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Published byCalvin Fitzgerald Modified over 9 years ago
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Lesson 7 Menu Warm-up Problems State the property that justifies each statement. 1.2(LM + NO) = 2LM + 2NO. 2.If m R = m S, then m R + m T = m S + m T. 3.m Z = m Z. 4.If BC = CD and CD = EF, then BC = EF. 5.Which property justifies the statement: If 90 = m I, then m I = 90?
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Lesson 7 MI/Vocab Write proofs involving segment addition. Write proofs involving segment congruence.
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Lesson 7 PS1
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Lesson 7 PS2
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Lesson 7 Ex1 Proof with Segment Addition 1. Given PR = QS 1. 2. Subtraction Property PR – QR = QS – QR 2. 3. Segment Addition Postulate PR – QR = PQ; QS – QR = RS 3. 4. Substitution PQ = RS 4. Proof: Statements Reasons Prove the following. Given: PR = QS Prove: PQ = RS
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Lesson 7 CYP1 Prove the following. Given:AC = AB AB = BX CY = XD Prove:AY = BD
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Lesson 7 CYP1 1. Given AC = AB, AB = BX 1. 2. Transitive Property AC = BX 2. 3. Given CY = XD 3. 4. Addition PropertyAC + CY = BX + XD4. AY = BD 6. Substitution6. Proof: Statements Reasons Which choice correctly completes the proof? 5. ________________ AC + CY = AY; BX + XD = BD 5. ?
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A.A B.B C.C D.D Lesson 7 CYP1 A.Addition Property B.Substitution C.Definition of congruent symbols D.Segment Addition Postulate
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Lesson 7 TH1
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Lesson 7 Ex2 Proof with Segment Congruence Prove the following. Given: Prove:
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Lesson 7 Ex2 Proof with Segment Congruence 5. Symmetric Property 5. Proof: Statements Reasons 1. Given 1. 2. Definition of congruent segments 2. 3. Given 3. 4. Transitive Property 4.
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Lesson 7 CYP2 Prove the following. Given: Prove:
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Lesson 7 CYP2 Which choice correctly completes the proof? Proof: Statements Reasons 1. Given 1. 2. Transitive Property 2. 3. Given 3. 4. Transitive Property 4. 5. _______________ 5. ?
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Lesson 7 CYP2 1.A 2.B 3.C 4.D A.Substitution B.Symmetric Property C.Segment Addition Postulate D.Reflexive Property
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