2. If the following equations were graphed on the same set of axes, at which point would they intersect? Algebraically Graphically Y 1 = Y 2 = View the graph by pressing GRAPH Press 2ndCALC5 (intersect) Press ENTER The calculator calculates the first point of intersection. Repeat the same process. Be sure to move the curser closer to the second point before pressing enter. Solve the following system of equations algebraically.

3. Find the solution set of the following quadratic function. Rewrite the equation in ax 2 + bx + c = 0 format. Rewrite the equation so that a is positive. Factor the equation. Set each factor equal to zero and solve. Write the solution set. Which is the larger root of the following quadratic function? 4 is the larger root.

4. For what values of x is the following fraction undefined? If the denominator was equal to zero, the fraction would be undefined. The fraction would be undefined at Solve the following equation for x Cross-multiply. Rewrite the equation in ax 2 + bx + c = 0 format. Factor the equation.

5. A ball is thrown in the air so that its height, h, in feet after t seconds is given by the equation a. Find the number of seconds that the ball is in the air when it reaches a height of 128 feet. b. After how many seconds will the ball hit the ground? The ball reaches 128 feet at 1 second and at 8 seconds. The ball hits the ground after 9 seconds. Maybe we should check this on our calculator.

6. Stanley has 660 yards of fencing that he wishes to use to enclose a rectangular garden. If all the fencing is used, what is the maximum area of the garden that can be enclosed? Let x represent the length and let w represent the width. Since all the fencing must be used, the perimeter of the garden will be 660 yards, and we can use the following equation. x 330 - x Let A( x ) represent the area of the rectangle. The maximum value occurs at The maximum area is 27,225 yards 2.

7. Which is an equation of the parabola shown in the accompanying figure? (1)y = –x 2 + 2x + 3 (3) y = x 2 + 2x + 3 (2) y = –x 2 – 2x + 3 (4) y = x 2 – 2x + 3 (1)y = –x 2 + 4x + 1 (3) y = x 2 + 4x + 1 (2) y = –x 2 – 4x + 1 (4) y = x 2 – 4x + 1