Download presentation
1
CHAPTER 5 PARTIAL DERIVATIVES
INTRODUCTION SMALL INCREMENTS & RATES OF CHANGE IMPLICIT FUNCTIONS CHAIN RULE JACOBIAN FUNCTION HESSIAN FUNCTION STATIONARY POINT
2
INTRODUCTION Consider the following functions where
are independent variables. If we differentiate f with respect variable , then we assume that as a single variable as constants
3
Notation If First order partial derivatives: Second order partial derivatives:
4
Example 1 Write down all partial derivatives of the following function
5
Example 1 Write down all partial derivatives of the following function Solution First order PD
6
Second order PD
7
Second order PD (mixed partial)
8
In example 1, we observed that This properties hold for all functions provided that certain smoothness properties are satisfies. The mixed partial derivative must be equal whenever f is continuous.
9
Example 2 Write down all partial derivatives of the following functions:
10
Solution 2
11
Solution 2
12
SMALL INCREMENTS & RATES OF CHANGE
Notation for small increment is Let then A small increment in z, is given by Where are small increments of the stated variables ii. Rate of change z wrt time, t is given by
13
Example 3 The measurements of closed rectangular box are length, x = 5m, width y = 3m, and height, z = 3.5m, with a possible error of in each measurement. What is the maximum possible error in the calculated value of the volume, V and the surface, S area of the box?
14
Solution 3 Volume of rectangular box: Possible error of the volume:
y z
15
Solution 3 Possible error of the volume:
16
Solution 3 Surface Area of rectangular box: Possible error of the volume:
y z
17
Solution 3 Possible error of the surface area:
18
Example 4 The radius r of a cylinder is increasing at the rate of 0
Example 4 The radius r of a cylinder is increasing at the rate of 0.2cms-1 while the height, h is increasing at 0.5cms-1. Determine the rate of change for its volume when r=8cm and h =12cm.
19
Solution 4 Volume of cylinder: Rate of change:
(1) (2)
20
Solution 4 From (1) Differentiate partially wrt t: Substitute in (2):
21
IMPLICIT FUNCTIONS Definition Let f be a function of two independent variables x and y, given by constant. To determine the derivative of this implicit function: Let Hence,
22
Example 5 Assume that y is a differentiable of x that satisfies the given function. Find using implicit differentiation.
23
Solution 5 Let Then, Therefore ,
24
THE CHAIN RULE Definition Let z be a function of two independent variables x and y, while x and y are functions of two independent variables u and v. The derivatives of z with respect to u and v as follows: Hence,
25
Example 6 Let , where and Find and
26
Solution 6
27
Solution 6 Therefore
28
JACOBIAN FUNCTION Definition Let be n number of functions of n variables
29
JACOBIAN FUNCTION Jacobian for this system of equations is given by: OR
30
Example 7 Given and , determine the Jacobian for the system of equation.
31
Solution 7 Given and , determine the Jacobian for the system of equation.
32
INVERSE FUNCTIONS FOR PARTIAL DERIVATIVES
Definition Let u and v be two functions of two independent variables x and y. . . Partial derivatives and are given by:
33
Example 8 Given and , Find and
34
Solution 8 Given and , Find and
35
Example 9 Let and Find and
36
HESSIAN FUNCTION Definition Let f be a function of n number of variables . Hessian of f is given by the following determinant:
37
HESSIAN FUNCTION Hessian of a function of 2 variables: Let f be a function of 2 independent variables x and y. Then the Hessian of f is given by:
38
HESSIAN FUNCTION Stationary Point Definition Given a function . The stationary point of occurs when and Properties of Stationary Point
39
HESSIAN FUNCTION Properties of Stationary Point
If H<0, then stationary point is a SADDLE POINT If H>0 MAXIMUM POINT if MINIMUM POINT if If H=0, then TEST FAILS or NO CONCLUSION
40
Example 10 Find and classify the stationary points of
41
Solution 10 Find stationary point(s):
42
Substitute (2) in (1) Stationary points:
43
Find the Hessian function:
44
Determine the properties of SP:
Point Hessian: Conclusion SP is a maximum point SP is a saddle point
Similar presentations
© 2025 SlidePlayer.com. Inc.
All rights reserved.