Presentation is loading. Please wait.

Presentation is loading. Please wait.

Final Exam Review Thermodynamics Heat & Conservation of Energy Heat Transfer.

Similar presentations


Presentation on theme: "Final Exam Review Thermodynamics Heat & Conservation of Energy Heat Transfer."— Presentation transcript:

1

2 Final Exam Review Thermodynamics Heat & Conservation of Energy Heat Transfer

3 What is heat? Def: The amount of internal ENERGY (Q) an object’s molecules have. More heat = more energy

4 Comparing Heat Energy Heat energy is effected by two things: 1) Mass- 10kg of steel at 100 degrees has more energy than 5kg of steel at 100 degrees. 2) Temperature- 5 kg of water at 100 degrees has more energy than 5 kg of water at 50 degrees.

5 Changing heat energy Changing the temperature of an object will increase or decrease the heat energy. Formula: Q = mcΔT Heat Energy (J) = mass(kg) * specific heat(J/kg˚C)* Δ temp (°C)

6 Example The specific heat of aluminum is 900 J/kg°C. How much heat energy does it take to raise the temperature of a 1kg softball bat from 37°C to 40°C?

7 Example The specific heat of aluminum is 900 J/kg°C. How much heat energy does it take to raise the temperature of a 1kg softball bat from 37°C to 40°C? Givens: m= 1kg c= 900 J/kg°C ΔT= 40°C – 37°C = 3°C

8 Example The specific heat of aluminum is 900 J/kg°C. How much heat energy does it take to raise the temperature of a 1kg softball bat from 37°C to 40°C? Givens: m= 1kg c= 900 J/kg°C ΔT= 40°C – 37°C = 3°C Q = mc ΔT

9 Example The specific heat of aluminum is 900 J/kg°C. How much heat energy does it take to raise the temperature of a 1kg softball bat from 37°C to 40°C? Givens: m= 1kg c= 900 J/kg°C ΔT= 40°C – 37°C = 3°C Q = mc ΔT Q = (1kg)(900J/kg°C)(3°C) = 2700 J

10 Practice Complete the worksheet provided for classwork. ?


Download ppt "Final Exam Review Thermodynamics Heat & Conservation of Energy Heat Transfer."

Similar presentations


Ads by Google