2. -Nice neat notes that are legible and use indentations when appropriate.

3. -Nice neat notes that are legible and use indentations when appropriate. -Example of indent.

4. -Nice neat notes that are legible and use indentations when appropriate. -Example of indent. -Skip a line between topics

5. -Nice neat notes that are legible and use indentations when appropriate. -Example of indent. -Skip a line between topics -Make visuals clear and well drawn.

6. -Nice neat notes that are legible and use indentations when appropriate. -Example of indent. -Skip a line between topics -Make visuals clear and well drawn. Please label. Effort Arm Resistance Arm

7. Speed: A measure of motion, = distance divided by time. D/T Speed: A measure of motion, = distance divided by time. D/T Copyright © 2010 Ryan P. Murphy

8. Speed: A measure of motion, = distance divided by time. D/T Speed: A measure of motion, = distance divided by time. D/T Copyright © 2010 Ryan P. Murphy Speed is the rate of motion, or the rate of change of position.

9. Speed: A measure of motion, = distance divided by time. D/T Speed: A measure of motion, = distance divided by time. D/T Copyright © 2010 Ryan P. Murphy Speed is the rate of motion, or the rate of change of position. Can only be zero or positive.

10. Distance = Speed ● Time

14. How far did Joe walk if he walked a steady 4 km/h for three straight hours?

15. Distance = Speed ● Time

16. How far did Joe walk if he walked a steady 4 km/h for three straight hours? Distance = Speed ● Time Distance = 4 km/h ● 3 h

17. How far did Joe walk if he walked a steady 4 km/h for three straight hours? Distance = Speed ● Time Distance = 4 km/h ● 3 h Distance =

18. How far did Joe walk if he walked a steady 4 km/h for three straight hours? Distance = Speed ● Time Distance = 4 km/h ● 3 h Distance = 12 km

19. Distance Speed = --------------- Time

20. What is Joes speed if he walked a steady 5 km in one hour? Rate / Speed R =

21. What is Joes speed if he walked a steady 5 km in one hour? Rate / Speed R = 5 km 1 hour or 5 km/hr

22. What is Joes speed if he walked 5 km in one hour? Rate / Speed R = 5 km 1 hour or 5 km/hr

23. Juan travels 300km in 6hrs. Find his average speed in km/h.

24. Speed = Distance / Time

25. Juan travels 300km in 6hrs. Find his average speed in km/h. Speed = Distance / Time 300km Speed = ------------ = 50 km/h 6h

26. Juan travels 300km in 6hrs. Find his average speed in km/h. Speed = Distance / Time 300km 50km Speed = ------------ = --------- 6h h

27. Distance Time = --------------- Speed

28. Marlene drove 500 km at an average speed of 50 km/h? How long did she drive?

29. Time = Distance / Speed

30. Marlene drove 500 km at an average speed of 50 km/h? How long did she drive? Time = Distance / Speed 500km Time = ------------ = _____h 50km/h

31. Marlene drove 500 km at an average speed of 50 km/h? How long did she drive? Time = Distance / Speed 500km Time = ------------ = _____h 50km/h

32. Marlene drove 500 km at an average speed of 50 km/h? How long did she drive? Time = Distance / Speed 500km Time = ------------ = 10h 50km/h

33. Velocity = (distance / time) and direction. Velocity = (distance / time) and direction. Copyright © 2010 Ryan P. Murphy

34. Velocity = –S is replaced with V because velocity is speed and direction. Copyright © 2010 Ryan P. Murphy

35. What’s Joes velocity if he walked 4 kilometers East in one hour? 4 km East 4 km V = ----------- = 4 km/hr/east 1 hour Copyright © 2010 Ryan P. Murphy

36. What’s Joes velocity if he walked 4 kilometers East in one hour? 4 km East 4km km V = ----------- = 4 hr/east 1 hour Copyright © 2010 Ryan P. Murphy 4 km hr East

37. Velocity deals with displacement. –Displacement measures where you end up relative to where you started. Copyright © 2010 Ryan P. Murphy 4m 8m

38. Velocity deals with displacement. –Displacement measures where you end up relative to where you started. Copyright © 2010 Ryan P. Murphy

