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Pre-Algebra Chapter 3 Review. Chapter 3 Review 1)Write each decimal. a) three thousand one and three thousandths b) four and three tenths.

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Presentation on theme: "Pre-Algebra Chapter 3 Review. Chapter 3 Review 1)Write each decimal. a) three thousand one and three thousandths b) four and three tenths."— Presentation transcript:

1 Pre-Algebra Chapter 3 Review

2 Chapter 3 Review 1)Write each decimal. a) three thousand one and three thousandths b) four and three tenths

3 Chapter 3 Review 1)Write each decimal. a) three thousand one and three thousandths 3001.003 b) four and three tenths 4.3 Answer

4 Chapter 3 Review 2)Round to the indicated place. a) -3.089, nearest hundredth b) 238.079, nearest unit c)1587.2364, nearest hundred

5 Chapter 3 Review 2)Round to the indicated place. a) -3.089, nearest hundredth -3.09 b) 238.079, nearest unit 238 c)1587.2364, nearest hundred 1600 Answer

6 Chapter 3 Review 3)Compare. Use >, < or = a) 0.12 < 0.2 b) -4.7 < -4.6 c)5.080 = 5.08

7 Chapter 3 Review 3)Compare. Use >, < or = a) 0.12 < 0.2 b) -4.7 < -4.6 c)5.080 = 5.08 Answer

8 Chapter 3 Review 4)Evaluate each expression for a = 3.02 and b = -12.3 a) a – b = b) │a│ + │b│ =

9 Chapter 3 Review 4)Evaluate each expression for a = 3.02 and b = -12.3 a) a – b = 15.32 b) │a│ + │b│ = 15.32 Answer

10 Chapter 3 Review 5) Solve. a) a + 0.03 = 3.75 b) 0.5 = x / 33

11 Chapter 3 Review 5) Solve. a) a + 0.03 = 3.75a = 3.72 b) 0.5 = x / 33 x = 16.5 Answer

12 Chapter 3 Review 6) Solve. a) 0.9853n = 98.53 b) -15 – 3(2x – 5) = 1.2

13 Chapter 3 Review 6) Solve. a) 0.9853n = 98.53 n = 100 b) -15 – 3(2x – 5) = 1.2 x = - 0.2 Answer

14 Chapter 3 Review 7) Write an equation and solve. A pound of peanuts costs $2.87. How many pounds can be bought with $20?

15 Chapter 3 Review 7) Write an equation and solve. A pound of peanuts costs $2.87. How many pounds can be bought with $20? 2.87p = 20 p = 6.97 lbs. Answer

16 Chapter 3 Review 8)Write an equation and solve. Three hundredths times a number is equal to the opposite of three and one hundredth.

17 Chapter 3 Review 8)Write an equation and solve. Three hundredths times a number is equal to the opposite of three and one hundredth. 0.03n = -3.01 n = -100.3 Answer

18 Chapter 3 Review 9)How much more mass does a 2 L bottle of water have than a 2 L bottle of gasoline? (d gas = 0.68 g/cm 3 )

19 Chapter 3 Review 9)How much more mass does a 2 L bottle of water have than a 2 L bottle of gasoline? (d gas = 0.68 g/cm 3 ) d = m/v  m = dv m water = (1)(2000) = 2000 g m gas = (0.68)(2000) = 1360 g Difference = 2000 – 1360 = 640 g or 0.64 kg Answer

20 Chapter 3 Review 10)An object falls for 10 sec. Ignoring air resistance, what is its velocity? (a gravity = 9.8 m/sec 2 )

21 Chapter 3 Review 10)An object falls for 10 sec. Ignoring air resistance, what is its velocity? (a gravity = 9.8 m/sec 2 ) v = at v = (9.8)(10) = 98 m/sec Answer


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