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Bree Gray Math 1210 Fall Semester
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Your company wants to run a pipeline from the well to the refinery. You are to propose the most cost effective way to build this pipeline.
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$300,000 per mile for material, labor, and fees $200,000 per mile if on private land $500,000 to drill through mountain $100,000 to do environmental study $50,000 per month for any delays
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Head east through mountain and south to the refinery. 20 miles 5 miles
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20 miles east+5 miles south=25 total miles 25 miles x $300,000/mile=$7,500,000 Additional costs: $500,000 for drilling, $100,000 for environmental study, $150,000 for 3 month set back Total cost: $8,250,000
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Run the pipeline west, south, and then east
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1 mi west+5 mi south+21 mi east=27 miles 27 miles x $300,000/mile=$8,100,000 This is cheaper than option 1.
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Running the shortest distance through private ground. X 20 miles 5 miles
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Solve for x using Pythagorean Theorem √400+25=20.6155 miles 20.616 miles x $500,000= $10,307,764.06 More expensive than both previous options.
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A pipeline that runs southeast on private property and goes through the south boarder of the private property and then heads east to the refinery. X C a α β
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a=20-x so C= √25+(20-x)² $500,000 √25+(20-x)²)+$300,000x Cost’(x)=$250,000(-2(20-x))(25+(20-x) ²)^- ½+$300,000 Simplify:
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u ²=14.0625 so u=3.75 20-x=3.75 and x=16.25 f’(16.25)=250000(25+(20-16.25)²)^-½+300000 Total cost: $800,000 This is the cheapest option
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C= √25+14.0625=6.25 miles through private ground α=tan(3.75/5)=36.87° β =|cos(3.75/6.25)-180|=126.87° X C a α β
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