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Chemistry Jeopardy Unit 6 Solutions & Solubility I’m Concentrating Colligative Properties Equal What?Special K’s 10 20 30 40 50
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The ingredient of a solution present in the greatest amount. A. Ions B. Liquid C. Solute D. Solvent
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This factor has the largest effect of the solubility of solid compounds. A. Pressure B. Temperature C. Rate of Stirring D. Amount of solvent
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A solution that contains the maximum amount of solute possible. A. Unsaturated B. Saturated C. Supersaturated D. Megasaturated
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To maximize the solubility of gases in solutions a student should. A. Increase the temperature B. Decrease the temperature C. Decrease the pressure D. Increase the amount of solvent
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What saying allows us to predict if a solvent will dissolve a solute? A. Likes dissolve likes B. Polar dissolves nonpolar C. Nonpolar dissolves polar D. All solvents dissolve all solutes
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Molarity has units of A. grams/mole B. moles/kilogram C. liters/mole D. moles/liter
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What is the concentration of a solution made by dissolving 1.5 mol of NaCl to a volume of 500. mL A. 1.5 M B. 0.0030 M C. 3.0 M D. 2.0 M
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The product of concentration times volume. A. Moles B. Molarity C. Keq D. Dilution
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Proper solution preparation requires what piece of equipment. A. Beaker B. Erlenmeyer Flask C. Graduated Cylinder D. Volumetric Flask
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What is the resulting concentration when 20. mL of a 2.0M solution is diluted to 40. mL? A. 1.0 M B. 0.50 M C. 2.0 M D. 4.0 M
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Colligative Properties depend on the number of A. Chemists Working B. Particles in solution C. Beakers used D. Readings taken
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A liquid reaches its boiling point when A. It feels like it B. When bubbles start form C. The vapor pressure of the liquid equals the pressure of the atmosphere D. Cannot be determined
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Adding a solute to a solvent A. Raises the freezing point B. Lowers the boiling point C. Lowers the freezing point D. Does not change the boiling point
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What is the advantage of using AlCl 3 to melt ice on sidewalks as opposed to NaCl A. The freezing point change will be 2x larger B. The freezing point change will be 4x larger C. The freezing point change will be 10x larger D. There is no advantage
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When ΔT f = 3.4 ºC for an aqueous solution of NaCl the new freezing point of the solution is A. 3.4 ºC B. -3.4 ºC C. 103.4 ºC D. 96.6 ºC
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When a reaction reaches equilibrium the forward and reverse reactions A. Occur at different rates B. Occur at the same rate C. Stop D. Make the same amount of chemical
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The only stress that can change the equilibrium constant is A.Concentration B.Temperature C.Pressure D.Final Exams
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A large equilibrium constant mean the reaction is A.Product favored B.Reactant favored C.Neutral D.Happens very fast
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Ksp expressions are written for A. Chemical equilibrium B. Force equilibrium C. Solubility equilibrium D. Balance Equilibrium
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When a common ion is added to an equilibrium the equilibrium shifts A. Toward the added ion B. Away from the added ion C. Toward the heat in the reaction D. Toward the higher pressure
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What is the equilibrium expression for the following equation? 3A (g) + 2B (g) A 3 B 2(g) A. Keq = [A 3 B 2 ] / ([A] 3 [B] 2 ) B. Keq = [A] 3 [B] 2 / [A 3 B 2 ] C. Keq = [A] [B] / [A 3 B 2 ] D. Keq = [A 3 ] [B 2 ] / [A 3 B 2 ]
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How can the following reaction be made to favor the product side of the reaction? 3A(g) + 2B(g) A 3 B 2 (g) + heat A. Add more product B. Increase the pressure C. Increase the temperature D. Add a catalyst
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What is the Ksp expression for the following reaction BaSO 4(s) Ba +2 + SO 4 -2 A. Ksp = [BaSO 4 ] / ([Ba +2 ] [SO 4 -2 ]) B. Ksp = [Ba +2 ] [SO 4 -2 ] / [BaSO 4 ] C. Ksp = [BaSO 4 ] / [Ba] 2 [SO4] -2 D. Ksp = [Ba +2 ] [SO4 -2 ]
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Which of the following will have no effect on the reaction? A (g) + B (g) AB (g) + heat A. Increasing the amount of A B. Decreasing the temperature C. Increasing the amount of A 2 B 2 D. Increasing the pressure
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How could you lower the concentration of Ba +2 for the following reaction? BaSO 4(s) Ba +2 + SO 4 -2 A. Add solid Na 2 SO 4 B. Increase the pressure C. Add solid Ba(NO 3 ) 2 D. The concentration cannot be changed
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