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Published byChristina Harrington Modified over 9 years ago
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Trig Identities in Equations Brought to you by Seamus and Lucas
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What are the Trig Identities?
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Problem 1 Solve for all values of x when 0°≤x<360°:
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Solution 1 cos -1 (½)= x x= 60° x= 300° cos -1 (1)= x x= 0°
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Problem 2
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Solution 2
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Problem 3 Find, to the nearest degree, all values of X between 0° and 360° that satisfy the equation 2sinx + 4cos2x=3
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Solution 3 2sin(x) + 4(1-2sin 2 x) - 3=0. 2sin(x) + 4 - 8sin 2 x - 3=0 -8sin 2 x + 2sin(x) + 1=0. {30°, 150°, 346°, 194°} -8sin 2 x + 4sin(x) - 2sin(x) + 1=0 4sin(x)(-2sin x +1) 1(-2sin x + 1) -2sin(x) + 1=0. 4sin(x) + 1=0 x=sin -1 (½). x=sin -1 (-¼) 30°. -14° (reject) 150°. 346° 194°
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