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Published byVirgil Osborne Modified over 9 years ago
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Chapter 4 The Composition of Solutions
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Expressing Solubility M = Molarity = moles solute / liters of solution
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Ex - Calculate the molarity of a solution made by dissolving 23.4 g Na 2 SO 4 in enough water to form 125 mL of solution.
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Ex - What are the concentrations of each ion in the last example?
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Ex - How many grams of Na 2 SO 4 are required to make 0.350 L of 0.500 M Na 2 SO 4
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A solution of precisely known concentration is called a standard solution. Standard solutions can be made 2 ways: from the solid - the solute is added to the flask and water is added to the line on the flask by dilution - a solution is added to the flask and water is added to further dilute the solution
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For dilution: moles of solute before dilution = moles of solute after dilution. M 1 V 1 = M 2 V 2 Ex - How much 3.0 M H 2 SO 4 would be required to make 500 mL of 0.10 M H 2 SO 4 ?
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Click here to take the quizClick here to take the quiz or here is the link: https://docs.google.com/spreadsheet/embeddedform?formkey =dE9GUm1KOEpmUmt5QVZreXg5N3NNYXc6MQ
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