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RC Circuits Physics 102: Lecture 7 Exam I: Monday February 18 PRACTICE EXAM IS AVAILABLE-CLICK ON “COURSE INFO” ON WEB PAGE Exam I
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Review, Sunday Feb. 17 3 PM, 141 Loomis I will go over a past exam On Monday, you get to vote for which exam a)Fall 2007 b)Spring 2007 c)Fall 2006 d)Spring 2006 e)Fall 2005
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Recall …. First we covered circuits with batteries and capacitors –series, parallel Then we covered circuits with batteries and resistors –series, parallel –Kirchhoff’s Loop Law –Kirchhoff’s Junction Law Today: circuits with batteries, resistors, and capacitors
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RC Circuits l RC Circuits l Charging Capacitors l Discharging Capacitors l Intermediate Behavior
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RC Circuits l Circuits that have both resistors and capacitors: l With resistance in the circuits, capacitors do not charge and discharge instantaneously – it takes time (even if only fractions of a second). V R2R2 R1R1 C S S
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Capacitors l Charge on Capacitors cannot change instantly. l Short term behavior of Capacitor: è If the capacitor starts with no charge, it has no potential difference across it and acts as a wire. è If the capacitor starts with charge, it has a potential difference across it and acts as a battery. l Current through a Capacitor eventually goes to zero. l Long term behavior of Capacitor: è If the capacitor is charging, when fully charged no current flows and capacitor acts as an open circuit. è If capacitor is discharging, potential difference goes to zero and no current flows.
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Charging Capacitors l Example: an RC circuit with a switch l When switch is first closed… (short term behavior): è No charge on the capacitor since charge can not change instantly – the capacitor acts as a wire or short circuit l After switch has been closed for a while… (long term behavior): è No current flows through the capacitor – the capacitor acts as a break in the circuit or open circuit R C S
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Charging Capacitors l Capacitor is initially uncharged and switch is open. Switch is then closed. What is current in circuit immediately thereafter? l What is current in circuit a long time later? R C S
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ACT/Preflight 7.1 2R C R S2S2 Both switches are initially open, and the capacitor is uncharged. What is the current through the battery just after switch S 1 is closed? 1) I b = 02) I b = E /(3R) 3) I b = E /(2R)4) I b = E /R S1S1 KVL: - E + I(2R) + q/C = 0 q = 0 I = E /(2R) IbIb + - + + - - 34% 44% 6% 17% 20
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ACT/Preflight 7.3 Both switches are initially open, and the capacitor is uncharged. What is the current through the battery after switch 1 has been closed a long time?long time 1) I b = 02) I b = E /(3R) 3) I b = E /(2R)4) I b = E /R 2R C R S2S2 S1S1 IbIb + - + + - - Long time current through capacitor is zero I b =0 because the battery and capacitor are in series. KVL: - E + 0 + q /C = 0 q = E C 56% 28% 5% 11% 24
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Discharging Capacitors l Example: a charged RC circuit with a switch l When switch is first closed… (short term behavior): è Full charge is on the capacitor since charge can not change instantly – the capacitor acts as a battery l After switch has been closed for a while… (long term behavior): è No current flows through the capacitor – the capacitor is fully discharged R C S
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ACT/Preflight 7.5 After switch 1 has been closed for a long time, it is opened and switch 2 is closed. What is the current through the right resistor just after switch 2 is closed? 1) I R = 02) I R = V/(3R) 3) I R = V/(2R)4) I R = V/R KVL: -q 0 /C+IR = 0 Recall q is charge on capacitor after charging: q 0 =VC (since charged w/ switch 2 open!) -V + IR = 0 I = V/R 2R C R S2S2 S1S1 IRIR + - + + - - + - 32% 16% 15% 37% 42
