1. Entry Task: Feb 4 th Monday WRITE THE QUESTION DOWN Entry Task Question: How many moles are there in 2000 grams of water (2 liters)? You have 5 minutes!

2. Agenda: Discuss Mole Lab- Post Lab Mole Notes #3 particles to Moles to Grams H.W. Particles  Moles  Grams ws

3. I can… Calculate the molar mass of a compound. Calculate particles  moles  grams

4. MOLE NOTES#3

5. THE MOLE IS A BRIDGE BETWEEN THE MICROSCOPIC WORLD OF ATOMS AND THE MACROSCOPIC WORLD OF MATERIALS AND OBJECTS.

6. When converting from super tiny (particles, ions, molecules, compounds) we use mole as a bridge to the large (grams, liters, etc) Particles  MOLE  Grams

7. Microscopic World of Particles Atoms, Ions, Molecules, & Formula Units Macroscopic World of the Observable Grams, Liters, etc… MOLE BRIDGE Mass (grams) 1 mol = MW g

8. Order of Operations- The SET Up 1.Starting amount 2/3. Mole/particle conversion (1 mole = 6.02 x10 23 ) small thing 3/2. Gram/Mole conversion (1 mole = Molar mass (g))

9. Practice: Particles to Grams

10. The Set-up How many grams are in 2.74 x10 22 formula units of LiCl? 2.74 x 10 22 f.u of LiCl 1 mole of LiCl 6.02 x 10 23 f.u LiCl Place starting amount here 1 mole of LiCl 42.39 g of LiCl Mole/Particle Conversion Mole/Gram conversion

11. The Clean up How many grams are in 2.74 x10 22 formula units of LiCl? 2.74 x 10 22 f.u of LiCl 1 mole of LiCl 6.02 x 10 23 f.u LiCl CROSS OUT LABELS ACROSS FROM EACH OTHER ------------ ---------- = 19.3 x 10 -1 grams of LiCl (2.74)(42.394)/6.02 = 19.3 1 mole of LiCl 42.39 g of LiCl ------------ Now the exponents: then 10 22 – 10 23 = 10 -1 = 1.93 grams of LiCl

12. Particles to grams conversions How many grams are in 1.26 x 10 23 molecules of nitrogen gas? 1.26 x 10 23 molecules of N 2 1 mole of N 2 6.02 x 10 23 molecules N 2 Place starting amount here ---------- = 5.86 grams of N 2 (1.26)(28.0134)/6.02 = 5.86 then 10 23 – 10 23 = 10 0 N2N2 N= 14.0067 g X 2 = 28.0134 g 1 mole = 28.0134 grams 1 mole of N 2 28.0134 g of N 2 ------------ Mole/Particle Conversion Mole/Gram conversion

13. Particles to grams conversions How many grams are in a 4.39 x 10 23 ions of Br -1 ? 4.39 x 10 23 ions of Br 1 mole of Br 6.02 x 10 23 ions Br Place starting amount here Place conversion here ---------- = 5.83 x 10 1 grams of Br (4.39)(79.904)/6.02 = 58.3 then 10 23 – 10 23 = 10 0 Br-1 Br -1 = 79.904 g 1 mole of Br 79.904 g of Br ------------

14. Practice: Grams to particles

15. The Set-up How many formula units are there in 45.0 grams of LiCl? 45.0 g of LiCl 1 mole of LiCl 6.02 x 10 23 f.u LiCl Place starting amount here 1 mole of LiCl 42.39 g of LiCl Mole/Gram Conversion Mole/Particle conversion

16. The Clean up How many formula units are there in 45.0 grams of LiCl? 45.0 g of LiCl 1 mole of LiCl 6.02 x 10 23 f.u LiCl 1 mole of LiCl 42.39 g of LiCl CROSS OUT LABELS ACROSS FROM EACH OTHER ------------ (45.0)(6.02)/42.39 = 6.39 = 6.39 x 10 23 formula units of LiCl ------------

17. 28.0134 g of N 2 Particles to grams conversions How many molecules of nitrogen gas are there in 275 grams? 275 grams of N 2 1 mole of N 2 6.02 x 10 23 molecules N 2 Place starting amount here ---------- = 5.91 x 10 24 molecules of N 2 (275)(6.02)/28.0134 = 59.1 x 10 23 molecules of N 2 N2N2 N= 14.0067 g X 2 = 28.0134 g 1 mole = 28.0134 grams 1 mole of N 2 ------------ Mole/gram Conversion Mole/Particle conversion