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3. 30N 42  50  10N 1. 20.1 22.3 38.6 46.0 TRANSLATIONAL: Need :45.9 up 16.3 right 45.9 16.3 48.7 N @ 70° ROTATIONAL: 10(7) = 70 CCW 20.1(5)= 101 CW 10(3.5)= 35 CCW 46(2)= 92 CW  NET = 88 Nm CW 48.7 N 70° Where to put it:  = F d 88 = 45.9 d Only the  part causes torque! 1.91 m = d You need CCW….so think if it should be 1.91 meters to left or right! Need : 88 Nm CCW

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5. 700 N 78  55  2. All angles of a triangle add to 180  47  55  800 T? CW  = CCW  sin55(800)(2.5)+sin55(700)(5) =sin47(T)(5) 1638 + 2867 = 3.657 T 1230 N = T

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7. 3. 30  50  65  Break the forces into components 11 19.1 7.71 9.19 18.1 8.45 TRANSLATIONAL:ROTATIONAL:Where to put it: Need : 16.3 down 2.94 left 16.6 N @ 80  2.94 16.3 11(2) = 22.0 CCW 9.19(.5)= 4.6 CW 18.1(2) = 36.2 CCW  NET = 53.6 Nm CCW Need: 53.6 Nm CW  = F d 53.6 = 16.3 d 3.29 m = d Only the  part causes torque! You need CW….so think if it should be 3.29 meters to left or right!

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9. 20. TATA TBTB 205 675  Put pivot pt on one of the forces you don’t know (either one) ROTATIONAL: CW = CCW 205(1.5) + 675(2) = T B (3) 307.5 + 1350 = 3T B 553 N = T B You could move pivot pt to other end to get T B..or use TRANS like I did TRANSLATIONAL: UP = DOWN T A + 553 = 205 + 675 T A = 327 N

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11. 21. 196 T 30° ROTATIONAL: CW = CCW 196 L = sin30 T L T = 392 N TRANSLATIONAL: Up & Down already cancel Need: cos30(392) to right 339 N to right

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13. 22. 2000 T 1200 Tension is a right angle 25  ROTATIONAL: CW = CCW sin25(2000)L + sin25(1200)(½ L) = T(¾ L) 845 + 254 =.75T 1465 N = T TRANSLATIONAL: 619 1327 Break tension into Components to look at forces UP, DOWN, LEFT, & RIGHT Need: 1327 right 2581 up 2000 + 1200 - 619 1327 2581 2902 N @ 63 