39. Velocity deals with displacement. –Displacement measures where you end up relative to where you started. Copyright © 2010 Ryan P. Murphy

40. Velocity deals with displacement. –Displacement measures where you end up relative to where you started. Copyright © 2010 Ryan P. Murphy

41. Velocity deals with displacement. –Displacement measures where you end up relative to where you started. Copyright © 2010 Ryan P. Murphy 50m 60m 30m 100m

42. Velocity deals with displacement. –Displacement measures where you end up relative to where you started. Copyright © 2010 Ryan P. Murphy 50m 60m 30m 100m

43. Velocity deals with displacement. –Displacement measures where you end up relative to where you started. Copyright © 2010 Ryan P. Murphy 50m 60m 30m 100m 178.88m 80m

44. Find the displacement. Copyright © 2010 Ryan P. Murphy

45. Find the displacement. Copyright © 2010 Ryan P. Murphy

46. Find the displacement. Copyright © 2010 Ryan P. Murphy 50m 10m 20m 100m

47. The speed of the car is 80 km / hr. Copyright © 2010 Ryan P. Murphy

48. The velocity of the car is 80 km / hr / West. Copyright © 2010 Ryan P. Murphy

49. The velocity of the plane is 300 km / hr / West. Copyright © 2010 Ryan P. Murphy

50. The velocity of the plane is 300 km / hr / West. Copyright © 2010 Ryan P. Murphy

51. The velocity of the plane is 300 km / hr / West. Copyright © 2010 Ryan P. Murphy

52. The speed of the plane is 300 km / hr

53. Copyright © 2010 Ryan P. Murphy The speed of the plane is 300 km / hr

54. Copyright © 2010 Ryan P. Murphy The speed of the plane is 300 km / hr Speed and Velocity Calculations and problems. Learn more at…. http://www2.franciscan.edu/academic/mathsci/mathscienceinte gation/MathScienceIntegation-827.htm http://www2.franciscan.edu/academic/mathsci/mathscienceinte gation/MathScienceIntegation-827.htm

55. It took Lightning McGreen 2.5 hours to travel 600 kilometers. –How fast was he going in Kilometers an hour? Copyright © 2010 Ryan P. Murphy

56. Forces in Motion, Speed, Velocity, Acceleration and more available sheet.

57. It took Lightning McGreen 2.5 hours to travel 600 kilometers. –How fast was he going in Kilometers an hour? Copyright © 2010 Ryan P. Murphy

58. It took Lightning McGreen 2.5 hours to travel 600 kilometers. –How fast was he going in Kilometers an hour? Copyright © 2010 Ryan P. Murphy

59. It took Lightning McGreen 2.5 hours to travel 600 kilometers. –How fast was he going in Kilometers an hour? Copyright © 2010 Ryan P. Murphy Speed = Distance / Time

60. It took Lightning McGreen 2.5 hours to travel 600 kilometers. –How fast was he going in Kilometers an hour? Copyright © 2010 Ryan P. Murphy Speed = Distance / Time

61. It took Lightning McGreen 2.5 hours to travel 600 kilometers. –How fast was he going in Kilometers an hour? Copyright © 2010 Ryan P. Murphy Speed = Distance / Time Speed = 600 km / 2.5 h

62. It took Lightning McGreen 2.5 hours to travel 600 kilometers. –How fast was he going in Kilometers an hour? Copyright © 2010 Ryan P. Murphy Speed = Distance / Time Speed = 600 km / 2.5 h Speed = 240 km/h

63. Answer: 240 km/h –Speed is distance over time. Copyright © 2010 Ryan P. Murphy

64. Forces in Motion, Speed, Velocity, Acceleration and more available sheet.

65. It took Ms. Rally 4 hours to travel 165 kilometers due North. –What was the velocity of her car in Kilometers an hour? Copyright © 2010 Ryan P. Murphy

66. It took Ms. Rally 4 hours to travel 165 kilometers due North. –What was the velocity of her car in Kilometers an hour? Copyright © 2010 Ryan P. Murphy

67. It took Ms. Rally 4 hours to travel 165 kilometers due North. –What was the velocity of her car in Kilometers an hour? Copyright © 2010 Ryan P. Murphy

