Download presentation
Presentation is loading. Please wait.
Published byCleopatra Glenn Modified over 9 years ago
1
Energy Conservation and Transfer Chm 2.1.1
2
States of Matter Solid KMT –particles packed tightly together –high attraction –Lowest energy of all states –Volume: definite –Shape: definite –Density: High (incompressible) –Types: Crystalline and Amorphous
3
States of Matter Liquid KMT –particles are “fluid”, –less attraction –Higher energy than in solids –Volume: definite –Shape: not definite –Density: relatively high
4
States of Matter Gases KMT –particles are spread apart –very low or no attraction –Highest energy –Volume and Shape not definite –Density: very low –able to be compressed
5
States of Matter
6
Phase Changes of Matter Endothermic –Melting (liquefying) –Boiling –Vaporization (Evaporation) –Sublimation Exothermic –Freezing (solidifying) –Condensing –Deposition
7
Temperature Measures “speed” or Kinetic Energy of particles (T) Measured in ºC or Kelvin (K) K = ºC + 273 Heat measures energy absorbed or released (q) Measured in joules (J) or kilojoules (kJ)
8
Equilibrium in Changes of State Equilibrium: a dynamic condition in which two opposing changes occur at equal rates, at the same time in a closed system
10
Equilibrium Vaporization liquid + heat energy vapor liquid + heat energy vaporCondensation vapor liquid + heat energy At Equilibrium Liquid + Heat Energy ↔ Vapor
11
Vapor Pressure Vapor Pressure = vapor molecules at equilibrium exert pressure Effects of Temperature of Vapor Pressure –Increase Temperature = increases VP –Decrease Temperature = decrease VP –Boiling = when VP of liquid is = to the atmospheric pressure
12
Phase Diagram for H 2 O
13
Phase Diagram for CO 2
14
Heating Curves
15
Heat Calculations Specific heat: –The amount of energy needed to raise 1g of a substance 1°C or 1K –Cp = J/g°C or J/gK –Measured under conditions of constant pressure –All substances have their own specific heat –Cp = q/mΔT
16
Calculating Heat Calculating Heat from Cp –q = mCpΔT Ex: Calculate the amount of heat absorbed by a 6.0g sample of aluminum when the temperature is increased from 500°C to 550°C.
17
The heating curve above gives data for water when it is cooled. How much heat energy is released from 4.0g of water when it is cooled from 100° to 0°
18
Heat of Fusion The amount of energy required/released when melting/freezing 1g of water at 0°C Hf = 334 J/g q = mHf Ex: how much energy will be absorbed by a 3.0g ice cube at 0°C?
19
Heat of Vaporization The amount of energy absorbed or released when vaporizing/condensing 1g of water at 100°C Hv = 2,260 J/g q = mHv Example: How much energy is absorbed when 9.36 g of water is vaporized?
20
Law of Conservation of Energy In a closed system –Energy is cannot be created or destroyed only transferred. –heat lost in a system is gained by the surroundings –Heat gained in a system is lost by the surroundings –q lost = q gained
21
An ice cube while melting gained 25 J of energy. How much energy was lost by its surroundings? A hot piece of metal is put into a cup of water. What will happen to the metal? What will happen to the water? Copper was heated and placed in a cup of water at room temperature (25°C). The water’s temperature rose 30°C. How much energy did the copper loose?
Similar presentations
© 2025 SlidePlayer.com. Inc.
All rights reserved.