1. EXAMPLE 1 Find a normal probability SOLUTION The probability that a randomly selected x -value lies between – 2σ and is the shaded area under the normal curve shown. x x P ( – 2σ ≤ x ≤ )xx A normal distribution has mean x and standard deviation σ. For a randomly selected x -value from the distribution, find P(x – 2σ ≤ x ≤ x). = 0.135 + 0.34= 0.475

2. EXAMPLE 2 Interpret normally distribute data Health The blood cholesterol readings for a group of women are normally distributed with a mean of 172 mg/dl and a standard deviation of 14 mg/dl. a. About what percent of the women have readings between 158 and 186 ? Readings higher than 200 are considered undesirable. About what percent of the readings are undesirable? b.

3. EXAMPLE 2 Interpret normally distribute data SOLUTION a. The readings of 158 and 186 represent one standard deviation on either side of the mean, as shown below. So, 68% of the women have readings between 158 and 186.

4. EXAMPLE 2 Interpret normally distribute data b. A reading of 200 is two standard deviations to the right of the mean, as shown. So, the percent of readings that are undesirable is 2.35% + 0.15%, or 2.5%.

5. GUIDED PRACTICE for Examples 1 and 2 A normal distribution has mean and standard deviation σ. Find the indicated probability for a randomly selected x -value from the distribution. x 1.1. P ( ≤ )xx 0.5 ANSWER

6. GUIDED PRACTICE for Examples 1 and 2 2.2. P( > )xx 0.5 ANSWER

7. GUIDED PRACTICE for Examples 1 and 2 3.3. P( < < + 2σ )xxx 0.475 ANSWER

8. GUIDED PRACTICE for Examples 1 and 2 4.4. P( – σ < x < )xx 0.34 ANSWER

9. GUIDED PRACTICE for Examples 1 and 2 5.5. P (x ≤ – 3σ) x 0.0015 ANSWER

10. GUIDED PRACTICE for Examples 1 and 2 6.6. P (x > + σ) x 0.16 ANSWER

11. GUIDED PRACTICE for Examples 1 and 2 7.7. WHAT IF? In Example 2, what percent of the women have readings between 172 and 200 ? 47.5% ANSWER