68. It took Ms. Rally 4 hours to travel 165 kilometers due North. –What was the velocity of her car in Kilometers an hour? Copyright © 2010 Ryan P. Murphy

69. It took Ms. Rally 4 hours to travel 165 kilometers due North. –What was the velocity of her car in Kilometers an hour? Copyright © 2010 Ryan P. Murphy Velocity = Distance / Time

70. It took Ms. Rally 4 hours to travel 165 kilometers due North. –What was the velocity of her car in Kilometers an hour? Copyright © 2010 Ryan P. Murphy Velocity = Distance / Time Velocity = 165km / 4 h

71. It took Ms. Rally 4 hours to travel 165 kilometers due North. –What was the velocity of her car in Kilometers an hour? Copyright © 2010 Ryan P. Murphy Velocity = Distance / Time Velocity = 165km / 4 h Velocity = 41.25 km/h/North

72. Answer: 41.25 km / h / North –Velocity is distance over time and direction. Copyright © 2010 Ryan P. Murphy

73. Forces in Motion, Speed, Velocity, Acceleration and more available sheet.

74. What is the speed if the distance was 340 km and the time was 3 hours? –Was Jater speeding? Copyright © 2010 Ryan P. Murphy

75. What is the speed if the distance was 340 km and the time was 3 hours? –Was Jater speeding? Copyright © 2010 Ryan P. Murphy

76. What is the speed if the distance was 340 km and the time was 3 hours? –Was Jater speeding? Copyright © 2010 Ryan P. Murphy

77. What is the speed if the distance was 340 km and the time was 3 hours? –Was Jater speeding? Copyright © 2010 Ryan P. Murphy

78. What is the speed if the distance was 340 km and the time was 3 hours? –Was Jater speeding? Copyright © 2010 Ryan P. Murphy Speed = Distance / Time

79. What is the speed if the distance was 340 km and the time was 3 hours? –Was Jater speeding? Copyright © 2010 Ryan P. Murphy Speed = Distance / Time Speed = 340km / 3 h

80. What is the speed if the distance was 340 km and the time was 3 hours? –Was Jater speeding? Copyright © 2010 Ryan P. Murphy Speed = Distance / Time Speed = 340km / 3 h Speed = 113km/h

81. 340 km / 3 hours = 113km/h –Jater was speeding. Copyright © 2010 Ryan P. Murphy

82. Forces in Motion, Speed, Velocity, Acceleration and more available sheet.

83. How far did Doc Budson travel if he was going 60 kilometers an hour for 4 straight hours? Copyright © 2010 Ryan P. Murphy

84. How far did Doc Budson travel if he was going 60 kilometers an hour for 4 straight hours? Copyright © 2010 Ryan P. Murphy

85. How far did Doc Budson travel if he was going 60 kilometers an hour for 4 straight hours? Copyright © 2010 Ryan P. Murphy

86. How far did Doc Budson travel if he was going 60 kilometers an hour for 4 straight hours? Copyright © 2010 Ryan P. Murphy

87. How far did Doc Budson travel if he was going 60 kilometers an hour for 4 straight hours? Copyright © 2010 Ryan P. Murphy Distance = Speed ● Time

88. How far did Doc Budson travel if he was going 60 kilometers an hour for 4 straight hours? Copyright © 2010 Ryan P. Murphy Distance = Speed ● Time Distance = 60km/h ● 4 h

89. How far did Doc Budson travel if he was going 60 kilometers an hour for 4 straight hours? Copyright © 2010 Ryan P. Murphy Distance = Speed ● Time Distance = 60km/h ● 4 h

90. In this case, we just multiply the distance traveled by the time. 60 km/h times 4 hours. Copyright © 2010 Ryan P. Murphy

91. 60 km times 4 hours = 240 km –Check your work, 240/4 should be 60. Copyright © 2010 Ryan P. Murphy

