30 mins Answer: He travelled 125 km A salesman travelled at an average speed of 50 km/h for 2 hours 30 mins. How far did he travel? D ST Distance = Speed x Time = 50 x 25 = 125 km

15 Answer: It took 9 hours 15 minutes A train travelled 555 miles at an average speed of 60 mph. How long did the journey take? D ST Time = Distance Speed 555 60 = = 925 hours= 9 hours 15 mins

16 3.6 – Equations & Problem Solving Example 3: Same – Direction (SAME DIRECTION) A train leaves a train stations at 1 p.m. It travels at a rate of 72 mi/hr. Another train leaves the same station at one hour later. It is traveling at 90 mi/hr. The second train follows the same path as the first on a parallel track. How long will it take for the second train to catch the first? rateTime = Distance = =

17 3.6 – Equations & Problem Solving A group of campers and their group leader left their campsite in a canoe. They traveled at 10 mi/hr. 2 hours later another group leader the same site in a motorboat. He traveled at 22 mi/hr. How long after the canoe left the site did the motorboat catch the canoe? How long did the motorboat travel?

18 3.6 – Equations & Problem Solving Example 4 Round Trip (SAME DISTANCE) You drive into town to get a new computer. Because of traffic, you drive at 15 mi/hr. On your way home you drive 35 mi/hr. Your total trip is 2 hours. How long did it take you to get to the store? rateTime = Distance = =

19 3.6 – Equations & Problem Solving Example 5 Opposite Direction (TOTAL DISTANCE) Jack and Jill leave their home in opposite directions on the same road. Jack drives 15 mi/hr. faster than Jill. After 3 hours they are 225 miles apart. Find Jack’s rate and Jill’s rate. rateTime = Distance = =


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