1. Density of a Gas at STP Lesson # 4

2. 1.Calculate the density of N 2 at STP. Calculate Density=grams litre Assume that you have 1 mole of N 2

3. 1.Calculate the density of N 2 at STP. Calculate Density=grams litre 28.0 g = Assume that you have 1 mole of N 2

4. 1.Calculate the density of N 2 at STP. Calculate Density=grams litre 28.0 g = 22.4 L Assume that you have 1 mole of N 2

5. 1.Calculate the density of N 2 at STP. Calculate Density=grams litre 28.0 g =1.25 g/L 22.4 L Assume that you have 1 mole of N 2

6. 2.Calculate the density of CO 2 at STP. Density=grams litre Assume that you have 1 mole of CO 2

7. 2.Calculate the density of CO 2 at STP. Calculate Density=grams litre 44.0 g = Assume that you have 1 mole of CO 2

8. 2.Calculate the density of CO 2 at STP. Calculate Density=grams litre 44.0 g = 22.4 L Assume that you have 1 mole of CO 2

9. 2.Calculate the density of CO 2 at STP. Calculate Density=grams litre 44.0 g =1.96 g/L 22.4 L Assume that you have 1 mole of CO 2

10. 3.Calculate the volume of O 2 gas produced at STP for the complete decomposition of 12.5 g HgO if the yield is 45.0 %. 2HgO→ 2Hg+O 2 12.5 g? L 1212

11. 3.Calculate the volume of O 2 gas produced at STP for the complete decomposition of 12.5 g HgO if the yield is 45.0 %. 2HgO→ 2Hg+O 2 12.5 g? L 12.5 g HgO x 1mole 216.6g

12. 3.Calculate the volume of O 2 gas produced at STP for the complete decomposition of 12.5 g HgO if the yield is 45.0 %. 2HgO→ 2Hg+O 2 12.5 g? L 12.5 g HgO x 1mole x 1 mole O 2 216.6g 2 mole HgO

13. 3.Calculate the volume of O 2 gas produced at STP for the complete decomposition of 12.5 g HgO if the yield is 45.0 %. 2HgO→ 2Hg+O 2 12.5 g? L 12.5 g HgO x 1mole x 1 mole O 2 x 22.4 L 216.6g 2 mole HgO 1 mole

14. 3.Calculate the volume of O 2 gas produced at STP for the complete decomposition of 12.5 g HgO if the yield is 45.0 %. 2HgO→ 2Hg+O 2 12.5 g? L 12.5 g HgO x 1mole x 1 mole O 2 x 22.4 L x 0.450 216.6g 2 mole HgO 1 mole

15. 3.Calculate the volume of O 2 gas produced at STP for the complete decomposition of 12.5 g HgO if the yield is 45.0 %. 2HgO→ 2Hg+O 2 12.5 g? L 12.5 g HgO x 1mole x 1 mole O 2 x 22.4 L x 0.450 = 0.291 L 216.6g 2 mole HgO 1 mole

16. 4.How many litres of CO 2 are produced by the reaction of 100. g of Fe 2 O 3, if the actual yield was 19.0 L @ STP, calculate the percentage yield. 19.0 L 2Fe 2 O 3 +3C  4Fe+3CO 2 100. g? L 3232

17. 4.How many litres of CO 2 are produced by the reaction of 100. g of Fe 2 O 3, if the actual yield was 19.0 L @ STP, calculate the percentage yield. 19.0 L 2Fe 2 O 3 +3C  4Fe+3CO 2 100. g? L 100. g Fe 2 O 3 x 1 mole x 3 mole CO 2 x 22.4 L = 21.05 L 159.6 g 2 mole Fe 2 O 3 1 mole Percentage yield = 19.0 L x 100% = 90.3 % 21.05 L 3232