92. Forces in Motion, Speed, Velocity, Acceleration and more available sheet.

93. What is the speed if a runner runs a distance of 400 meters in 43 seconds. Copyright © 2010 Ryan P. Murphy

94. What is the speed if a runner runs a distance of 400 meters in 43 seconds. Copyright © 2010 Ryan P. Murphy

95. What is the speed if a runner runs a distance of 400 meters in 43 seconds. Copyright © 2010 Ryan P. Murphy

96. What is the speed if a runner runs a distance of 400 meters in 43 seconds. Copyright © 2010 Ryan P. Murphy

97. What is the speed if a runner runs a distance of 400 meters in 43 seconds. Copyright © 2010 Ryan P. Murphy Speed = Distance / Time

98. What is the speed if a runner runs a distance of 400 meters in 43 seconds. Copyright © 2010 Ryan P. Murphy Speed = Distance / Time Speed = 400m / 43s

99. What is the speed if a runner runs a distance of 400 meters in 43 seconds. Copyright © 2010 Ryan P. Murphy Speed = Distance / Time Speed = 400m / 43s Speed = 9.30 m/s

100. 400m / 43s = 9.30 m/s Copyright © 2010 Ryan P. Murphy

101. Forces in Motion, Speed, Velocity, Acceleration and more available sheet.

102. Activity! Looking for the Violators.

103. Safety is a big concern here. Students need to be far from road. Outside behavior must be excellent. Safety is a big concern here. Students need to be far from road. Outside behavior must be excellent.

104. Activity! Looking for the Violators. Safety is a big concern here. Students need to be far from road. Outside behavior must be excellent. Safety is a big concern here. Students need to be far from road. Outside behavior must be excellent. We also must try to conceal ourselves at all time. We do not want anyone to see us / slow down. We also must try to conceal ourselves at all time. We do not want anyone to see us / slow down.

105. Activity! Optional –Teacher measures out 300 feet along road and puts a cone at the start and finish a short distance from the roads edge. –From a distance, students use a stopwatch to time the speed of cars from the start cone to the finish cone. –Speed = Distance (300 ft) divided by time (ft/sec.) –Multiply by.681 (ft/sec to mph conversion) = mph –Over 30 mph is speeding in the village. –Create list of all the speeds and then average. –Does the village have a speeding problem?

106. Activity! Optional –Teacher measures out 300 feet along road and puts a cone at the start and finish a short distance from the roads edge. –From a hidden distance, students use a stopwatch to time the speed of cars from the start cone to the finish cone. –Speed = Distance (300 ft) divided by time (ft/sec.) –Multiply by.681 (ft/sec to mph conversion) = mph –Over 30 mph is speeding in the village. –Create list of all the speeds and then average. –Does the village have a speeding problem?

107. Activity! Optional –Teacher measures out 300 feet along road and puts a cone at the start and finish a short distance from the roads edge. –From a hidden distance, students use a stopwatch to time the speed of cars from the start cone to the finish cone. –Speed = Distance (300 ft) divided by time (ft/s.) –Multiply by.681 (ft/sec to mph conversion) = mph –Over 30 mph is speeding in the village. –Create list of all the speeds and then average. –Does the village have a speeding problem?

108. Activity! Optional –Teacher measures out 300 feet along road and puts a cone at the start and finish a short distance from the roads edge. –From a hidden distance, students use a stopwatch to time the speed of cars from the start cone to the finish cone. –Speed = Distance (300 ft) divided by time (ft/s.) –Multiply by.681 (ft/sec to mph conversion) = mph –Over 30 mph is speeding in the village. –Create list of all the speeds and then average. –Does the village have a speeding problem?

109. Activity! Optional –Teacher measures out 300 feet along road and puts a cone at the start and finish a short distance from the roads edge. –From a hidden distance, students use a stopwatch to time the speed of cars from the start cone to the finish cone. –Speed = Distance (300 ft) divided by time (ft/s.) –Multiply by.681 (ft/sec to mph conversion) = mph –Over 30 mph is speeding in the village. –Create list of all the speeds and then average. –Does the village have a speeding problem?

110. Activity! Optional –Teacher measures out 300 feet along road and puts a cone at the start and finish a short distance from the roads edge. –From a hidden distance, students use a stopwatch to time the speed of cars from the start cone to the finish cone. –Speed = Distance (300 ft) divided by time (ft/s.) –Multiply by.681 (ft/sec to mph conversion) = mph –Over 30 mph is speeding in the village. –Create list of all the speeds and then average. –Does the village have a speeding problem?