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ACT: RC Circuits Both switches are closed. What is the final charge on the capacitor after the switches have been closed a long time? 1) Q = 02) Q = C E /3 3) Q = C E /24) Q = C E KVL (right loop): -Q/C+IR = 0 KVL (outside loop), - E + I(2R) + IR = 0 I = E /(3R) KVL: -Q/C + E /(3R) R = 0 Q = C E /3 R 2R C S2S2 S1S1 IRIR + - + + - - + - 27
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RC Circuits: Charging KVL: - + I(t)R + q(t) / C = 0 Just after…: q =q 0 –Capacitor is uncharged –- + I 0 R = 0 I 0 = / R Long time after: I c = 0 –Capacitor is fully charged –- + q /C =0 q = C Intermediate (more complex) q(t) = q (1-e -t/RC ) I(t) = I 0 e -t/RC C R S1S1 S2S2 + + + I - - - The switches are originally open and the capacitor is uncharged. Then switch S 1 is closed. t q RC 2RC 0 qq 1717
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RC Circuits: Discharging KVL: - q(t) / C - I(t) R = 0 Just after…: q=q 0 –Capacitor is still fully charged –-q 0 / C - I 0 R = 0 I 0 = -q 0 / (RC) Long time after: I c =0 –Capacitor is discharged (like a wire) –-q / C = 0 q = 0 Intermediate (more complex) q(t) = q 0 e -t/RC I c (t) = I 0 e -t/RC C R S1S1 - + + I - + - S2S2 q RC2RC t 40
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What is the time constant? l The time constant = RC. l Given a capacitor starting with no charge, the time constant is the amount of time an RC circuit takes to charge a capacitor to about 63.2% of its final value. l The time constant is the amount of time an RC circuit takes to discharge a capacitor by about 63.2% of its original value.
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Time Constant Demo Which system will be brightest? Which lights will stay on longest? Which lights consumes more energy? 2 Each circuit has a 1 F capacitor charged to 100 Volts. When the switch is closed: 1 = 2RC = RC/2 2 I=2V/R 1 Same U=1/2 CV 2 50
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Summary of Concepts l Charging Capacitors è Short Term: capacitor has no charge, no potential difference, acts as a wire è Long Term: capacitor fully charged, no current flows through capacitor, acts as an open circuit l Discharging Capacitors è Short Term: capacitor is fully charged, potential difference is a maximum, acts as a battery è Long Term: capacitor is fully discharged, potential difference is zero, no current flows l Intermediate Behavior è Charge & Current exponentially approach their long-term values è = RC
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Charging: Intermediate Times 2R C R S2S2 S1S1 IbIb + - + + - - Calculate the charge on the capacitor 3 10 -3 seconds after switch 1 is closed. q(t) = q (1-e -t/RC ) = q (1-e - 3 10 -3 /(20 100 10 -6) ) ) = q (0.78) Recall q = C = (50)(100x10 -6 ) (0.78) = 3.9 x10 -3 Coulombs R = 10 V = 50 Volts C = 100 F 38
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Practice! Calculate current immediately after switch is closed: Calculate current after switch has been closed for 0.5 seconds: Calculate current after switch has been closed for a long time: Calculate charge on capacitor after switch has been closed for a long time: R C E S1S1 R=10 C=30 mF E =20 Volts - E + I 0 R + q 0 /C = 0 I + + + - - - - E + I 0 R + 0 = 0 I 0 = E /R After a long time current through capacitor is zero! - E + IR + q ∞ /C = 0 - E + 0 + q ∞ /C = 0 q ∞ = E C 32
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ACT: RC Challenge 1) 0.368 q 0 2) 0.632 q 0 3) 0.135 q 0 4) 0.865 q 0 R C E 2R S1S1 E = 24 Volts R = 2 C = 15 mF After being closed for a long time, the switch is opened. What is the charge Q on the capacitor 0.06 seconds after the switch is opened? q(t) = q 0 e -t/RC = q 0 (e - 0.06 /(4 (15 10 -3 )) ) = q 0 (0.368) 45
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RC Summary ChargingDischarging q(t) = q (1-e -t/RC )q(t) = q 0 e -t/RC V(t) = V (1-e -t/RC )V(t) = V 0 e -t/RC I(t) = I 0 e -t/RC Short term: Charge doesn’t change (often zero or max) Long term: Current through capacitor is zero. Time Constant = RC Large means long time to charge/discharge 45
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