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Published byWalter Houston Modified over 9 years ago
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Transistor (BJT)
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Introduction BJT (Bipolar Junction Transistor) Vaccum tubes It comes because it is most advantageous in amplification Why it is called transistor? Transistor = Transfer + Resistor Why it is called BJT? Types of BJT
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Introduction(cont.) npnpnp npn B C pnp E B C Cross Section B C E Schematic Symbol B C E Collector doping is usually ~ 10 9Collector doping is usually ~ 10 9 Base doping is slightly higher ~ 10 10 – 10 11Base doping is slightly higher ~ 10 10 – 10 11 Emitter doping is much higher ~ 10 17Emitter doping is much higher ~ 10 17
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Junction Transistor Sandwich structure. Base is always in between E & C. B is lightly doped. E & C are heavily doped. E is more heavily doped than C and area of C is more than E. Two PN junctions. E B C BE CB E B C BE CB N-P-N P-N-P
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Unbiased transistor No external supply is applied. Penetration of depletion region (less in E & C, more in B)
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Transistor Biasing ModeBE junctionBC junction cutoffreverse biased reverse biased linear(active)forward biased reverse biased saturation forward biased forward biased Inverse active reverse biased forward biased
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Transistor Biasing (cont.) Transistor biasing in active region. EB junction is forward biased and CB junction is reversed biased.
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Transistor operation in active region (NPN) E B C N P N v
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9 Large current
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Transistor operation (cont.) Electrons will flow from E to B. Now electrons have three options 1.Recombine with holes (I B ) 2.Diffuse through base and out of the base connection. 3.Remaining e- will go in C (I c ).
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Transistor operation (cont.) E B C N P N Electrons emitted Electrons collected Recombination current Emitter current Collector current I E =I B +I C
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Transistor current Emitter current, Base current, Collector current. I E = I B + I C. (I E ≈ I C ) I E = I PE + I NE (for NPN I NE for PNP I PE ). I B = I PE - I PC. Reverse saturation current (I CBO ) : It is the reverse sat. current when EB junction is open. I C = I PC + I CBO.
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Parameters relating to current components
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Transistor as an amplifier Discussion of an amplification effect With E.g. for common-base configuration transistor:
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Transistor construction technologies Grown type. Alloy type. Electrochemically etched type. Diffusion type Epitaxial type.
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Transistor configuration Made one of three terminal common to i/p and o/p. Depending on which terminal is made common. There are three possibilities 1. Common base configuration (CB). 2. Common emitter configuration (CE). 3. Common collector configuration (CC).
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Common Base configuration (CB) V ee V cc ReRe RcRc IEIE IBIB ICIC V ee V cc ReRe RcRc IEIE IBIB ICIC Common base configuration for NPN transistor Common base configuration for PNP transistor
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Common Base configuration (CB) Input Output Current relations in CB configuration 1. I c = I C(INJ) + I CBO 2. I C(INJ) (practically) 3. I CBO (with emitter open) I CB= collector to base current I O = emitter is open
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Common Base configuration (CB) 4. current amplification factor/current gain (α dc ) α dc =I C(inj) /I E So I c = (α dc * I E ) + I CBO E xpression for I B : I B = (1- α)I E.
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Transistor char in CB configuration 1.Input char.2. Output char.3. Transfer char. I/P char : graph of I/P current versus I/P voltage. O/P char : graph of O/P current versus O/P voltage. Transfer char: graph of O/P current versus I/P current
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CB I/P char. I/P current is emitter current(I E ) and I/P voltage is emitter to base voltage(V BE ). 1. Its identical to VI char of diode in FB. 2. Up to cut-in V 3. I/P resistance 4. Effect of V CB on I/P VI char (Early effect) V CB = 4V V CB = 8V I E (mA) V BE
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Early effect / Base width modulation Effect on β and α. E BC E B C Increase V CB Total base width = width of depletion region at CB junction + width of region which contains free charge carriers
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Output char of transistor in CB ICICICIC Active Region Saturation Region Cutoff Region I B = 0 IEIEIEIE V CB Operating region 1.Cutoff region 2.Active region 3.Saturation region
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Output char of transistor in CB Cut off region : region below the curve I E =0 Active region : I C ≈ I E (Const. current source) Dynamic O/P resistance Saturation region Current controlled current source.