111. Activity! Optional –Teacher measures out 300 feet along road and puts a cone at the start and finish a short distance from the roads edge. –From a hidden distance, students use a stopwatch to time the speed of cars from the start cone to the finish cone. –Speed = Distance (300 ft) divided by time (ft/s.) –Multiply by.681 (ft/sec to mph conversion) = mph –Over 30 mph is speeding in the village. –Create list of all the speeds and then average. –Does the town have a speeding problem?

115. Note: This is nice to know. Average vs. Instantaneous Velocity –Instantaneous Velocity: When an object starts and then speeds up (not moving at one steady speed).

116. Note: This is nice to know. Average vs. Instantaneous Velocity –Instantaneous Velocity: When an object starts and then speeds up (not moving at one steady speed). Instantaneous Velocity Definition: The velocity of an object at any given instant (especially that of an accelerating object); the limit of the change in position per unit time as the unit of time approaches zero; expressed mathematically

117. Note: This is nice to know. Average vs. Instantaneous Velocity –Instantaneous Velocity: When an object starts and then speeds up (not moving at one steady speed). Instantaneous Velocity Definition: The velocity of an object at any given instant (especially that of an accelerating object); the limit of the change in position per unit time as the unit of time approaches zero; expressed mathematically

118. Average: The result obtained by adding several quantities together and then dividing this total by the number of quantities; the mean

119. Average: The result obtained by adding several quantities together and then dividing this total by the number of quantities; the mean.

120. Acceleration = The rate of change in velocity. (m/s) Acceleration = The rate of change in velocity. (m/s) Copyright © 2010 Ryan P. Murphy

123. Or… a = (v 2 − v 1 )/(t 2 − t 1 )

125. Acceleration is measured by taking the change in velocity of an object divided by the time to change that velocity:

129. Video Link! Speed, Velocity, Acceleration –Be proactive, sketch problems in journal as completed in video. –http://www.youtube.com/watch_popup?v=rZo 8-ihCA9Ehttp://www.youtube.com/watch_popup?v=rZo 8-ihCA9E

130. Acceleration = The final velocity – the starting velocity, divided by time. Acceleration = The final velocity – the starting velocity, divided by time. Copyright © 2010 Ryan P. Murphy

131. Acceleration = The final velocity – the starting velocity, divided by time. Acceleration = The final velocity – the starting velocity, divided by time. Copyright © 2010 Ryan P. Murphy

132. Acceleration = The final velocity – the starting velocity, divided by time. Acceleration = The final velocity – the starting velocity, divided by time. Copyright © 2010 Ryan P. Murphy

133. Acceleration = The final velocity – the starting velocity, divided by time. Acceleration = The final velocity – the starting velocity, divided by time. Copyright © 2010 Ryan P. Murphy

134. Video Link (Optional) 100 meter final London Summer Games (Note Bolt’s acceleration) –http://www.youtube.com/watch?v=2O7K-8G2nwU (Skip ahead to 4:15 for race)http://www.youtube.com/watch?v=2O7K-8G2nwU

135. Forces in Motion, Speed, Velocity, Acceleration and more available sheet.

136. Ratman's rat mobile is traveling at 80m/s North when it turns on its rocket boosters accelerating the rat mobile to 200 m/s in 4 seconds. –What’s the rat mobiles acceleration? Copyright © 2010 Ryan P. Murphy

137. Ratman's rat mobile is traveling at 80m/s North when it turns on its rocket boosters accelerating the rat mobile to 200 m/s in 4 seconds. –What’s the rat mobiles acceleration? Copyright © 2010 Ryan P. Murphy

138. Ratman's rat mobile is traveling at 80m/s North when it turns on its rocket boosters accelerating the rat mobile to 200 m/s in 4 seconds. –What’s the rat mobiles acceleration? Copyright © 2010 Ryan P. Murphy

139. Ratman's rat mobile is traveling at 80m/s North when it turns on its rocket boosters accelerating the rat mobile to 200 m/s in 4 seconds. –What’s the rat mobiles acceleration? Copyright © 2010 Ryan P. Murphy 200 m/s80 m/s 4 s

