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Area: Parallelograms 10-1 PRE-ALGEBRA LESSON 10-1 It takes 126 ft of fence to enclose a field that is twice as long as it is wide. What is the area of.

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Presentation on theme: "Area: Parallelograms 10-1 PRE-ALGEBRA LESSON 10-1 It takes 126 ft of fence to enclose a field that is twice as long as it is wide. What is the area of."— Presentation transcript:

1 Area: Parallelograms 10-1 PRE-ALGEBRA LESSON 10-1 It takes 126 ft of fence to enclose a field that is twice as long as it is wide. What is the area of the field? 882 ft 2

2 Area: Parallelograms PRE-ALGEBRA LESSON 10-1 (For help, go to Lesson 3-4.) Use A = w and find the third value. 1.A = 54 in. 2, w = 6 in.2. = 35 m, w = 7 m 3.A = 25 cm 2, = 2.5 cm4. = 7.2 ft, w = 7.2 ft Check Skills You’ll Need 10-1

3 Area: Parallelograms PRE-ALGEBRA LESSON 10-1 Solutions 1.A = w2.A = w 54 = 6A = 35 7 = 9 in.A = 245 m 2 3.A = w4.A = w 25 = 2.5wA = 7.2 7.2 w = 10 cmA = 51.84 ft 2 10-1

4 Area: Parallelograms Find the area of the rectangle. PRE-ALGEBRA LESSON 10-1 Step 1Change the units so that they are the same. 150 cm = 1.5 mChange 150 centimeters to meters. Step 2Find the area. A = bhUse the formula for area of a rectangle. = (4)(1.5)Replace b and h with the dimensions 4 and 1.5. = 6Simplify. The area of the rectangle is 6 m 2. Quick Check 10-1

5 Area: Parallelograms Find the area of each parallelogram. PRE-ALGEBRA LESSON 10-1 a.b. A = bharea formula = (8)(2)Substitute. = 16Simplify. The area is 16 m 2.The area is 15 in. 2. A = bh = (2.5)(6) = 15 Quick Check 10-1

6 Area: Parallelograms PRE-ALGEBRA LESSON 10-1 Find each area. 1.rectangle ABFE 2.parallelogram ACFD 3.a rectangle with a base of 50 cm and a height of 5 cm 250 cm 2 40 cm 2 48 cm 2 10-1


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