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Interference: Division of wave fronts

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Presentation on theme: "Interference: Division of wave fronts"— Presentation transcript:

1 Interference: Division of wave fronts
Young’s double slit arrangement Lloyd’s mirror Fresnel’s mirrors Fresnel’s bi-prism Billet’s split lens Meslin’s split lens

2 Interference: Division of amplitude
Pohl’s patterns Fringes from a transparent film Fringes from a wedge Michelson’s interferometer Newton’s rings Fabry-Perot interferometer

3 Interferometers

4 Albert Abraham Michelson (1852-1931)
Michelson measured the velocity of light with amazing delicacy in 1881. Michelson and Morley showed that the light travels at a constant speed in all inertial frames of reference. Michelson measured the standard meter in terms of wavelength of cadmium light ( The Nobel Prize: 1907)

5 Michelson Morley

6 Photograph of Michelson Interferometer

7 Michelson Interferometer
This instrument can produce both types of interference fringes i.e., circular fringes of equal inclination at infinity and localized fringes of equal thickness.

8 Schematic diagram

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10 Effective linear arrangement for circular fringe
An observer looking through the telescope will see 𝑀 1 ′ , a reflected image of M1 and the images S’ and S” of the source provided by 𝑀 1 ′ and M2.

11 Order of the fringe, if the central fringe is dark:
Order of fringes 2𝑑 cos 𝜃 𝑚 =𝑚𝜆, 𝑚=0, 1, 2, 3, …, 𝑚 0 Minima: 2𝑑 cos 𝜃 𝑚 =(𝑚+1/2)𝜆, 𝑚=0, 1, 2, 3, …, 𝑚 0 Maxmima: Order of the fringe, if the central fringe is dark: 𝑚 0 =2𝑑/𝜆 For any value of d, the central fringe has the largest value of m. As d is increased new fringes appear at the centre and the existing fringes move outwards, and finally move out of the field of view.

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13 Haidinger Fringe

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15 Measurement of wavelength of light
2𝑑 cos 𝜃= 𝑚𝜆 2𝑑= 𝑚 0 𝜆 (𝜃=0) Move one of the mirrors to a new position d’ so that the order of the fringe at the centre is changed from mo to m. 2 𝑑 ′ =𝑚𝜆 ⟹2 𝑑− 𝑑 ′ = 𝑚 0 −𝑚 𝜆=𝑛𝜆 ⟹𝜆=2∆𝑑/(∆𝑚)

16 C0ncordance 2 𝑑 1 =𝑝 𝜆 1 =𝑞 𝜆 1 +∆𝜆 2𝑑= 𝑚 0 𝜆
If fringe patterns due to two wavelengths coincide at the centre, 2 𝑑 1 =𝑝 𝜆 1 =𝑞 𝜆 1 +∆𝜆 The fringe pattern is very bright⟹Concordance 2𝑑= 𝑚 0 𝜆

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18 Fringe system at concordance
2 𝑑 1 =𝑝 𝜆 1 =𝑞 𝜆 1 +∆𝜆

19 Measurement of wavelength separation
2𝑑= 𝑚 0 𝜆 2 𝑑 1 =𝑝 𝜆 1 =𝑞 𝜆 1 +∆𝜆 The condition for concordance: As d is increased 𝑝→𝑝+∆𝑝and 𝑞→𝑞+∆𝑞 with ∆𝑞< ∆𝑝. When 𝑞=𝑝−1/2, the bright fringe pattern of λ1coincides with the dark fringe pattern of λ1+λ, and vice-versa and the fringe pattern is washed away (Discordance). The fringe pattern is dark⟹Discroncordance

20 Fringe patterns at discordance

21 2 𝑑 1 =𝑝 𝜆 1 =𝑞 𝜆 1 +∆𝜆 2 𝑑 2 =(𝑝+𝑛) 𝜆 1 =(𝑞+𝑛−1) 𝜆 1 +∆𝜆
The condition for concordance: 2 𝑑 1 =𝑝 𝜆 1 =𝑞 𝜆 1 +∆𝜆 Δ can be measured by increasing d1 to d2 so that the two sets of fringes, initially concordant, become discordant and are finally concordant again. If p changes to p+n, and q changes to q+(n-1) we have concordant fringes again. 2 𝑑 2 =(𝑝+𝑛) 𝜆 1 =(𝑞+𝑛−1) 𝜆 1 +∆𝜆 ⟹2( 𝑑 2 −𝑑 1 )=𝑛 𝜆 1 =(𝑛−1) 𝜆 1 +∆𝜆 ⟹2 𝑑 2 −𝑑 1 =𝑛 𝜆 1 & 𝑛−1 ∆𝜆= 𝜆 1 ⟹2 𝑑 2 −𝑑 1 =𝑛 𝜆 1 ≈ 𝜆 1 2 ∆𝜆 𝑓𝑜𝑟 𝑛≫1 ⟹∆𝜆≈ 𝜆 1 2 /2 𝑑 2 −𝑑 1

22 Measurement of the coherence length of a spectral line
Measurement of thickness of thin transparent flakes Measurement of refractive index of gases

23 Newton’s rings

24 Pair of rays method Condition for dark rings

25 1 𝑉 = 1 𝑈 − 2 𝑅 = 𝑅−2𝑈 𝑅𝑈 ⟹𝑉= 𝑅𝑈 𝑅−2𝑈 𝑑=𝑉−𝑈= 𝑅𝑈 𝑅−2𝑈 −𝑈≈ 2 𝑈 2 𝑅 , 𝑎𝑠 𝑅≫𝑈 𝑆 1 𝑁 =𝑑 cos 𝜃 𝑚 ≈𝑑 1− 𝜃 𝑚 =𝑚𝜆 𝑓𝑜𝑟 𝑎 𝑑𝑎𝑟𝑘 𝑟𝑖𝑛𝑔 𝐴𝑠 𝑑 𝜆 = 𝑚 0 , 𝑚 0 −𝑚=𝑑 𝜃 𝑚 2 /2𝜆⟹ 𝜃 𝑛 2 =2𝑛𝜆/𝑑

26 A𝑠 𝑑≪𝑈, 𝑟 𝑛 2 ≈ 𝑈 2 𝜃 𝑛 2 = 2𝑛𝜆 𝑈 2 𝑑 = 2𝑛𝜆 𝑈 𝑈 2 𝑅 =𝑛𝜆𝑅 ⟹𝑟 𝑛 = 𝑛𝜆𝑅

27 Newton’s rings

28 Measurement of R.I. of a liquid
𝑡 𝑛 = 𝑟 𝑛 2 2𝑅 ⟹𝑠𝑎𝑔𝑖𝑡𝑡𝑎 𝑓𝑜𝑟𝑚𝑢𝑙𝑎 For an air film, 2 𝑡 𝑛 =𝑛𝜆⟹ 𝑟 𝑛 2 =2 𝑡 𝑛 𝑅=𝑛𝜆𝑅 For a liquid film of R.I. μ, 2𝜇 𝑡 𝑛 =𝑛𝜆⟹2𝜇 𝑟 𝑛 2 /2𝑅=𝑛𝜆⟹ 𝑟 𝑛 2 =𝑛𝜆𝑅/𝜇 𝑟 𝑛 2 𝑟 𝑛 2 =𝜇


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