140. Ratman's rat mobile is traveling at 80m/s North when it turns on its rocket boosters accelerating the rat mobile to 200 m/s in 4 seconds. –What’s the rat mobiles acceleration? Copyright © 2010 Ryan P. Murphy 120 m/s 4 s

141. Ratman's rat mobile is traveling at 80m/s North when it turns on its rocket boosters accelerating the rat mobile to 200 m/s in 4 seconds. –What’s the rat mobiles acceleration? Copyright © 2010 Ryan P. Murphy

142. Ratman's rat mobile is traveling at 80m/s North when it turns on its rocket boosters accelerating the rat mobile to 200 m/s in 4 seconds. –What’s the rat mobiles acceleration? The formula for acceleration is: a = (Final velocity – starting velocity) / time. Copyright © 2010 Ryan P. Murphy

143. Ratman's rat mobile is traveling at 80m/s North when it turns on its rocket boosters accelerating the rat mobile to 200 m/s in 4 seconds. –What’s the rat mobiles acceleration? The formula for acceleration is: a = (Final velocity – starting velocity) / time. a = 200m/s -80m/s / 4 s = Copyright © 2010 Ryan P. Murphy

144. Ratman's rat mobile is traveling at 80m/s North when it turns on its rocket boosters accelerating the rat mobile to 200 m/s in 4 seconds. –What’s the rat mobiles acceleration? The formula for acceleration is: a = (Final velocity – starting velocity) / time. a = 200m/s -80m/s / 4 s = a = 120 m/s / 4 s = Copyright © 2010 Ryan P. Murphy

145. Ratman's rat mobile is traveling at 80m/s North when it turns on its rocket boosters accelerating the rat mobile to 200 m/s in 4 seconds. –What’s the rat mobiles acceleration? The formula for acceleration is: a = (Final velocity – starting velocity) / time. a = 200m/s -80m/s / 4 s = a = 120 m/s / 4 s = 30 m/s Copyright © 2010 Ryan P. Murphy

146. Ratman's rat mobile is traveling at 80m/s North when it turns on its rocket boosters accelerating the rat mobile to 200 m/s in 4 seconds. –What’s the rat mobiles acceleration? The formula for acceleration is: a = (Final velocity – starting velocity) / time. a = 200m/s -80m/s / 4 s = a = 120 m/s / 4 s = 30 m/s North Copyright © 2010 Ryan P. Murphy

147. A car traveling at 10 m/s starts to decelerate steadily. It comes to a complete stop in 20 seconds. –What is its acceleration / deceleration? Copyright © 2010 Ryan P. Murphy a = (v 2 − v 1 ) t

148. A car traveling at 10 m/s starts to decelerate steadily. It comes to a complete stop in 20 seconds. –What is its acceleration / deceleration? Copyright © 2010 Ryan P. Murphy a = (v 2 − v 1 ) t 0 m/s 10 m/s 20 s

149. A car traveling at 10 m/s starts to decelerate steadily. It comes to a complete stop in 20 seconds. –What is its acceleration / deceleration? Copyright © 2010 Ryan P. Murphy a = (v 2 − v 1 ) t 10 m/s 20 s

150. A car traveling at 10 m/s starts to decelerate steadily. It comes to a complete stop in 20 seconds. –What is its acceleration / deceleration? Copyright © 2010 Ryan P. Murphy a = (v 2 − v 1 ) t 10 m/s 20 s -.5 m/s

151. Forces in Motion, Speed, Velocity, Acceleration and more available sheet.

152. A unicyclist was traveling at 2 m/s South and speed up to 6 m/s in 3 seconds. –What was the acceleration? Copyright © 2010 Ryan P. Murphy

153. A unicyclist was traveling at 2 m/s South and speed up to 6 m/s in 3 seconds. –What was the acceleration? Copyright © 2010 Ryan P. Murphy

154. A unicyclist was traveling at 2 m/s South and speed up to 6 m/s in 3 seconds. –What was the acceleration? Copyright © 2010 Ryan P. Murphy

155. The final velocity (6 m/s) minus the starting velocity (2 m/s) South divided by the time (3 seconds) = acceleration. Copyright © 2010 Ryan P. Murphy 6 m/s – 2m/s 3s – 0s

