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C2: Quadratic Functions and Discriminants Dr J Frost (jfrost@tiffin.kingston.sch.uk) Last modified: 2 nd September 2013
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Starter Solve the following: ? ? ? ? ? ?
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Completing the Square ? ? ? ? ? ? Put the following in the form p(x+q) 2 + r
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Completing the Square Put the following in the form p – q(x + r) 2 2x – 3 – x 2 -2 – (x-1) 2 7 – 6x – x 2 16 – (x+3) 2 5 – 2x 2 – 8x13 – 2(x+3) 2 18x + 10 – 3x 2 37 – 3(x-3) 2 ? ? ? ?
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Exercises ? ? ? ? ? ? ? ? ? 1 2 3 4 5 6 7 8 9 3 + 6x – x 2 = 12 – (x-3) 2 10 – 8x – x 2 = 26 – (x+4) 2 10x – 8 – 5x 2 = -3 – 5(x-1) 2 1 – 36x – 6x 2 = 55 – 6(x+3) 2 10 11 12 13
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Solving Equations by Completing the Square ? ?
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Your go… ? ?
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Examples 1 3 5 7 9 Exercise 2D – Page 21 ? ? ? ? ? E2 Given that for all values of x: 3x 2 + 12x + 5 = p(x+q) 2 + r a)Find all the values of p, q and r. b)Hence solve the equation 3x 2 + 12x + 5 = 0 p = 3, q = 2, r = -7 x = -2 √ (7/3) ? ? E1
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The Quadratic Formula ? Proof?
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The Discriminant Roots ? What formula do we know to find these roots?
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The Discriminant b 2 – 4ac is known as the discriminant.
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The Discriminant x 2 + 3x + 4 EquationDiscriminantNumber of Roots -70 x 2 – 4x + 1122 x 2 – 4x + 4 01 2x 2 – 6x – 360 2 x – 4 – 3x 2 -47 0 1 – x 2 42 ?? ?? ?? ?? ?? ??
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The Discriminant y = ax 2 + bx + c x y x y x y b 2 – 4ac > 0b 2 – 4ac = 0b 2 – 4ac < 0 ?? ? What can we say about the discriminant in each case? 2 roots/solutions1 roots/solutions0 roots/solutions ???
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The Discriminant a) p = 4 (reject p = -1) b) x = -4 ? ?
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The Discriminant Find the values of k for which x 2 + kx + 9 = 0 has equal roots. k = 6 Find the values of k for which x 2 – kx + 4 = 0 has equal roots. k = 4 Find the values of k for which kx 2 + 8x + k = 0 has equal roots. k = 4 1 2 3 ? ? ? We’ll revisit this topic after we’ve done Inequalities. Find the values of k for which kx 2 + (2k+1)x = 4 has equal roots. k = -1 0.5 √ 3 4 ?
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Sketching Quadratics Sketch y = x 2 + 2x + 1Sketch y = x 2 + x – 2 x y x y 1 1 -21 Sketch y = -x 2 + 2x + 3 x y 3 3 Sketch y = 2x 2 – 5x – 3 x y -3 -0.53 ?? ??
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Sketching Quadratics Sketch y = x 2 – 4x + 5Sketch y = x 2 + 6x + 12 x y x y (2, 1) 5 (-3, 3) 12 Sketch y = -x 2 + 2x – 3 y -3 (1,-2) Sketch y = -2x 2 – 12x – 22 y -22 (-3, -4) ?? ?? All of the following have no roots. Complete the square in order to find the min/max point.
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Exercises Sketch the following. Make sure you indicate any intersections with the axes. Q8-10 have no roots – complete the square in order to indicate the min/max point. y = x 2 – 9 y = x 2 – 3 y = 1 - x 2 y = x 2 + 2x – 35 y = 2x 2 + x – 3 y = 6 – 10x – 4x 2 y = 15x – 2x 2 y = x 2 – 10x + 28 y = x 2 + 8x + 19 y = 2x – 2 – x 2 1 2 3 4 5 6 7 8 9 10
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