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Breakdown voltage and punch-through effect Increasing V CB causes CB junction to breakdown. Reach through / Punch through effect V CB ICIC E BC
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Potential variation through transistor Without biasing With external bias
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Transfer characteristic Linear rela.tionship ICIC IEIE
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Common Emitter (CE) configuration V cc V BE V CE RBRB RCRC V BB V BE V CE RCRC RBRB Common emitter config. for NPN transistor Common emitter config. for PNP transistor
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CE Configuration Input Output Current relation I E = I B + I C I C = α * I E + I CBO I C = I B (α/1- α) + I CBO / (1- α) But (α/1- α) = β So I C = I B * β + (β+1) I CBO I C = I B * β + I CEO
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CE Configuration Reverse leakage current in CE configuration (I CEO ) Thermal instability, so thermal stabilizing circuit is required. Relation between α and β. α = β/(1+ β) and β = α /(1- α)
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CE characteristics (Input) Same as conventional PN junction diode Dynamic i/p resistance Base current reduces as V CE increases. V CE = 8V V CE = 4V I B (μA) V BE
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CE characteristics (output) 1. Cut off region 2. Active region 3. Saturation region 4.Dynamic O/P resistance 5. Definition of β 6. Maximum VCE and breakdown
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Transfer characteristic Why CE o/p char is more sloping than CB o/p char??? ICIC IBIB V CE = 2V V CE = 5V
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Typical transistor junction voltage values Cutoff region Short-circuited base Open-circuited base Cut-in voltage Saturation voltage VoltageSi transistorGe transistor V BE (Cutoff) 0-0.1 V BE (Cut in) 0.50.1 V BE (active) 0.70.2 V BE (sat.)0.80.3 V CE (sat.)0.20.1
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Standard test for regions Saturation region 1. find I C, I B then check I B >= I C / β 2. measure V CB, positive for PNP and negative for NPN. Active region measure V BE = 0.7 and measure V CB is negative (reverse biased) Cutoff V BE is < 0.5 and V CB is negative
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Common collector configuration V cc V BC V EC RBRB RERE V BB V BC V ECs RERE RBRB
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Practical way to draw CC config. V CC O/P voltage I/P voltage
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Current relation I E = I B + I C I C = α * I E + I CBO I E = (β+1) * I B Current gain γ = I E /I B Maximum use of CC is for impedance matching (I/P is high and O/P is low).
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I/P char. And O/P char. V EC = 2V V EC = 1V I B (μA) V BC IEIEIEIE Active Region Saturation Region Cutoff Region I B = 0 IBIBIBIB V EC
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Transfer char. IE IBIB V CE = 2V V CE = 5V
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Comparison of configurations parameterCBCECC Common terminal between i/p and o/p BaseEmitterCollector I/P currentIEIE IBIB IBIB O/P currentICIC ICIC IEIE Current gainα = I C /I E β= I C /I B Γ= I E /I B I/P voltageV EB V BE V BC O/P voltageV CB V CE V EC
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Analytic expression for transistor char.
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Base spreading resistance E B C V CE V EB V CB V CB = V C + r bb * I B VEVE VCVC
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Ebers – moll model VEVE VCVC IEIE IBIB ICIC αI ICαI IC αN IEαN IE
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Ebers – moll model (cont.) I = I C + α N I E I C = - α N I E + I (I is diode current) VCVC αN IEαN IE ICIC I
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Why can’t we construct a transistor by connecting back to back diodes? VEVE VCVC
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Photo transistor Dark current 20 mW/(cm* cm) 40 mW/(cm* cm) 60 mW/(cm* cm) 80 mW/(cm* cm)
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Photo transistor (cont.) Advantages: Photo current multiplied by β High sensitivity Good switching speed No memory effect.
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Phototransistor (cont.) Disadvantages Not so fast as conventional transistor because of photo- conducting material Poor linearity Temperature sensitive device External voltage source is needed for operation
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