156. The final velocity (6 m/s) minus the starting velocity (2 m/s) South divided by the time (3 seconds) = acceleration. Copyright © 2010 Ryan P. Murphy 4 m/s 3s

157. The final velocity (6 m/s) minus the starting velocity (2 m/s) South divided by the time (3 seconds) = acceleration. Copyright © 2010 Ryan P. Murphy 4 m/s 3s = 1.333 m/s South

158. Copyright © 2010 Ryan P. Murphy Acceleration: Learn more at… http://www.physicsclassroom.com/class/1dkin/u1l1e.cfm http://www.physicsclassroom.com/class/1dkin/u1l1e.cfm

159. Video Link! Khan Academy. Acceleration. (Optional) complete problems as he does. –Be active in your learning not passive. –http://www.khanacademy.org/science/physics/ mechanics/v/accelerationhttp://www.khanacademy.org/science/physics/ mechanics/v/acceleration Copyright © 2010 Ryan P. Murphy

160. Deceleration: To slow velocity. Deceleration: To slow velocity. - Copyright © 2010 Ryan P. Murphy

161. Deceleration: To slow velocity. Deceleration: To slow velocity. Formula is the same as acceleration but will be a negative value. Formula is the same as acceleration but will be a negative value. Copyright © 2010 Ryan P. Murphy

162. Deceleration: To slow velocity. Deceleration: To slow velocity. Formula is the same as acceleration but will be a negative value. Formula is the same as acceleration but will be a negative value. Copyright © 2010 Ryan P. Murphy Note: There is no "deceleration", only negative acceleration

163. The formula is the same, but the value will be a negative. –Deceleration = (final velocity – starting velocity) divided by time. Copyright © 2010 Ryan P. Murphy

164. Forces in Motion, Speed, Velocity, Acceleration and more available sheet.

165. Lightning McGreen was traveling 200 m/s West when he slowed to 50 m/s in 10 seconds. –What was his deceleration? Copyright © 2010 Ryan P. Murphy

166. Lightning McGreen was traveling 200 m/s West when he slowed to 50 m/s in 10 seconds. –What was his deceleration? Copyright © 2010 Ryan P. Murphy

167. The final velocity (50 m/s) minus the starting velocity (200 m/s) divided by 10 seconds. Copyright © 2010 Ryan P. Murphy 50 m/s - 200 m/s 10s – 0s

168. The final velocity (50 m/s) minus the starting velocity (200 m/s) divided by 10 seconds. Copyright © 2010 Ryan P. Murphy 150 m/s 10s

169. The final velocity (50 m/s) minus the starting velocity (200 m/s) divided by 10 seconds. Copyright © 2010 Ryan P. Murphy 150 m/s 10s Deceleration = -15 m/s

170. The final velocity (50 m/s) minus the starting velocity (200 m/s) divided by 10 seconds. Copyright © 2010 Ryan P. Murphy 150 m/s 10s Deceleration = -15 m/s West

171. The final velocity (50 m/s) minus the starting velocity (200 m/s) divided by 10 seconds. Copyright © 2010 Ryan P. Murphy 150 m/s 10s Deceleration = -15 m/s West

172. The final velocity (50 m/s) minus the starting velocity (200 m/s) divided by 10 seconds. Copyright © 2010 Ryan P. Murphy 150 m/s 10s Deceleration = -15 m/s West

173. The final velocity (50 m/s) minus the starting velocity (200 m/s) divided by 10 seconds. Copyright © 2010 Ryan P. Murphy 150 m/s 10s Deceleration = -15 m/s West

174. The final velocity (50 m/s) minus the starting velocity (200 m/s) divided by 10 seconds. Copyright © 2010 Ryan P. Murphy 150 m/s 10s Deceleration = -15 m/s West

175. Momentum: A measure of the motion of a body equal to the product of its mass and velocity. Momentum: A measure of the motion of a body equal to the product of its mass and velocity. Copyright © 2010 Ryan P. Murphy

176. Momentum = Mass * Velocity. Momentum = Mass * Velocity. Copyright © 2010 Ryan P. Murphy p = m v

177. Momentum = Mass * Velocity. Momentum = Mass * Velocity. Copyright © 2010 Ryan P. Murphy p = m v Momentum Mass kg Velocity m/s

178. Momentum = ? Copyright © 2010 Ryan P. Murphy

179. Video Link! Momentum (Optional) –http://www.youtube.com/watch?v=edcpZoM5xmohttp://www.youtube.com/watch?v=edcpZoM5xmo Copyright © 2010 Ryan P. Murphy

180. Forces in Motion, Speed, Velocity, Acceleration and more available sheet.

181. What is the momentum of Fred if he weighs 3000 kg and is traveling with a velocity of 20 m/s / West? Copyright © 2010 Ryan P. Murphy

182. What is the momentum of Fred if he weighs 3000 kg and is traveling with a velocity of 20 m/s / West? Copyright © 2010 Ryan P. Murphy p = m v

183. What is the momentum of Fred if he weighs 3000 kg and is traveling with a velocity of 20 m/s / West? Copyright © 2010 Ryan P. Murphy p = m v Momentum = 3000 kg 20/m/s/ West

184. What is the momentum of Fred if he weighs 3000 kg and is traveling with a velocity of 20 m/s / West? Copyright © 2010 Ryan P. Murphy p = m v Momentum = 3000 kg 20/m/s/ West Momentum =

185. What is the momentum of Fred if he weighs 3000 kg and is traveling with a velocity of 20 m/s / West? Copyright © 2010 Ryan P. Murphy p = m v Momentum = 3000 kg 20/m/s/ West Momentum = 60,000 kg/m/s West

186. What is the momentum of Fred if he weighs 3000 kg and is traveling with a velocity of 20 m/s / West? Copyright © 2010 Ryan P. Murphy p = m v Momentum = 3000 kg 20/m/s/ West Momentum = 60,000 kg/m/s West

187. What is the momentum of Fred if he weighs 3000 kg and is traveling with a velocity of 20 m/s / West? Copyright © 2010 Ryan P. Murphy p = m v Momentum = 3000 kg 20/m/s/ West Momentum = 60,000 kg/m/s West Momentum = 6 x 10 4 kg/m/s West

188. Momentum = 60,000 kg/m/s Copyright © 2010 Ryan P. Murphy Momentum. Learn more at… http://www.physicsclassroom.com/class/mom entum/u4l1a.cfm http://www.physicsclassroom.com/class/mom entum/u4l1a.cfm

189. Forces in Motion, Speed, Velocity, Acceleration and more available sheet.

190. Chick Licks weighs 1000 kg and had a velocity of 20 m/s North. –What was his momentum? Copyright © 2010 Ryan P. Murphy

191. Chick Licks weighs 1000 kg and had a velocity of 20 m/s North. –What was his momentum? Copyright © 2010 Ryan P. Murphy p = m v

192. Chick Licks weighs 1000 kg and had a velocity of 20 m/s North. –What was his momentum? Copyright © 2010 Ryan P. Murphy p = m v Momentum = 1000 kg 20/m/s/ North

193. Chick Licks weighs 1000 kg and had a velocity of 20 m/s North. –What was his momentum? Copyright © 2010 Ryan P. Murphy p = m v Momentum = 1000 kg 20/m/s/ North Momentum = 20,000 kg/m/s North

194. Chick Licks weighs 1000 kg and had a velocity of 20 m/s North. –What was his momentum? Copyright © 2010 Ryan P. Murphy p = m v Momentum = 1000 kg 20/m/s/ North Momentum = 20,000 kg/m/s North

195. Chick Licks weighs 1000 kg and had a velocity of 20 m/s North. –What was his momentum? Copyright © 2010 Ryan P. Murphy p = m v Momentum = 1000 kg 20/m/s/ North Momentum = 20,000 kg/m/s North Momentum = 2 x 10 4 kg/m/s North

196. Momentum for car = 20,000 kg/m/s North

197. Copyright © 2010 Ryan P. Murphy

198. Momentum for car = 20,000 kg/m/s North –The truck has more momentum so the car gets pushed back. Copyright © 2010 Ryan P. Murphy

199. Momentum for car = 20,000 kg/m/s North –The truck has more momentum so the car gets pushed back. Copyright © 2010 Ryan P. Murphy